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PLANE TRIGONOMETRY
AND NUMERICAL COMPUTATION
A SERIES OF MATHEMATICAL TEXTS
EDITED BY
EARLE RAYMOND HEDRICK
THE CALCULUS
By Ellery Williams Davis and William Charles
Brenke.
ANALYTIC GEOMETRY AND ALGEBRA
By Alexander Ziwet and Louis Allen Hopkins.
ELEMENTS OF ANALYTIC GEOMETRY
By Alexander Ziwet and Louis Allen Hopkins.
PLANE AND SPHERICAL TRIGONOMETRY WITH COM-
PLETE TABLES
By Alfred Monroe Kenyon and Louis Ingold.
PLANE AND SPHERICAL TRIGONOMETRY WITH BRIEF
TABLES
By Alfred Monroe Kenyon and Louis Ingold.
ELEMENTARY MATHEMATICAL ANALYSIS
By John Wesley Young and Frank Millett Morgan.
COLLEGE ALGEBRA
By Ernest Brown Skinner.
ELEMENTS OF PLANE TRIGONOMETRY WITH COMPLETE
TABLES
By Alfred Moore Kenyon and Louis Ingold.
ELEMENTS OF PLANE TRIGONOMETRY WITH BRIEF
TABLES
By Alfred Moore Kenyon and Louis Ingold.
THE MACMILLAN TABLES
Prepared under the direction of Earle Raymond Hedrick.
PLANE GEOMETRY
By Walter Burton Ford and Charles Ammerman.
PLANE AND SOLID GEOMETRY
By Walter Burton Ford and Charles Ammerman.
SOLID GEOMETRY
By Walter Burton Ford and Charles Ammerman.
CONSTRUCTIVE GEOMETRY
Prepared under the direction of Earle Raymond Hedrick.
JUNIOR HIGH SCHOOL MATHEMATICS
By William Ledley Vosburgh and Frederick William
Gentleman.
PLANE TRIGONOMETRY
AND NUMERICAL
COMPUTATION
BY
JOHN WESLEY YOUNG
PROFESSOR OF MATHEMATICS
DARTMOUTH COLLEGE
AND
FRANK MILLETT MORGAN
ASSISTANT PROFESSOR OF MATHEMATICS
DARTMOUTH COLLEGE
- Neto gorfe
THE MACMILLAN COMPANY
1919
All rights reserved
Copyright, 1919,
By the MACMILLAN COMPANY.
Set up and electrotyped. Published October, 1919.
NOV 12 1919
Nortoooti Press
J. S. Gushing Co. — Berwick & Smith Co.
Norwood, Mas3., U.S.A.
©C1.A535687
PREFACE
Ever since the publication of our Elementary Mathematical
Analysis (The Macmillan Co., 1917) we have been asked by
numerous teachers to pubhsh separately, as a textbook in plane
trigonometry, the material on trigonometry and logarithms of
the text mentioned.
The present textbook is the direct outcome of these requests.
Of course, such separate publication of material taken out of
the body of another book necessitated some changes and an in-
troductory chapter. As a matter of fact, however, we have
found it desirable to make a number of changes and additions
not required by the necessities of separate publication. As a
result fully half of the material has been entirely rewritten, with
the purpose of bringing the text abreast of the most recent
tendencies in the teaching of trigonometry.
There is an increasing demand for a brief text emphasizing the
numerical aspect of trigonometry and gi\Hing only so much of the
theory as is necessary for a thorough understanding of the
numerical applications. The material has .■ therefore been ar-
ranged in such a way that the first six chapters give the essen-
tials of a course in numerical trigonometry and logarithmic
computation. The remainder of the theory usually given in
the longer courses is contained in the last two chapters.
More emphasis than hitherto has been placed on the use of
tables. For this purpose a table of squares and square roots
has been added. Recent experience has emphasized the appli-
cations of trigonometry in navigation. ^Ye have accordingly
added some material in the text on navigation, have introduced
V
vi PREFACE
the haversine, and have added a four-place table of haversines
for the benefit of those teachers who feel that the use of the
haversine in the solution of triangles is desirable. This material
can, however, be readily omitted by any teacher who prefers
to do so.
J. W. Young,
F. M. Morgan.
Hanover, N.H.,
August, 1919.
CONTENTS
CHAPITER
I. Introductory Conceptions
II. The Right Triangle
III. Simple Trigonometric Relations
IV. Oblique Triangles .
V. Logarithms ....
VI. Logarithmic Computation
VII. Trigonometric Relations
VIII. Trigonometric Relations (continued)
Tables
Index ........
PAGES
1-10
11-31
32-39
40-49
50-60
61-74
75-87
88-103
106-119
121-122
vu
PLAKE TRIGO]N^OMETRY AND
JN^UMERICAL COMPUTATION
CHAPTEK I
INTRODUCTORY CONCEPTIONS
1. The Uses of Trigonometry. The word " trigonometry '^
is derived from two Greek words meaning " the measurement
of triangles.'' A triangle has six so-called elements (or parts) ;
viz., its three sides and its three angles. We know from our
study of geometry that, in general, if three elements of a tri-
angle (not all angles) are given, the triangle is completely
determined.* Hence, if three such determining elements of a
triangle are given, it should be possible to compute the remain-
ing elements. The methods by which this can be done, i.e.
methods for " solving a triangle,'' constitute one of the prin-
cipal objects of the study of trigonometry.
If two of the angles of a triangle are given, the third angle
can be found from the relation A -\- B -{- C = 180° (A, B, and
C representing the angles of the triangle) ; also, in a right tri-
angle, if two of the sides are kno^n, the third side can be
found from the relation a^ -\- h- = C' (a, b being the legs and c
the hypotenuse). But this is nearly the limit to which the
methods of elementary geometry will allow us to go in the
solution of a triangle.
Trigonometry! is the foundation of the art of surveying
* What exceptions are there to this statement ?
t Throughout this book we shaU confine ourselves to the subject of ** plane
trigonometry," which deals with rectilinear triangles in a plane. " Spherical
trigonometry" deals with similar problems regarding triangles on a sphere
whose sides are arcs of great circles.
B 1
PLANE TRIGOXO:\IETRY
[I, § 1
and of much of the art of navigation. It is, moreover, of
primary importance in practically every branch of pure and
applied mathematics. Many of the more elementary applica-
tions will be presented in later portions of this text.
2. The << Shadow Method." The ancient Greeks employed
the theory of similar triangles in the solution of a special type
of triangle problem which it is worth our while to examine
briefly, because it contains the germ of the theory of trigo-
nometry.
It is desired to find the height CA of a vertical tower stand-
ing on a level plain. It is observed
that at a certain time the tower casts a
shadow 42 ft. long. At the same time
a pole CA', 10 ft. long, held vertically
with one end on the ground casts a
shadow 7 ft. long. From these data
the height of the tower is readily com-
puted as follows : The right triangles
ABC 2ind A'B'C are similar since AB
= Z B\ (\Yhy ? ) Therefore we have
CA CA' 10
A
or
BC
B'C
CA
CA'
B'C
The tower is
then 60 ft.
high.
3.
A
«« Function "
of an
Angle
^(7 = ^X42 = 60.
From the point of view of
our future study the important thing to notice in the solution
CA CA'
of the preceding article is the fact that the ratios ,
^ ^ BC B'C
are equal, i.e. that the ratio of the side opposite the angle B to
the side adjacent to the angle is determined by the size of the angle,
and does not depend at all on any of the other elements of the
triangle, jDrovided only it is a right triangle.
I, § 3] INTRODUCTORY CONCEPTIONS 3
Definition. Whenever a quantity depends for its value on
a second quantity, the first is called a function of the second.
Thus in our example the ratio of the side opi)osite an angle
of a right triangle to the side adjacent is a quantity which
depends for its value only on the angle ; it is, therefore, called'
a function of the angle. This ratio is merely one of several
functions of an angle which we shall define in the next
chapter. By means of these functions the fundamental prob-
lem of trigonometry can be readily solved.
The particular function which we have discussed is called
the tangent of the angle. Explicitly defined for an acute angle
of a right triangle, we have
. 4. p 1 side opposite the ans^le
tangent of angle = ^ ^ r^ — ^—~•
side adjacent to the angle
If the angle £ in the preceding example were measured it
would be found to contain oo°. In any right triangle then
containing an angle of Bd"" we should find this ratio to be equal
to y^-, or 1.43. If the angle is changed, this ratio is changed,
but it is fixed for any given angle. If the angle is 45°, the
tangent is equal to 1, since in that case the triangle is
isosceles.
The word tangent is abbreviated " tan/'* Thus we have
already found tan 5o° = 1.43 and tan 45° = 1.00. Similarly
to every other acute angle corresponds a definite number,
which is the tangent of that angle. The values of the tan-
gents of angles have been tabulated. We shall have occasion
to use such tables extensively in the future.
If a, h, c are the sides of a right triangle ABC with right
angle at C and with the usual notation whereby the side a is
opposite the angle A and side b opposite the angle B, the defi-
nition of the tangent gives
tan^ = -.
a
PLANE TRIGONOMETRY
[I, §3
From this we get at once,
b = a tan B and a = -
tan B
These are our first trigonometric formulas. By means of
them and a table of tangents we can compute either leg of a
right triangle, if the other leg and an acute angle are given.
EXERCISES
1. What is meant by '' the elements of a triangle " ? by *' solving a
triangle" ?
2. A tree casts a shadow 20 ft. long, when a vertical yardstick with
one end on the ground casts a shadow of 2 ft. How high is the tree ?
3. A chimney is known to be 90 ft. high. How long is its shadow
when a 9-foot pole held vertically with one end on the ground casts a
shadow 5 ft. long ?
4. Give examples from your own experience of quantities which are
functions of other quantities.
5. Define the tangent of an acute angle of a right triangle. Why does
its value depend only on the size of the angle ?
6. In the adjacent figure think of the line BA as rotating about the
point B in the direction of the arrow, starting from
the position j5C (when the angle B is 0) and assum-
ing successively the positions BAi, BA2, BA^, ....
Show that the tangent of the angle B is veiy
small when B is veiy small, that tan B increases as
the angle increases, that tan B is less than 1 as
long as 5 is less than 45°, that tan 45° = 1, that
tan B is greater than 1 if the angle is greater than
45°, and that tan B increases without limit as B ap-
proaches 90°.
7. The following table gives the values of the tan-
gent for certain values of the angle :
angle
10°
20°
30°
40°
50°
60°
70°
tangent
0.176
0.364
0.577
0.839
1.19
1.73
2.75
I, § 4] INTRODUCTORY CONCEPTIONS 5
By means of this table tind the other leg of a right triangle ABC from
the elements given :
(a) B = 50^ a = 10 (d) B = 20°, b = IS (g) B = 60°, a = 37
(6) B = 70°, a = 16 (e) A = 30°, 6=5 (h) A z= 20°, a = 22
(c) B = 40°, 6 = 24 (/) ^ = 10°, b = Q2
8. From the data and the results of the preceding exercise find the
other acute angle and the hypotenuse of each of the right triangles.
4. Coordinates in a Plane. The student should already be
familiar from his study of algebra with the method of locating
points in a plane by means of coordinates. Since we shall
often have occasion to use such a method in the future, we will
recall it briefly at this point.
The method consists in referring the points in question to
two straight lines X'X and Y' T, at right angles to each other,
which are called the axes of
coordinates. X'X is usually
drawn horizontally and is
called the x-axis ; Y^ Y, which
is then vertical, is called the
y-axis.
The position of any point
P is completely determined
if its distance (measured in
terms of some convenient ^^^* ^
unit) and its direction from each of the axes is known. Thus
the position of P^ (Fig. 2) is known, if we know that it is 4
units to the right of the i/-axis and 2 units above the a;-axis. If
we agree to consider distance measured to the right or upwards
as positive, and therefore distance measured to the left or down-
ward as negative ; and if, furthermore, we represent distances
and directions measured parallel to the x-axis by x, and distances
and directions measured parallel to the ?/-axis by y, then the
position of Pi may be completely given by the specifications
x = -|-4, y =-\- 2\ or more briefly still by the symbol (4, 2).
Second Quadras
It
<
First Quadrant
Ms.
f 1
X> M^
1 M, X
n
Third Quadra
nt
yt^ourfh Quadrant
6 PLANE TRIGONOMETRY [I, § 4
Similarly, the point P2 in Fig. 2 is completely determined
by the symbol (-3, 5). Observe that in such a symbol the x of
the point is written first, the y second. The two numbers x
and y, determining the position of a point, are called the
coordinates of the point, the x being called the x- coordinate
or abscissa, the y being called the y-cobrdinate or ordinate
of the point. What are the coordinates of P3 and P^ in
Eig. 2?
The two axes of coordinates divide the plane into four regions
called quadrants, numbered as in Fig. 2. The quadrant in
which a point lies is completely determined by the signs of its
coordinates. Thus points in the first quadrant are character-
ized by coordinates ( + , +), those in the second by ( — , +),
those in the third by ( — , — ), and those in the fourth by (+, — ).
Square-ruled paper (so-called coordinate or cross section
paper) is used to advantage in " plotting '' {i.e. locating) points
by means of their coordinates.
5. Magnitude and Directed Quantities. In the last article
we introduced the use of positive and negative numbers, i.e.
the so-called signed numbers, while in the preceding articles,
where we were concerned with the sides and angles of triangles,
we dealt only with unsigned numbers. The latter represent
magnitude or size only (as a length of 20 ft.), while the former
represent both a magnitude and one of two opposite direc-
tions or senses (as a distance of 20 ft. to the left of a given
line). We are thus led to consider two kmds of quantities •
(1) magnitudes, and (2) directed quantities. Examples of the
former are : the length of the side of a triangle, the weight of
a barrel of flour, the duration of a period of time, etc. Ex-
amples of the latter are : the coordinates of a point, the tem-
perature (a certain number of degrees above or below zero),
the time at which a certain event occurred (a certain numbev
of hours before or after a given instant), etc.
I, § 6] INTRODUCTORY CONCEPTIONS 7
Geometrically, the (listinction between directed quantities
and mere magnitudes corresponds to the fact that, on the one
hand, we may think of the line segment AB as drawn from A to
B or from jB to ^ ; and, on the other hand, we
may choose to consider only the length of ' * *~~^ ' ^
such a segment, irrespective of its direction. '
Figure 3 exhibits the geometric representation
of 5, + 5, and — 5. A segment whose direc-
tion is definitely taken account of is called 3i~directed segment.
The magnitude of a directed quantity is called its absolute
value. Thus the absolute value of — 5 (and also of + 5) is 5.
Observe that the segments OM^, M^P^ (Fig. 2) representing
the coordinates of P^ are directed segments.
6. Directed and General Angles. In elementary geometry
an angle is usually defined as the figure formed by two half-
lines issuing from a point. However, it is often more serviceable
to think of an angle as being generated
by the rotation in a plane of a half-line
/ \ OP about the point as a pivot, start-
,-'''"" \ ing from the initial position OA and
^ ^ ending at the terminal position OB (Fig.
4). We then say that the line OP has
generated the angle AOB, Similarly, if OP rotates from the
initial position OB, to the terminal position OA, then the angle
BOA is said to be generated. Considerations similar to those
regarding directed line segments (§ 5) lead us to regard one of
the above directions of rotation as positive and the other as
negative. It is of course quite immaterial which one of the
two rotations we regard as positive, but
w^e shall assume, from now on, that
cotmterclockicise rotation is positive and
clockwise rotation is negative.
Still another extension of the notion Fig. 5
8
PLANE TRIGONOMETRY
[I, §6
of angle is desirable. In elementary geometry no angle greater
than 360° is considered and seldom one greater than 180°. But
from the definition of an angle just given, we see that the
revolving line OP may make any number of complete revolu-
tions before coming to rest, and thus the angle generated may
be of any magnitude. Angles generated in this way abound
in practice and are known as angles of rotation.^
When the rotation generating an angle is to be indicated, it is
customary to mark the angle by means of an arrow starting at
the initial line and ending at the terminal line. Unless some
such device is used, confusion is liable to result. In Fig. 6
1110
Fig.
angles of 30°, 390°, 750°, 1110°, are drawn. If the angles were
not marked one might take them all to be angles of 30°.
7. MeaSlirement of Angles. For the present, angles will be
measured as in geometry, the degree (°) being the unit of measure. A
complete revolution is 360°. The other units in this system are the
minute ('), of which 60 make a degree, and the second ('^), of which 60
make a minute. This system of units is of great antiquity, having been
used by the Babylonians. The considerations of the previous article then
make it clear that any real number, positive or negative, may represent an
angle, the absolute value of the number representing the magnitude of
the angle, the sign representing the direction of rotation.
X
p'
Fig. 7
^k;
Consider the angle XOP = 6^ whose vertex coincides with the origin
of a system of rectangular coordinates, and whose initial line OX coin-
*For example, the minute hand of a clock describes an angle of —180°
n 30 minutes, an angle of — 540° in 90 minutes, and an angle of — 720° in 120
ninutes.
I, § 8] INTRODUCTORY CONCEPTIONS 9
cides with the positive half of the ic-axis (Fig. 7). The angle $ is then
said to be in the first, second, third, or fourth quadrant, according as its
terminal line OP is in the first, second, third, or fourth quadrant.
8. Addition and Subtraction of Directed Angles. The
meaning to be attached to the sum of two directed angles is analogous to
that for the sum of two directed
line segments. Let a and b be /^ /^
two half -lines issuing from the ^ ^^
same point O and let (a6) repre-
sent an angle obtained by rotat-
ing a half -line from the position
a to the position 6. Then if we
have two angles (a6) and (6c) with the same vertex O, the sum (a6) -|- (6c)
of the angles is the angle represented by the rotation of a half -line from
the position a to the position 6 and then rotating from the position 6 to the
position c. But these two rotations are together equivalent to a single rota-
tion from a to c, no matter what the relative positions of a, 6, c may have
been. Hence, we have for any three half-Unes a, 6, c issuing from a point 0,
(1) {ah)\{hc) = {^ac), (a6) + (ba)=: 0, (a6) = (c&)-(ca).
It must be noted, however, that the equality sign here means " equal,
except possibly for multiples of 260^.^^ The proof of the last relation is
left as an exercise.
EXERCISES
1. On square-ruled paper draw two axes of reference and then plot the
.following points: (2, 3), (- 4, 2), (- 7, - 1), (0, - 3), (2, - 5), (5, 0).
2. What are the coordinates of the origin ?
3. Where are all the points for which x = 2? x=— 3? ?/=— 1?
2/ = 4? x = 0?
4. Show that any point P on the ^/-axis has coordinates of the form
(0, y). What is the form of the coordinates of any point on the x-axis ?
5. A right triangle has the vertex of one acute angle at the origin and
one leg along the x-axis. The vertex of the other acute angle is at
(7, 10). What is the tangent of the angle at O ?
6. What angle does the minute hand of a clock describe in 2 hours
and 30 minutes ? in 4 hours and 20 minutes ?
7. Suppose that the dial of a clock is transparent so that it may be
read from both sides. Two persons stationed at opposite sides of the dial
observe the motion of the minute hand. In what respect will the angles
described by the minute hand as seen by the two persons differ?
10 PLANE TRIGONOIviETRY [I, § 8
8. In what quadrants are the following angles : ST"" ? 135^ ? — 325° ?
540^? 1500°? -270°?
9. In what quadrant is ^/2 if ^ is a positive angle less than 360° and in
the second quadrant ? third quadrant ? fourth quadrant ?
10. By means of a protractor construct 27° + 85° +(— 30°) -f 20° +
(-45°).
11. By means of a protractor construct — 130° + 56° — 24°.
CHAPTER II
THE RIGHT TRIANGLE
9. Introduction. At the beginning of the preceding chap-
ter we described the fundamental problem of trigonometry to
be the " solution of the triangle/' i.e. the problem of com-
puting the unknown elements of a triangle when three of the
elements (not all angles) are given. This problem can be
solved by finding relations between the sides and angles of a
triangle by means of which it is possible to express the un-
known elements in terms of the known elements. In order
to establish such relations, it has been found desirable to
define certain functions of an angle. One such function — the
tangent — was introduced in § 3 by way of preliminary illus-
tration.
In the present chapter, we shall give a new definition of the
tangent of an angle and also define two other equally impor-
tant functions — the sine and the cosine. It should be noted
that the definition given for the tangent in § 3 applies only to
an acute angle of a right triangle. For the purposes of a sys-
tematic study of trigonometry we require a more general defini-
tion, which will apply to any angle, positive or negative, and
of any magnitude. Such definitions are given in the next
article, in which the notion of a system of coordinates plays a
fundamental role, the notion of a triangle not being introduced
at all. After considering some of the consequences of our
definitions in §§ 11-13, we consider the way in which these
definitions enable us to express relations between the sides
and angles of a right triangle. These results are then imme-
diately applied to the solution of numerical problems by means
of tables and to applications in surveying and navigation.
11
12
PLANE TRIGONOMETRY
[11, § 10
10. The Sine, Cosine, and Tangent of an Angle. We
may now define three of the functions referred to in § 3. To
this end let d = XOP (Fig. 9) be any directed angle, and let
JcyL^
us establish a system of rectangular coordinates in the plane
of the angle such that the initial side OX of the angle is the
positive half of the a^axis, the vertex being at the origin and
the 2/-axis being in the usual position with respect to the
a;-axis. Let the units on the two axes be equal. Finally, let
P be any point other than on the terminal side of the angle
6, and let its coordinates be (a?, y). The directed segment
OP = r is called the distance of P and is always chosen posi-
tive. The coordinates x and y are positive or negative accord-
ing to the conventions previously adopted. We then define
ordinate of P y
The sine of Q =
The cosine of Q =
The tangent of Q =
distance of P "
abscissa of P
distance of P"
ordinate of P
X
y
-, . p T^=-j provided x^ 0.^
abscissa oi P x
These functions are usually written in the abbreviated forms
sin 6, cos 9, tan 6, respectively ; but they are read as " sine 0,'^
" cosine 6,'' " tangent ^." It is very important to notice that
the values of these functions are independent of the position
of the point P on the terminal line, For let P (x\ y') be any
other point on this line. Then from the similar right triangles
ocyrf and x^y'r' it follows that the ratio of any two sides
of the triangle xyr is equal in magnitude and sign to the
* Prove that x and y cannot be zero simultaneously.
t Triangle xyz means the triangle whose sides are x, y^ z.
II, § 11]
THE RIGHT TRIANGLE
13
ratio of the corresponding sides of the triangle x'y'r'. There-
fore the values of the functions just defined depend merely
on the angle 6. They are one-valued functions of 6 and are
called trigonometric functions.
Since the values of these functions are defined as the ratios
of two directed segments, they are abstract numbers. They
may be either positive, negative, or zero. Remembering that r
is always positive, we may readily verify that the signs of the
three functions are given by the following table.
Quadrant
Sine . .
Cosine .
Tangent
1
+
+
+
2
+
+
4
+
11. Values of the Functions for 45°, 135°, 225°, 315°. In
each of these cases the triangle ocyr is isosceles. AYhy?
Since the trigonometric functions are independent of the
position of the point P on the terminal line, we may choose
the legs of the right triangle xyr to be of length unity, which
t^--
Fig. 10
gives the distance OP as V2. Figure 10 shows the four angles
with all lengths and directions marked. Therefore,
sin 4o = — -,
V2
sin 135° :
V2'
sin 225° = --^,
V2
sin 315° = -—,
V2
cos 45° = -
V2'
cos 315° =
vr
tan 45° = 1,
cos 135° = --!-, tan 135° = - 1,
V2
cos 225° = - — , tan 225° = 1,
V2'
tan 315° = - 1.
14
PLANE TRIGONOMETRY
[II, § 12
12. Values of the Functions for 30°, 150°, 210°, 330°. Erom
geometry we know that if one angle of a right triangle con-
tains 30°, then the hypotenuse is double the shorter leg,
which is opposite the 30° angle. Hence if we choose the
shorter leg (ordinate) as 1, the hypotenuse (distance) is 2,
Ml it<^^
>/7 -^
S30
fSf'
Fig. 11
and the other leg (abscissa) is V3. Figure 11 shows angles of
30°, 150°, 210°, 330° with all lengths and directions marked.
Hence we have
sin 30° = :",
2'
sin 150° = -
sin 210° = --,
2'-
sin 330° = - ±,
2'
cos 30° =
cos 150° =
cos 210° =
cos 330° =
V3
2 '
V3
2 '
V3
V3
tan 30° =
V3
tan 150°=--
V3
-^-^, tan 210° = -
2 '
V3
tan 330° =
V3
13. Values of the Functions for 60°, 120°, 240°, 300°. It is
left as an exercise to construct these angles and to prove that
sin 60° = ^,
2 '
sin 120°=^,
cos 60°=-,
2'
cos 120° = ■
"2'
tan 60°=V3,
tanl20° = -V3,
sin 240° = - ^, cos 240° = - -, tan 240° = V3,
2 2
sin 300° = -
V5
cos 300°=-,
2'
tan 300° = - V3.
II, § 14]
THE RIGHT TRIANGLE
15
14. Sides and Angles of a Right Triangle. Evidently any
right triangle ABC can be so placed in a system of coordi-
nates that the vertex of either acute
angle coincides with the origin
and that the adjacent leg lies along
the positive end OX of the ic-axis
(Fig. 12). The follov/ing relations
then follow at once from the defini-
tions of the sine, cosine, and tangent
of § 10.
In any right trimigle, the trigonometric functions of either acute
angle are given by the ratios :
the sine •
the cosine =
side opposite the angle
hypotenuse '
side adjacent to the angle
the tangent =
hypotenuse
side opposite the angle
side adjacent to the angle '
These relations are fundamental in all that follows. They
should be firmly fixed in mind in such a way that they can be
readily applied to any right triangle in what-
ever position it may happen to be (for example
as in Fig. 13). The student should be able to
reproduce any of the following relations with-
out hesitation whenever called for. They
should not be memorized, but should be read
from an actual or imagined figure :
Fig. 13
sin J. = -
sin J5 = - ,
c
cos A = -,
c
cos 5 = -
tan ^ = - ,
Also the known relation :
tan B = ~,
a
c2 = a2 + 62,
16
PLANE TRIGONOMETRY
[II, § 14
If any two elements (other than the right angle) of a right
triangle are given, we can then find a relation connecting these
two elements with any unknown element, from which relation
the unknown element can be computed.
15. Applications. The angle which a line from the eye to
an object makes with a horizontal line in the same vertical
plane is called an angle of elevation or an angle of depression,
Fig. U
Horizontal
according as the object is above or below the eye of the ob-
server (Fig. 14). Such angles occur in many examples.
Example 1. A man wishing to know the distance between two points
A and B on opposite sides of a pond locates a point C on the land (Fig.
15) such that J.C = 200 rd., angle C = 30^ and angle B = 90°. Fmd the
distance AB.
AB _
AG
AB = AC 'Sin G
= 200 . sin 30°
= 200 . 1
Solution :
- = sin G.
(Why ?)
100 rd.
Fig. 15
Example 2. Two men stationed at points A and G 800 yd. apart and
in the same vertical plane with a balloon J5, observe simultaneously the
angles of elevation of the balloon to be 30° and 45° respectively. Find the
height of the balloon.
Solution : Denote the height of the balloon DB by y, and let DG = x;
then AD = 800 - x.
Fig. 16
II, § 15J THE RIGHT TRIANGLE 17
Since tan 45^ = 1, we have 1
X
1 _ y
and since tan 30^ = 1/^'^^ ^^'^ \vii\Q — ^^ _ *
Therefore x = y and 800 — x = ?/ VS.
'Solving these equations for y, we have y = = 292.8 yd.
V3 + 1
EXERCISES
1. In what quadrants is the sine positive ? cosine negative ? tangent
positive ? cosine positive? tangent negative ? sine negative ?
2. In w^hat quadrant does an angle lie if
"(a) its sine is positive and its cosine is negative ?
(6) its tangent is negative and its cosine is positive?
(c) its sine is negative and its cosine is positive ?
(d) its cosine is positive and its tangent is positive ?
3. T\Tiich of the following is the greater and wiiy : sin 49° or cos 49° ?
sin 35° or cos 35° ?
4. If ^ is situated between 0° and 360°, how many degrees are there in
e if tan ^ = 1 ? Answer the similar question for sin ^ = i ; tan d = —\.
5. Does sin 60° = 2 . sin 30° ? Does tan 60° = 2 • tan 30° ? What
can you say about the truth of the equality sin 2 ^ = 2 sin ^ ?
6. The Washington Monument is 555 ft. high. At a certain place in
the plane of its base, the angle of elevation of the top is 60°. How far is
that place from the foot and from the top of the tower ?
7. A boy whose eyes are 5 ft. from the ground stands 200 ft. from a
flagstaff. From his eyes, the angle of elevation of the top is 30°. How
high is the flagstaff ?
8. A tree 38 ft. high casts a shadow 38 ft. long. What is the angle
of elevation of the top of the tree as seen from the end of the shadow ?
How far is it from the end of the shadow to the top of the tree ?
9. From the top of a tower 100 ft. high, the angle of depression of
two stones, which are in a direction due east and in the plane of the base
are 45° and 30° respectively. How far apart are the stones ?
.4718. 100(V3 - 1)= 73.2 ft.
c
18
PLANE TRIGONOMETRY
[II, § 15
10. Find the area of the isosceles triangle in which the equal sides 10
inches in length include an angle of 120^. Ans. 25 V3 = 43.3 sq. in.
11. Is the formula sin 2 ^ = 2 sin 6 cos $ true when 6 = 30° ? 60° ?
120° ?
12. From a figure prove that sin 117^ = cos 27°.
13. Determine whether each of the following formulas is true when
e = 30°, 60°, 150°, 210° :
1 + tan2 e =
1 + - '
1
cos^ 6 '
1
tan^(9 sin^^'
sin2(9 -f cos- (9 = 1.
14. Let Pi(Xi, ?/i) and P2(X2, ?/2) he any two points the distance be-
tween which is r (the units on the axes being equal) . If ^ is the angle
that the hne P1P2 makes with the x-axis, prove that
^2 -Xi ^ y ^-Vi ^ 2 r.
cos d sin d
16. Computation of the Value
Function from that of Another.
of One Trigonometric
J{1
Fig. 17
Example 1. • Given that sin ^ = |, find the
values of the other functions.
Since sin is positive, it follows that d is
an angle in the first or in the second quad-
rant. Moreover, since the value of the sine
is I, then y = Z - k and r = 5 • ^*, where k is
any positive constant different from zero. (Why ?) It is, of course,
immaterial what positive value we assign to A*, so we shall assign the
value 1. We know, however, that the abscissa, ordinate, and distance
are connected by the relation x^ + 7/2 = r^, and hence it follows that
X = ± 4. Figure 17 is then self-explanatory. Hence we have, for the first
quadrant, sin ^ = |, cos ^ = |, and tan ^ = f ; for the second quadrant,
sin ^ = f , cos ^ = — I, tan d = — I.
Example 2. Given that sin^r=y\ and that tan ^
is negative, find the other trigonometric functions of
the angle 6.
Since sin 6 is positive and tan 6 is negative, 6 must
be in the second quadrant. We can, therefore, con-
struct the angle (Fig. 18), and we obtain sin ^ = y^j ,
cos ^ =— i|, tan e :
_5_
12*
Fig. 18
II, § 17]
THE RIGHT TRIANGLE
19
17. Computation for Any Angle. Tables. The values of
the trigonometric functions of any angle may be computed by
the graphic method. For
example, let us find the
trigonometric functions of
35°. We tirst construct
on square-ruled paper,
by means of a protractor,
an angle of 35° and choose
a point P on the ter-
minal line so that OP
shall equal 100 units.
Then from the figure we
find that OM=z 82 units
and MP = 57 units.
Therefore
30 iO 50 60 70 80 90 100
Fig. 19
sin 35° = i¥o = ^-^^^ cos 35° = -f-^-^ = 0.82, tan 35° = fj = 0.70.
The tangent may be found more readily if we start by tak-
ing OA = 100 units and then measure AB. In this case,
AB = 70 units and hence tan 35^ = j^-^ = 0.70.
It is at once evident that the graphic method, although
simple, gives only an approximate result. However, the values
of these functions have been computed accurately by methods
beyond the scope of this book. The results have been put in
tabular form and are known as tables of natural trigonometric
functions. Such tables and how to use them will be discussed
in the next article.
Figure 20 makes it possible to read off the sine, cosine, or
tangent of any angle between 0° and 90° with a fair degree of
accuracy. The figure is self-explanatory. In reading off
values of the tangent use the vertical line through 100 for angles
up to 55°, and the line through 10 for angles greater than 55°.
Its use is illustrated in some of the following exercises.
20
PLANE TRIGONOMETRY [II, § 17
iO 20 30 iO 50 60 70 SO 90 100
Fig. 20. — Graphical Table of Trigonometric Functions
II, § 18] THE RIGHT TRIANGLE 21
EXERCISES
Find the other trigonometric functions of the angled when
1. tan e = -S. 3. cos (9 = ^f 5. sin (9 = J.
2. sin (9 = - |. 4. tan ^ = f . 6i cos ^ = — -J.
7. sin 6 = ^ and cos d is negative.
8. tan = 2 and sin 6 is negative.
9. sin ^ = — i and tan 6 is positive.
10. cos d = i and tan 6 is negative.
11. Can 0.6 and 0.8 be the sine and cosine, respectively, of one and
the same angle ? Can 0.5 and 0.9 ? Ans. Yes ; no.
12. Is there an angle whose sine is 2 ? Explain.
13. Determine graphically the functions of 20^, 38^ 70°, 110^.
14. From Fig. 20, find values of the following :
sin 10°, cos 50°, tan 40°, sin 80°, tan 70°, cos 32°, tan 14°, sin 14°.
15. A tower stands on the shore of a river 200 ft. wide. The angle of
elevation of the top of the tower from the point on the other shore exactly
opposite to the tower is such that its sine is |. Find the height of the
tower.
16. From a ship's masthead 160 feet above the water the angle of de-
pression of a boat is such that the tangent of this angle is ^^2* Find the
distance from the boat to the ship. Ans. 640 yards.
18. Use of Tables of Trigonometric Functions. Examina-
tion of the tables of ^' Four Place Trigonometric Functions ''
(p. 112) shows columns headed '^ Degrees/' " Sine/' " Tangent/'
" Cosine/' and under each of the last three named a column
headed " Value " (none of the other columns concern us at pres-
ent). Two problems regarding the use of these tables now
present themselves.
1. To find the value of a function when the angle is given,
(a) Find the value of sin 15° 20'. In the column headed
" Degrees " locate the line corresponding to 15° 20' (p. 113) ; on
the same line in the " value " column for the " Sine/' we read
the result : sin 15^ 20' = 0.2644. On the same line, by using
the proper column, we find tan 15° 20' = 0.2742, and cos 15° 20'
= 0.9644.
22 PLANE TRIGONOMETRY [II, § 18
(b) Find the value of tan 57° 50'. The entries in the
column marked " Degrees " at the top only go as far as 45°
(p. 116). But the columns marked " Degrees '' at the bottom
contain entries beginning with 46° (p. 116) and running back-
wards to 90° (p. 112). In using these entries we must use the
designations at the bottom of the columns. Thus on the line
corresponding to 57° 50' (p. 115) we find the desired value :
tan 57° 50' = 1.5900. Also sin 57° 50' = 0.8465, and cos 57°
50' = 0.5324.
(c) Find the value of sin 34° 13'. This value lies between
the values of sin 34° 10' and 34° 20'. We find for the latter
sin 34° 10' = 0.5616
sin 34° 20' = 0.5640
Difference for 10' = 0.0024
Assuming that the change in the value of the function
throughout this small interval is proportional to the change in
the value of the angle, we conclude that the change for 1' in the
angle would be 0.00024. For 3', the change in the value of the
function would then be 0.00072. Neglecting the 2 in the last
place (since we only use four places and the 2 is less than 5),
we find sin 34° 13' = 0.5616 + 0.0007 = 0.5623. This process is
called interpolation. With a little practice all the work in-
volved can and should be done mentally ; Le. after locating the
place in the table (and marking it with a finger), we observe
that the " tabular difference '' is '^ 24 '' ; we calculate mentally
that .3 of 24 is 7.2, and then add 7 to 5616 as we write down
the desired value 0.5623.
Similarly we find tan 34° 13' = 0.6800 (the correction to be
added is in this case 12.9 which is " rounded off '' to 13) and
cos 34° 13' = 0.8269. (Observe that in this case the correction
must be subtracted. Why ?)
2. To find the angle ivhen a value of a function is given.
Here we proceed in the opposite direction. Given sin A =
II, § IS] THE RIGHT TRIANGLE 23
0.3289 ; find A. An examination of tlie sine column shows
that the given value lies between sin 19° 10' (= 0.3283) and
sin 19° 20'(= 0.3311). We note the tabular difference to be 28.
The correction to be applied to 19^ 10' is then ^\ of 10' = f f '
= i^^' = 2.1'. Hence A = 19° 12.1'. (With a four place table
do not carry your interpolation farther than the nearest tenth
of a minute.) (See § 20.)
EXERCISES
1. For practice in the use of tables, verify the following :
(a) sin 18° 20' = 0.3145 (d) sin 27M-1' =0.4576 (6^) sin 62° 24M = 0.886 2
(6) cos 37'^ 30' =0.7934 (e) cos 34° 11' =0.8272 (/i) cos 59° 46' .2 =0.5034
(c) tan 75° 50' = 3.9617 (/) tan 68° 21' = 2.5173 (i) tan 14° 55'.6 =0.2665
Assume first that the angles are given and verify the values of the
functions. Then assume the values of the functions to be given and
verify the angles.
2. A certain railroad rises 6 inches for every 10 feet of track. What
angle does the track make with the horizontal ?
3. On opposite shores of a lake are two flagstaff s A and B. Per-
pendicular to the line AB and along one shore, a line BC = 1200 ft. is
measiu-ed. The angle ACB is observed to be 40° 20'. Find the distance
between the two flagstaffs.
4. The angle of ascent of a road is 8°. If a man walks a mile up the
road, how many feet has he risen ?
5. How far from the foot of a tower 150 feet high must an observer,
6 ft. high, stand so that the angle of elevation of its top may be 23°. 5 ?
6. From the top of a tower the angle of depression of a stone in the
plane of the base is 40° 20' . What is the angle of depression of the stone
from a point halfway down the tower?
7. The altitude of an isosceles triangle is 24 feet and each of the equal
angles contains 40° 20'. Find the lengths of the sides and area of the
triangle.
8. A flagstaff 21 feet high stands on the top of a cliff. From a point
on the level with the base of the cliff, the angles of elevation of the top
and bottom of the flagstaff are observed. Denoting these angles by u
and /3 respectively, find the height of the cUff in case sin a = -/y and
cos/3 = ^f. Ans, 75 feet.
24 PLANE TRIGONOMETRY [II, § 18
9. A man wishes to find the height of a tower CB which stands on a
horizontal plane. From a point A on this plane he finds the angle of ele-
•vation of the top to be such that sin CAB = |. From a point A' which
is on the line AG and 100 feet nearer the tower, he finds the angle of
elevation of the top to be such that tan CA'B = J. Find the height of
tiie tower.
10. Find the radius of the inscribed and circumscribed circle of a regu-
lar pentagon whose side is 14 feet.
11. If a chord of a circle is two thirds of the radius, how large an
angle at the center does the chord subtend ?
19. Computation with Approximate Data. Significant
Figures. The numerical applications of trigonometry (in sur-
veying, navigation, engineering, etc.) are concerned with com-
puting the values of certain unknown quantities (distances,
angles, etc.) from known data which are secured by measure-
ment. Now, any direct measurement is necessarily an approxi-
mation. A measurement may be made with greater or less
accuracy according to the needs of the problem in hand — but
it can never be absolutely exact. Thus, the information on a
signpost that a certain village is 6 miles distant merely
means that the distance is 6 miles to the nearest mile — i.e. that
the distance is between 5^ and 6^ miles. Measurements in a
physical or engineering laboratory need sometimes to be made to
the nearest one thousandth of an inch. For example the bore
of an engine cylinder may be measured to be 3.496 in., which
means that the bore is between 3.4955 in. and 3.4965 in.
A simple convention makes it possible to recognize at a
glance the degree of accuracy implied by a number represent-
ing an approximate measure (either direct or computed). This
convention consists simply in the agreement to write no more
figures than the accuracy warrants. Thus in arithmetic 6 and
6.0 and 6.00 all mean the same thing. This is not so, when
these numbers are used to express the result of measurement
or the result of computation from approximate data. Thus 6
means that the result is accurate to the nearest unit, 6.0 that
II, § 20] THE RIGHT TRIANGLE 25
it is accurate to the nearest tenth of a unit, 6.00 to the nearest
hundredth of a unit.
These considerations have an important bearing on practical
computation. If the side of a square is measured and found
to be 3.6 in. and the length of the diagonal is cbmputed by
the formula : diagonal = side x V2, it would be wrong to write
= 3.6 X V2 = 3.6 X 1.4142 = 5.09112 in. The correct result
is 5.1 in. For the computed value of the diagonal cannot be
more accurate than the measured value of the side. The result
5.09112 must therefore be " rounded off ^' to two significant
figures, which gives 5.1. As a matter of fact for the purpose
of this problem V2 = 1.4142 should be rounded before multi-
plication to \/2 = 1.4 ; thereby reducing the amount of labor
necessary.
A number is '' rounded off,*' by dropping one or more digits
at the right and, if the last digit dropped is 5^, 6, 7, 8, or 9
increasing the preceding digit by 1.^ Thus the successive
approximations to tt obtained by rounding of 3.14159 ••• are
3.1416, 3.142, 3.14, 3.1, 3.
20. The Number of Significant Figures of a number (in the
decimal notation) may now be defined as the total number of
digits in the number, except that if the number has no digits
to the right of the decimal point, any zeros occurring between
the decimal point and the first digit different from zero are
not counted as significant. Thus, 34.06 and 3,406,000 are both
numbers of four significant figures : while 3,406,000.0 is a
number of eight significant figures.!
* In roundino: off a 5 computers round off to an even digit. Thus .1.415
would be rounded to 1.42, whereas 1.445 would be rounded to 1.44. If this
rule is used consistently the errors made will tend to compensate each other.
t Confusion will arise in only one case. For example, if 3999.7 were
rounded by droppinoj the 7 we should write it as 4000 which according to the
above definition would have only 1 significant figure, whereas we know from
the way it was obtained that all four figures are significant. In such a case
we may underscore the zeros to indicate they are significant or use some
other device.
26 PLANE TRIGONOMETRY [II, § 20
In any computation involving multiplication or division the
number of significant figures is generally used as a measure of
the accuracy of the data. A computed result should not in
general contain more significant figures than the least accurate
of the data. But computers generally retain one additional
figure during the computation and then properly round off the
final result. Even then the last digit may be inaccurate — but
that is unavoidable.
The following general rules will be of use in determining
the degree of accuracy to be expected and in avoiding useless
labor :
1. Distances expressed to two significant figures call for
angles expressed to the nearest 30' and vice versa.
2. Distances expressed to three significant figures call for
angles expressed to the nearest 5', and vice versa,
3. Distances expressed to four significant figures call for
angles expressed to the nearest minute, and vice versa.
4. Distances expressed to five significant figures call for
angles expressed to the nearest tenth of a minute, and vice
versa.
In working numerical problems the student should use every
safeguard to avoid errors. Neatness and systematic arrange-
ment of the work are important in this connection. All work
should be checked in one or more of the following ways.
1. Gross errors may be detected by habitually asking oneself :
Is this result reasonable or sensible ? 2. A figure drawn to
scale makes it possible to measure the unknown parts and to
compare the results of such measurements with the computed
results. 3. An accurate check can often be secured with com-
paratively little additional labor by computing one of the
quantities from two different formulas or by verifying a
known relation. For example, if the legs a, 6 of a right tri-
angle have been computed by the formulas a = c sin ^ and
6 = c cos A, we may check by verifying the relation a^ + 6^ = c^.
n, § 21]
THE RIGHT TRIANGLE
27
Example. A stniii^ht road is to be built from a point A to a point Ji
which is 5.02 miles east and 8.27 miles north of
A. What will be the direction of the road and
its length ?
T7 1 * I 6.92 , „ 8.27
Formulas : tan A = ; AB =
8 27 cos A
Therefore tan A = 0.716 and A = 35^ 35',
cos A = 0.813 AB = 10.17.*
Check by a2 + 62 = ^2.
From a table of squares (p. 107, see § 21)
(5.92)2= 35.05
(8.27)2 = 68.39 (10.17)2 = 103.4.
103.4
21. Use of Table of Squares. Square Roots. The table
of squares of numbers (p. 106) may be used to facilitate com-
putation. In the example of the last article, we required the
square of 5.92. We find 5.9 on p. 107 in the left-hand column
and find the third digit 2 at the head of a certain column. At
the intersection of the line and column thus determined we
find the desired result (5.92)2 ^ 35,95, The square of 8.27 is
found similarly at the intersection of the line corresponding
to 8.2 and the column headed 7. To find (10.17)^, we find the
line corresponding to 1.0 (the first two digits, neglecting the
decimal point) and find (1.01)^ = 1.020 and (1.02)2 = 1.040.
By interpolating, as explained in § 18, we find (1.017)2 = 1.034.
Now shifting the decimal point one place in the "number"
requires a corresponding shift of two places in the square.
Hence, (10.17)2 = 103.4.
The table can also be used to find the square root of a num-
ber. Thus to find V2 we find, on working backwards in this
table, that 2 lies between 1.988 [=(1.41)^] and 2.016 [ = (1.42)2].
By interpolation we then find V2 = 1.414, correct to four
significant places. [Tabular difference = 28 ; correction = -^^
= 4 in the fourth place.]
♦The retention of four significant figures in AB is justified because the
number is so small at the left.
28 PLANE TRIGONOMETRY [II, § 21
EXERCISES
1. From an observing station 357 ft. above the water, the angle of
depression of a ship is 2° 15^ Elnd the horizontal distance to the ship in
yards.
2. A projectile falls in a straight line making an angle of 25° with the
horizontal. AYill it strike the top of a tree 24 meters high which is 72 meters
from the point where the projectile would strike the ground ?
3. At a point 372 ft. from the foot of a cliff surmounted by an observa-
tion tower the angle of elevation of the top of the tower is 51° 25', and of
the foot of the tower 31° 55'. Find the height of the cliff and of the
tower.
4. How far from the foot of a flagpole 130 ft. high must an observer
stand so that the angle of elevation of the top of the pole will be 25° ?
5. GA is a horizontal line, T is a point vertically above A;B?i point
A C
vertically below A. The angle BGA in minutes is Find Z BGT
4000
in degrees and minutes, given GA = 10,340 meters , AT = 416.4 meters.
6. It is desired to find the height of a wireless tower situated on the
top of a hill. The angle subtended by the tower at a point 250 ft. below
the base of the tower and at a distance measured horizontally of 2830 ft.
from it is found to be 2° 42'. Find the height of the tower.
7. From a tower 428.3 ft. high the angles of depression of two objects
situated in the same horizontal line with the base of the tower and on the
same side are 30° 22' and 47° 37'. Find the distance between them.
8. The summit of a mountain known to be 13.260 ft. high is seen at
an angle of elevation of 27° 12' from a camp located at an altitude of
6359 ft. Compute the air-hne distance from the camp to the summit of
the mountain.
9. Two towns A and B^ of which B is 25 miles northeast of J., are to
be connected by a new road. 11 miles of the road is constructed from
A in the direction N. 21° E. ; what must be length and direction of the
remainder of the road, assuming it to be straight ?
22. Applications in Navigation. We shall confine ourselves
to problems in plane sailing ; i.e. we shall assume that the dis-
tances considered are sufficiently small so that the curvature of
the earth may be neglected.
11, § 22]
THE RIGHT TRIANGL^]
29
Fig. 21
Defixitiox. The course of a
ship is the direction in which she
is sailing. It is given either by
the points of a mariner's compass
(Fig. 21) as X. E. hy X. or in
degrees and minutes measured
dockicise from the north. Observe
that a " point '^ on a mariner's
compass is 11° 15'. Hence for
example, the course of a ship
could be given either as X. E. by
N. or as 33° 45'. A course S. E. by S. is the same as a course
of 146° 15'.
The distance a ship travels on a given course is always given
Departure ^ uautlcal mllcs or knots. A knot is the length
of a minute of arc on the earth's equator. (The
earth's circumference is then 360 x 60 = 21,600
knots.) The horizontal component of the dis-
tance is called the departure, the vertical com-
ponent is called the difference in latitude. The
departure is usually given in miles (knots), the
difference in latitude in decrees and minutes.
Fig. 22
Example. A ship starts from a position in 22° 12' X. lati-
tude, and sails 321 knots on a course of 31° 15'. Find the
difference in latitude, the departure, and the latitude of the
new position of the ship,
diff. in lat. = distance times cosine of course
= 321 cos 31° 15'
= 321 X 0.855 = 274' = 4° 34'.
departure = distance times sine of course
= 321 sin 31° 15'
= 321 X 0.519 = 167 knots.
Since the ship is sailing on a course wliich increases the lati-
30 PLANE TRIGONOMETRY [II, § 22
tude, the latitude of the new position is 22° 12' + 4° 34' = 26°
46' N.
Knowing the difference in latitude and the departure, we are
able to calculate the new position of the ship, if the original
position is known. In the preceding example, we found the
latitude of the new position from the difference in latitude.
To find the difference in longitude from the departure is not
quite so simple. As the latitude increases, a given departure
implies an increasing difference in longitude. Only on the
equator is the departure of one nautical mile equivalent to a
difference in longitude of one minute.
The adjacent figure shows a departure AB in latitude ^ -^ ^
In practice, it is customary to take for <^
in the determination of difference in longi-
tude the so-called middle latitude^ i.e. the
latitude halfway between the original latitude and the final
latitude.
Thus in the preceding example, the original latitude was
22° 12' N, the final latitude was 26° 46' N. The middle lati-
tude is therefore i (22° 12' + 26° 46')= 24° 29'. Hence
j.pp . T ., -, departure
difference m longitude = -, , ^ . ^ ^. — = — -. — ^
cosine 01 middle latitude
167 16^ = 184' = 3° 4'.
cos 24° 29' ■" 0.910
The determination of the position of a ship from its course
and distance is known as dead reckoning. It is subject to con-
siderable inaccuracy and must often in practice be checked by
II, § 22] THE RIGHT TRIANGLE 31
direct determination of position by observations on the sun
or stars.
EXERCISES
1. A ship sails X. E. by E. at the rate of 12 knots per hour. Find the
rate at which it is moving north.
2. A ship sails N. E. by N. a distance of 578 miles. Find its departure
and difference in latitude.
3. A ship sails on a course of 73^ until its departure is 315 miles. Find
the actual distance sailed. Find also its difference in latitude.
4. A ship sails from latitude 47^ 15' N. 670 miles on a course N. W.
by N. Find the latitude arrived at.
6. A ship sails from latitude 30° 24' N. and after 25 hours reaches lati-
tude 35° 26' X. Its course was X. X. W. Find the average speed of the
ship.
6. A vessel sails from lat. 24^ 30' X., long. 30^ 15 W., a distance of 692
miles on a coiu-se of 32^20'. Find the latitude and longitude of its new
position.
7. A vessel sails from lat. 10^30' S., long. 167^ 20' W.. a distance of
692 miles on a course of 152^ 30'. Find the latitude and longitude of its
new position.
ordinate of P
y
secant 6 =
distance of F
abscissa of P
_ r
X
f»nt,a n P'pn t fi -
abscissa of P
X
ordinate of P
y
CHAPTEE III
SIMPLE TRIGONOMETRIC RELATIONS
23. Other Trigonometric Functions. The reciprocals of
the sine, the cosine, and the tangent of any angle are called,
respectively, the cosecant, the secant, and the cotangent of
that angle. Thus,
^^ distance of P r . •-, -, , r..
--------^ /] (provided y =^ 0).
(provided x ^ 0).
(provided y ^0),
These functions are written esc 6, sec 6, ctn 6. From the
definitions follow directly the relations
CSC 6 = , sec 6 = , ctn 9 = ;
sin 6 cos 6 tan 6
or
CSC 6 * sin ^ = 1, sec d • cos 6 = 1, ctn 6 • tan 6 = 1.
To the above functions may be added versed sine (written versin), the
coversed sine (written coversin), and the external secant (written exsec),
which are defined by the equations versin d = 1 — cos d^ coversin 6 =
1 — sin ^, and exsec 6 = sec 6 — 1. Of importance in navigation and service-
able in other applications (see § 38) is the haversine (written hav)
which is defined to be equal to one half the versed sine ; i.e.
have = 1(1 — COS0).
24. The Representation of the Functions by Lines. Con-
sider an angle 6 in each quadrant and about the origin draw
32
Ill, § 24] SIMPLE TRIGONOxMETRIC RELATIONS 33
Fig. 24
a circle of unit radius. Let P{x, y) be the point where the
circle meets the terminal side of 6. Then
sin (9 = ^=?/, cos (9 = 1 = a;,
i.e. the sine is represented by the ordinate of P and the cosine
by the abscissa. Hence the sine and cosine have respectively
the same signs as the ordinate and abscissa of P.
If we draw a tangent to the circle at the point A where the
Fig. 25
circle meets the a;-axis and let the terminal line of meet this
tangent in Q, we have
tan^ = ^=^Q, sec^ = ^=OQ.
Note that when = 90°, 270°, and in general 90 + n . 360°,
-270° + n . 360°, where n is any integer, there is no length AQ
cut off on the tangent line and hence these angles have no
tangents.
If we draw a line tangent to the circle at the point B where
34
PLANE TRIGONOMETRY
[III, § 24
the circle cuts the y-a,xis and let the terminal line of cut
this tangent in B, we have
ctn ^ = ^ = BE, and esc (9 = — = OR.
Fig. 26
H Cotan. ^
1^
5^
s.
/v
\
/ *'V
\
^(^
0^
M
I
/
EXERCISES
1. From Fig. 24 prove sin^ 8 + cos^ ^ = 1.
2. From Fig. 25 prove 1 + tan2 6 = sec^ ^.
3. From Fig. 26 prove 1 + ctn2 6 = csc2 e,
25. Relations among the Trigonometric Functions. As
one might imagine, the six trigonometric functions sine, cosine,
tangent, cosecant, secant, cotangent are connected by certain
relations. We shall now find some of these relations.
From Eig. 9 (§ 10) it is seen that for all cases we have
(1) x^ + y^ = r\
If we divide both sides of (1) by r^, we have
- + ^ = 1 (by hypothesis r=^0);
or
sin2 e + cos2 e = 1.
Dividing both sides of (1) by x^, we have
7/2 A.2
1 + -. = ^ (if o; =5^0).
Therefore,
x^ x"-
1 + tan2 e = sec2 6.
Similarly dividing both sides of (1) by ]p- gives
;+i=^
or
ctn2 e + 1 = csc2 e
(if2/=^0);
Ill, § 26] SIMPLE TRIGONOMETRIC RELATIONS 35
Moreover, we have
y
A V ^ sin 9
tan e = ^ = - = ^,
X X cos 6
r
and, similarly,
' cos 6
ctn9 = -T-5-.
, sin 6
26. Identities. By means of the relations just proved
any expression containing trigonometric functions may be
put into a number of different forms. It is often of the
greatest importance to notice that two expressions, although
of a different form, are nevertheless identical in value. (How
was an "^ identity'' defined in algebra ?)
The truth of an identity is usually established by reducing
both sides, either to the same expression, or to two expres-
sions which we know to be identical. The following examples
will illustrate the methods used.
Example 1. Prove the relation sec2 d + csc^ 6 = sec2 d csc2 d.
We may write the given equation in the form
^ + -^^ = sec2 ^ csc2 (9,
cos2 6 sin2 e
sin2 d + cos2 e
~ sec2 d csc2 ^,
which reduces to
cos2 e sin2 e
= = sec2 d csc2 d.
cos2 e sin2 d
sec2 d csc2 (9 = sec2 ^ csc2 d.
Since this is an identity, it follows, by retracing the steps, that the
given equality is identically true.
Both members of the given equality are undefined for the angles 0^, 90°,
180°, 270°, 360°, or any multiples of these angles.
PQc2
Example 2. Prove the identity 1 + sin ^ =
^ 1 - sin ^
Since cos2 ^ = l — sin2 d, we may write the given equation in the form
1 + sin ^ = ^ ~~ '^"^'^ ^ or 1 4- sin ^ = 1 + sin d.
1 - sin ^
36 PLANE TRIGONOMETRY [III, § 26
As in Example 1, this shows that the given equahty is identically true.
The right-hand member has no meaning when sin ^ = 1 , while the left-
hand member is defined for all angles. We have, therefore,- proved that
the two members are equal except for the angle 90*^ or (4 m-|-1)90°, where
n is any integer.
The formulas of § 25 may be used to solve examples of the
type given in § 16.
Example 3. Given that sin 6 = -^\ and that tan d is negative, find the
values of the other trigonometric functions.
Since sin^ d -\- cos2 ^ = 1, it follows that cos 6 = ± ^|, but since tan is
negative, lies in the second quadrant and cos d must be — i|. More-
over, the relation tan = sin ^/cos gives tan =— y\. The reciprocals
of these functions give sec ^ = — i|, esc = J/, ctn = — -y.
EXERCISES
1. Define secant of an angle ; cosecant ; cotangent.
2. Are there any angles for which the secant is undefined ? If so,
what are the angles ? Answer the same question for cosecant and co-
tangent.
3. Define versed sine ; coversed sine ; haversine.
4. Complete the following formulas :
sin2 4- cos2 = ? 1 + tan2 z= ? 1 + ctn2 0= ? tan ^ = ?
Do these formulas hold for all angles ?
5. In what quadrants is the secant positive ? negative ? the cosecant
positive ? negative ? cotangent positive ? negative ?
6. Is there an angle whose tangent is positive and whose cotangent is
negative ?
7. In what quadrant is an angle situated if we know that
(a) its sine is positive and its cotangent is negative ?
(6) its tangent is negative and its secant is positive ?
(c) its cotangent is positive and its cosecant is negative ?
8. Express sin2 ^ -f cos ^ so that it shall contain no trigonometric
function except cos 0.
9. Transform (1 -h ctn2 ^)csc so that it shall contain only sin 0.
10. Which of the trigonometric functions are never less than one in
absolute value ?
11. Eor what angles is the following equation true : tan = ctn ?
12. How many degrees are there in when ctn ^ = 1 ? ctn =— 1?
sec ^ = \/2 ? CSC ^ = V2 ?
Ill, § 27] SIMPLE TRIGONOMETRIC RELATIONS 37
13. Determine from a figure the values of the secant, cosecant, and
cotangent of 30°, 150^ 210°, 330°.
14. Determine from a ligure the vahies of the secant, cosecant, and
cotangent of 45^ 135°, 225°, 315°.
15. Determine from a figure the values of the sine, cosine, tangent,
secant, cosecant, and cotangent of 60°, 120°, 240°, 300°.
16. Find 6 from the following equations.
(tt) sin d = I. (0 tan ^ = — 1;
(6) sin d=-l. ( j) ctn <9 = - 1.
(c) cos d = |. (/c) tan ^ = 1.
(d) cos ^ = - i. (0 ctni9 = 1.
(e) sec = 2. (m) tan2 ^ = 3.
(/) sec ^ = - 2. (n) sin ^ = 0.
{g) CSC ^ = 2. (o) cos ^ = 0.
Qi) CSC = -2. (p) tan ^ = 0.
Prove the follovring identities and state for each the exceptional values
of the variables, if any, for which one or both members are undefined :
17.
cos d tan e =
: sin 0.
18.
sin ctn =
cos^.
19.
1 + sin <9 _
cos (9
cos 1 — sin
20. sin2 __ cos2 = 2 sin2 0-1.
21. (1 — sin2 0) csc2 = ctn2 0.
22. tan ^ + ctn ^ = sec esc 0.
23. [x sm0 -\-y cos 0^ + [xGos0—y sin 0Y = x2 + r/2.
24. ^-^^ =cos^.
tan -\- ctn
25. 1 — ctn4 = 2 csc2 - csc^ 0.
26. tan2 — sin2 = tan2 sin2 0.
27. 2(1 H- sin 0) (1 -f cos (9) = (1 + sin (9 + cos 0)2.
28. sin6 -h cos6 <9 = 1 - 3 sin2 cos2 ^.
29. csc^ ^ csc^ :.2sec2g.
CSC 0—1 CSC ^ + 1
1 — tan _ Ctn 0^1 ^
1 -f- tan (9 ~ ctn -\- 1
27. The Trigonometric Functions of 90° — 9. Figure 27
represents angles 6 and 90° — 0, when is in each of the four
38
PLANE TRIGONOMETRY
[III, § 27
quadrants. Let OP be the terminal line of 6 and OP' the
terminal line of 90° -0. Take OP' = OP and let {x,y) be
T p'
p y
P' p y
Fig. 27
;-^ X
the coordinates of P and (x', y') the coordinates of P\
in all four figures we have
^' = y, y' = ^y r' = r.
Hence
Then
sin (90° - 6>) = 2^^ = - = cos 6>,
Also,
cos (90° _ ^) = - = ^ = sin (9,
r r
tan (90° - ^) = ^ = ^ = ctn 0.
x' y
CSC (90°-^)= sec (9,
sec (90° - ^) = CSC 6y
ctn(90°-^)=tan(9.
Definition. The sine and cosine, the tangent and cotangent,
the secant and cosecant, are called co-functions of each other.
The above results may be stated as follows : Any function
of an angle is equal to the corresponding cofunction of the com-
plementary angle,^
28. The Trigonometric Functions of 180° — 6. By draw-
ing figures as in § 27, the following relations may be proved :
sin (180° - ^) = sin 6, esc (180° -0)= esc 6,
cos (180° - 6>) = - cos 6, sec (180° - 0) = - sec 6,
tan (180° - 6>) = - tan 6, ctn (180° - 6>) = - ctn 6.
The proof is left as an exercise.
* Two angles are said to be complementary if their sum is 90°, regardless
of the size of the ano^les.
Ill, § 29] SIMPLE TRIGONOMETRIC RELATIONS 39
29. The result of § 27 shows why it is possible to arrange
the tables of the trigonometric functions with angles from 0°
to 45° at the top of the pages and angles from 45° to 90° at
the bottom of the pages. For example, since sin (90° — 0) = cos 0,
the entry for cos 6 will serve equally well for sin (S0° — 0).
As particular instances we may note sin 67° = cos 23°, tan 67°
= ctn 23°, cos 67° = sin 23°. Verify these from the table.
The result of § 28 enables us to find the values of the func-
tions of an obtuse angle from tables that give the values only
for acute angles. It will be noted that § 28 says that a7iy
function of an obtuse angle is in absolute value equal to the same
function of its supplementary angle but may differ from it in
sign.
Thus to find tan 137° we know that it is in absolute value
the same as tan (180° - 137°) = tan 43° = 0.9325. But tan 137°
is negative. Hence
tan 137° = - 0.9325.
Similarly, sin 137° = 0.6820.
cos 137° = - 0.7314.
EXERCISES
Find the values of the following :
tan 146°, sin 136^ cos 173^ tan 100^, cos 96^ sin 138%
tan 98% sin 145% cos 168% cos 138°, tan 173% cos 157°.
CHAPTER lY
OBLIQUE TRIANGLES
30. Law of Sines. Consider any triangle ABO with the
altitude CD drawn from the vertex C (Fig. 28).
On C
In all cases we have sin ^4 = - , sin B = ->
b a
Therefore, dividing, we obtain
sin A a
- , or :
b sm A
(1)
(2)
sin B b ' sin A sin B
If the perpendicular were dropped from B, the same argu-
ment would give a/sin A = c/sin (7. Hence, we have
d _ i> _ c
sin A sin B sin C
This law is known as the law of sines and may be stated as
follows : Any two sides of a triangle are proportional to the
sines of the angles opjjosite these sides.
31. Law of Cosines. Consider any triangle ABC with the
altitude CD drawn from the vertex C (Fig. 29).
In Fig. 29 a
AD = b cos A ; CD = b sin A ; DB = c — b cos A.
In Fig. 29 b
AD = — b cos A ; CD = b sin A ; DB = c — b cos A,
In both figures
a2 = DB'- + CD^.
40
IV, § 32]
Therefore
OBLIQUE TRIANGLES
a- = c'2 - 2 he cos A + h"- cos2 A -|- ^2 siii2 ^
= o2 - 2 6c cos ^ + (cos2 ^ + sin2 A)b'^,
C
41
whence
a2 = 62 + c2 — 2 &c cos .4.
The result holds also when J. is a right angle. Why ?
Similarly it may be shown that
62 = c2 + a^ - 2 ca cos B,
c2 = a2 + 62-2a6cos C.
Any one of these similar results is called the law of cosines.
It may be stated as follows :
Tlie square of any side of a triangle is equal to the sum of the
squares of the other two sides diminished by twice the product of
these two sides times the cosine of their included angle.^
32. Solution of Triangles. To solve a triangle is to find
the parts not given, when certain parts are given. From
geometry we know that a triangle is in general determined
when three parts of the triangle, one of which is a side,
are given.f Eight triangles have already been solved
(§ 15), and we shall now make use of the laws of sines and
cosines to solve oblique triangles. The methods employed
will be illustrated by some examples. It will be found
advantageous to construct the triangle to scale, for by so doing
one can often detect errors which may have been made.
* Of what three theorems in elementary geometry is this the equivalent ?
t When two sides and an angle opposite one of them are given, the triangle
is not always determined. Why ?
42 PLANE TRIGONOMETRY
33. Illustrative Examples.
[IV, § 33
Fui. :io
Example 1. Solve the triangle ABC, given
a = £76 A = 30° 20^ B = 60° 45', a = 276.
Solution :
C= 180°- (A + B)z= 180°- 91° 5' = 88° 55';
^ ^ g sin ^ ^ 276 sin 60° 45' ^ (276) (0.8725) ^ 47^3 g .
sin^ sin 30° 20' 0.5050
also
^ ^ g sin C ^ 276 sin 88° o r>' ^ (276) (0.9998) ^ ^^^ ^
sin.l sin 30° 20' 0.5050
•Check : It is left as an exercise to show that for these values we have
c"-^ = a- -{■ b- — 2 ab cos C.
Example 2. Solve the triangle ABC, given
A = 30°, 5 = 10, a = 6.
^6 Constructing the triangle ABC, we see that
two triangles ABiC and AB^C answer the descrip-
FiG. 31
^ tion since 6 > a > altitude CB.
Solution : Now
sinB, ^ & ^ ^^ gij^ 5^ ^ 6^in^ ^q 833,
sin A a a
Bi = 56°. 5.
whence
But
B2 = 180°- Bi = 180° - 56°.5 = 123°.5,
and
Ci = 180° - (^ + ^1) = 180° - 86°.5 = 93°. 5,
C2 = 180° -{A-\- B2) = 180° - 153°. 5 = 26°.5.
Now
C2 _ sin C2
a sin A sin A 0.500
Also
ci _ sin Ci _ osinCa _ (6)(0.
— — 7 , or Ci — — ^ — — —
a sm A sm J.
0.500
11. c
Check : Ci^ = gS ^_ 52 _ 2 g6 cos Ci.
143.5 = 36 + 100 +(2) (6) (10) (0.061) = 143.3.
C22 = g2 + 62 - 2 ab cos C2.
28.62 = 36 + 100 - (2) (6)(10) (0.895) = 28.60.
IV, § 33]
OBLIQUE TRIANGLES
43
Example 3. Solve the triangle ABC, given a = 10, h = 0, C = 40^.
Solution : c'^ = a'^ -\- b^ — 2 ah cos C ^
Joy '
= 100 4- 36 -(120) (0.766)= 44.08.
Therefore c = Q. 64. Now
sm
^ ^asin(;^ (10)(0.643) ^ ^^^g
c 6.64
ie. Jl = 104°. 5. Likewise,
^.^^^^6sin_C^(6)(0.643)^
c 6.64 '
Check : A ^ B ^ C = 180°.0.
Example 4. Solve the triangle ABC when
a =1 7, 6=3, c = 5.
From the law of cosines.
cos.l = ^^ + ^-^-^^ = -l = -0.500,
2 he 2
2ac 14
COS = ^^ + ^^^^ = 11 = 0.786.
2 ah 14
Therefore
^ = 120°, 5 = 21^8, C = 38°.2.
Check : A ■\- B -\- C = 180°.0
EXERCISES
1. Solve the triangle ABC, given
(a) ^ = 30^ 5 = 70°,
(5) A = 40°, B = 70°,
(c) ^ = 4.5°.5, C = 68°.o,
(d) l? = 60°.o, C = 44°20\
(e) a = 30, 6 = 54, C = 50° ;
(/) 6 = 8, cf = 10, C = 60° ;
a = 100 ;
c = 110 ;
5 = 40-;
c = 20;
(g) a = 10, 6 = 12, c = 14 ;
(/i) a = 21, 6 = 24, c = 28.
2. Determine the number of solutions of the triangle ABC when
(a) A = 30°, 6 = 100, a = 70
(6) ^=30°, 6 = 100, a = 100
(c) ^ = 30°, 6 = 100, a = 50
(d) ^ = 30°, 6 = 100, a = 40
(e) A = 30'^, 6 = 100, a = 120 ;
(/) A = 106°, 6 = 120, a = 16 ;
(g) A= 90°, 6= 15, a= 14.
44
PLANE TRIGONOMETRY
[IV, 33
(c) A = 30°, a = 22, b= 34.
One force
rind the
3. Solve the triangle ABC when
(a) ^ = 37'-' 20', a = 20, 6 = 26;
{b) ^ = 37^20', a = 40, 6 = 26;
4. In order to find the distance from a point ^ to a point 5, a line
AC and the angles CAB and ACB were measured and found to be
300 yd., 60° 30^ 56° 10' respectively. Find the distance AB,
5. In a parallelogram one side is 40 and one diagonal 90. The angle
between the diagonals (opposite the side 40) is 25°. Find the length of
the other diagonal and the other side. How many solutions ?
6. Two observers 4 miles apart, facing each other, find that the angles
of elevation of a balloon in the same vertical plane with themselves are
60° and 40° respectively. Find the distance from the balloon to each
observer and the height of the balloon.
7. Two stakes A and B are on opposite sides of a stream ; a third
stake C is set 100 feet from A^ and the angles J. C-B and CAB are observed
to be 40° and 110°, respectively. How far is it from AtoB?
8. The angle between the directions of two forces is 60°.
is 10 pounds and the resultant of the two forces is 15 pounds
other force.*
9. Resolve a force of 90 pounds into two equal components whose
directions make an angle of 60° with each other.
10. An object B is wholly inaccessible and invisible from a certain
point A, However, two points C and D on a line with A may be found
such that from these points B is visible. If it is found that CD = 300 feet,
^C = 120 feet, angle DCB = 70°, angle CDB = 50°, find the length AB,
11. Given a, 6, A, in the triangle ABC. Show that the number of
possible solutions are as follows : q
^<90°
( a 5 one solution,
12. The diagonals of a parallelogram are 14 and 16 and form an angle
of 50°. Find the length of the sides.
^ ^ * It is shown in physics that if the line segments AB
and AC represent in magnitude and direction two
forces acting at a point A, then the diagonal AD of the
parallelogram ABCD represents both in magnitude and
direction the resultant of the two given forces.
one solution.
IV, § 34]
OBLIQUE TRIANGLES
45
13. Resolve a force of magnitude 150 into two components of 100 and
80 and tind the angle between these components.
14. It is sometimes desirable in surveying to extend a line such as AB
in the adjoining figure. Show that this can be done by means of the
broken line ABODE. What measurements are necessary ?
15. Three circles of radii 2, 6, 5 are mutually tangent. Find the angles
between their lines of centers.
16. In order to find the distance between two objects A and B on op-
posite sides of a house, a station C was chosen, and the distances CA
= 500 ft., CB = 200 ft., together with the angle ACB = 65^30', were
measured. Find the distance from A to B.
17. The sides of a field are 10, 8, and 12
rods respectively. Find the angle opposite the
longer side.
18. From a tower 80 feet high, two objects,
A and B, in the plane of the base are found to
have angles of depression of 13° and 10^ respec-
tively ; the horizontal angle subtended by A and B at the foot C of the
tower is 44°. Find the distance from A to B.
34. Areas of Oblique Triangles.
1. When two sides and the included angle are given.
Denoting the area by S, we have from geometry
C /S = I ch,
but ^ = & sin ^ ; therefore
(1) S = \ cb sin A.
Likewise,
Fig. 34
S = ^ ah sin C and S ■■
i ac sin B.
2. When a side and two adjacent angles are given.
Suppose the side a and the adjacent angles B and C to be
given. We have just seen that S = \ac sin B. But from the
law of sines we have
a sin (7
c =
sin A
46 PLANE TRIGONOMETRY [IV, § 34
Therefore
^ _ g- « sin J5 » sin C
2 sin^
But sin A = sin [180° - (j8 + (7)] = sin {B + G). Therefore
o __ (X^ sin B sin C
~2sin(^+(7)*
3. Tr/ie7i ^/ie f^?'ee sides are given.
We have seen that S = ^bc sin ^. Squaring both sides of
this formula and transforming, we have
^2 ^ ^ sin2 A = — (l- cos2^)
4 4
= |(l + cos^).|(l-cos^);
whence, by the law of cosines,
^c /^i , ^^ + c2 — a^\ hcf. 62 + c2 — a2'
>S2 = ^ 1-f
2V 2bG J 2\ 2 be
2 6c + 62 ^ c2 - a2 2 6c - 62 -~ c2 + a2
4 4
6 + c + a 6 + c — a a— 6 + c a + 6-
2 2
which may be written in the form
,^2 = s(s — a)(s — 6)(s — c),
where 2s = a + 6 + c. Therefore,
(2) S = ■Vs(s - a)(s - 6) (s - c).
35. The Radius of the Inscribed Circle. If r is the radius
of the inscribed circle, we have from elementary geometry,
since s is half the perimeter of the triangle, S = 7^s', equating
this value of S to that found in equation (2) of the last article
and then solving for r, we get,
-4
(s — a)(s — b)(s — c)
s
IV, § 36]
OBLIQUE TRIANGLES
47
EXERCISES
Find the area of the triangle ABC, given ^
1. a = 25, 6 = 31.4, = 80^25'. 4. a = 10, 6 = 7, C=60°.
2 6 = 24, c = 34.3, A = 60° 25'. 5. a = 10, 6 = 12, C = 60°.
3. a = 37, 6 = 13, C = 40°. 6. a = 10, b = 12, C = 8^
7. Find the area of a parallelogram in terms of two adjacent sides
and the inckided angle.
8. The base of an isosceles triangle is 20 ft. and the area is 100/ VS
sq. ft. Find the angles of the triangle. Ans. 30°, 30°, 120°.
9. Find the radius of the inscribed circle of the triangle whose sides
are 12, 10, 8.
10= How many acres are there in a triangular field having one of its
sides 50 rods in length and the two adjacent angles, respectively, 70°
and 60° ?
36. The Law of Tangents. For the work in the next
chapter the formulas in this
and the next article will be
needed.
Let CD be the bisector of
the angle C of the A ABC.
Through A draw a line II DC,
meeting BC produced in E.
Then CE = b. Why ? From
A draw a line q _L DC meeting
CB in F. At F draw a line r ± AF meeting AB in G.
AE=p.
Kow AACF is isosceles. Why? The angle ACE = ZA
+ ZB and the bisector of Z.ACE is _L CD. Hence Z CAF
==ZCFA = IZ{A + B). Moreover ZBAF=ZA-^Z{A
+ B) = ^Z{A-B).
B r^
Q
A + B
-I.
r
Let
Now
tan^i-±^ = i^ and tan —
2 q 2
tan
2
tan
A-B
48
PLANE TRIGONOMETRY
But
p_BE_a + h ^^r.^
r BF a-b ^ '
Hence
tan^ + ^
2 a + b
tan^-^ «-^
[IV, § 36
37. Angles of a Triangle in Terms of the Sides. Con-
struct the inscribed circle of the triangle
and denote its radius by r. If the perim-
eter a + b + c = 2s, then (Fig. 36)
AE = AF=s-a,
A^s-c^F^ i. BD = BF=s-b,
Fig. 3G Qjj ^ (J^ ^ ^ _ ^^
Then tanij. = -^^, tani5=-^^, tan|(7 = - ^
• a s — s — c
where, from § 35,
-V
{s — a){s — b){s — c) ^
38. Solution of Triangles by Means of the Haversine.
The haversine may be used advantageously in the solution of triangles,
(1) when two sides and the included angle are given ; (2) when the
three sides are given. The law of cosines gives
2hav.d = l-cos^ = l _ ?>^ + c^ - ^2
2 be
2 6c
or 4 6chav J. = a2 — (6 — c)2.
1. If 5, c and A are given we may find a from the formula
(1) fl2^(6~ c)2 -f 4 6chav^.
Similar formulas give 62 or c^ in terms of a^c^B and a, 6, C respectively.
2. If a, 6, c are given, we may find A from the formula
(2) ^^^A^a'-ih-cY^is-l^is-c)^
^ ^ 4 be 6c
Similar formulas will give B and C
IV, § 38] OBLIQUE TRIANGLES 49
Example 1. Given A = 04^
23'
.4,
6 = 55.12, r = .39.90. To find a.
By formula (1) above :
t
b = 55.12
be = 2199
c = 39.90
hav 94° 23'.4 = 0.0446
(b-c)= 15.22
6c hav ^= 1184
(?j_c)2= 231.6
4 6c hav .4 = 4736
4 be hav A = 4736
a2 = 4968
a = 70.49
Example 2. Given a = 4.51, b = 6.13, c = 8.16. Find A, B, C.
a2
hav ^=i^^ = 0.0811 A= 33^05
200.1
4 6c = 200.1
^^- 3^-58 hav 5 =2^^ = 0.1648 B= 47^54
(c-q)2^ 13.32 147.21
52_(c-a)2= 24.26
ac= 36.80
4ac = 147.21
c2= 66.59 have = -^5:51 =0.5785 C^ 99^02^
(6-«)2 = _2^ 110.58 ^^^^^, ^^^r^
c2^^b-ay= 63.97
ab= 27.646
4a6 = 110.58
EXERCISES
Solve the following triangles :
1. a = 62.1, 6 = 32.7, c = 47.2.
2. ^ = 37° 20', 6 = 2.4, c = 4.7.
3. B = 12r.32', a = 27.9, c = .35.8.
4. a = 3.2, 6 = 5.7, c = 6.5.
5. C = 72°21'.4, a = 314.1, 6 = 427.3.
6. a = 346.1, 6 = 425.8, c = 562.3.
CHAPTER V
LOGARITHMS
39. The Invention of Logarithms. The extensive numeri-
cal computations required in business, in science, and in engi-
neering were greatly simplified by the invention of logarithms
by John Napier, Baron of Merchiston (1550-1617). By means
of logarithms w^ are able to replace multiplication and division
by addition and subtraction, processes which we all realize are
more expeditious than the first two.
If we consider the successive integral powers of 2
(1)
Exponent x
1
2
3
4
5
6
7
Result 2^ . .
2
4
8
16
32
64
128
Exponent x .
8
9
10
11
12
etc.
A. P.
Result 2^ . .
256
512
1024
2048
4096
etc.
G. P.
we see that the results form a geometric progression (G. P.)
and the exponents an arithmetic progression (A. P.). We
know from elementary algebra that
and
^n _ ^m
■ = X""
Hence if we wish to multiply two numbers in our G. P. e.g,
4 X 8, we merely have to add the corresponding exponents 2
and 3 and under the sum 5 find the desired product 32. Sim-
ilarly, if we wish to divide e.g. 4096 by 128, we merely have to
subtract the exponent corresponding to 128, from that cor-
50
\-. § 39]
LOGARITHMS
51
responding to 4096 and under their difference 5 we find ^he
desired quotient 32.
To make the above plan at all useful it is evident that our
table must be expanded so as to contain more numbers. First
we can expand our table so that it will contain numbers less
than 2, by subtracting 1 successively from the numbers in the
A. P. and by dividing successively by 2 the numbers in the
G.P.
(2)
In the second place we may find new numbers by inserting
arithmetic means and geometric means. Thus, if we take the
following portion of the preceding table
-5
-4
-3
-2
-1
1
2
3
4
5
6
7
0.03125
0.0625
0.125
0.25
0.5
1
2
4
8
16
32
64
128
-2
- 1
1
2
3
4
i
i
1
2
4
8
16
and insert between every two successive numbers of the upper
line their arithmetic, and between every two successive num-
bers of the lower line their geometric mean, we obtain the
table
-2
-f
-1
-i
i
1
1
2
. f
3
i
4
i
iV2
i
-J-V2
1
V2
2
2V2
4
4V2
8
8V2
16
(3)
If the radicals are expressed approximately as decimals, this
table takes the form
-2.0
-1.5
-1.0
-0.5
1.00
0.5
1.0
1.5
2
2.5
3
3.5
4
16
0.25
0.35
0.50
0.72
1.41
2.00
2.83
4.00
5.66
8.00
11.31
52 PLANE TRIGONOMETRY [V, § 39
By continuing this process we can make any number appear
in the G. P. to as high a degree of approximation as we desire.
To prepare an extensive table, which gives values at small inter-
vals, is quite laborious. However, it has been done, and we
have printed tables so complete that actual multiplication of
any two numbers can' be replaced by addition of two other
numbers. We shall soon learn how to use such tables.
40. Definition of the Logarithm. The logarithm of a
number ^ to a base 6 (6 > 0, =5!^ 1) is the exponent x of
the power to which the base h must be raised to produce the
number J^,
That is, if
&- = AT,
then
These two equations are of the highest importance in all work
concerning logarithms. One should keep in mind the fact
that if either of them is given, the other may always be
inferred.
The numbers forming the A. P. in tables 1, 2, and 3 of § 39
are the logarithms of the corresponding numbers in the G. P.,
the base being 2. From table 3 we have 2^ = 4\/2 which says
log2 4V2 = |.
EXERCISES
1. When 3 is the base what are the logarithms of 9, 27, 3, 1, 81, 1,
1
2. Why cannot 1 be used as the base of a system of logarithms ?
3. When 10 is the base what are the logarithms of 1, 10, 100, 1000 ?
4. Find the values of x which will satisfy each of the following
equalities :
(a) logs 27 = X. (d) logo a = X. {g) logs x = 6.
(6) log^ 3 = 1. (e) loga 1 = X. {K) logas x = J.
(c) log^ 5 = i. (/) loga -h = ^' (0 logo.ooi x = 2.
V, § 41] LOGARITHMS 53
t
5. Find the value of each of the following expressions :
(a) log 2 16. (c) loge^l^ (e) log25 125.
(6) log343 49. (d) log2Vi6. (/) log2^V.
41. The Three Fundamental Laws of Logarithms. From
the laws of exponents we derive, the following fundamental
laws.
I. The logarithm of a product equals the sum of the logarithms
of its factors. Symbolically,
logft MN = log5 M + logft A^.
Proof. Let log^ M = x, then b"" = M. Let log^ ^= !/) then
6'^ = X. Hence we have 3fJSf = &^+^, or
log, MX =x + y, i.e. log, JAY = log, M + log, JV.
II. TJie logarithm of a quotient equals the logarithm of the
dividend minus the logarithm of the divisor. Symbolically,
log6^= logft M — logfe N.
N
Proof. Let log, M = x, then 6^ = M. Let log, X^ y, then
6'^ = X. Hence we have M/X = 6^~^, or
M M
^ogt,^— = x-y, i.e. log,^ = log, Jf - log, Y".
III. The logarithm of the pth power of a number equals p
times the logarithm of the number. Symbolically
logft MP = p logft M.
Proof. Let log, M = x, then b"" = M. Kaising both sides
to the ^th power, we have b^"" = M^. Therefore
log, M^ =2)x = p log, .v.
Prom law III it follows that the logarithm of the real jjositive
nth root of a number is one nth of the logarithm of the member.
54 PLANE TRIGONOMETRY [V, § 41
EXERCISES
1. Given logio 2 = 0.3010, logio 3 = 0.4771, logio 7 = 0.8451, find the
value of each of the following expressions :
(a) logio 6. . (/) logio 5.
[Hint: logio 2x3= logio 2 + logio 3.] [Hint: logio 5 = logio V--]
(b) logio 21.0. (9) logio 15a
(c) logio 20.0. W logio Vl4.
(d) logio 0.03. (i) logio 49^
(e) logio |. 0") logio V24. 75.
2. Given the same three logarithms as in Ex. 1, find the value of each
of the following expressions :
^^\ 1^^ 4 X 5 X 7 ^7.N i^rr ^ X 3 X 20 . . , „ 2058
(d) logio (2)25. (e) logio (3)3(5)6, (/) logio(23)(i).
42. Logarithms to the Base 10. Logarithms to the base 10
are known as common or Briggian logarithms. Proceeding as
in § 39 we can show that lO^-^^^^^ = 2, i.e. logio ^ = 0.3010. Let
us multiply both members of the equation lO^-^^^^ = 2 by 10, 10^,
10^, etc. and notice the effect on the logarithm.
100.3010 ^ 2 logio 2 = 0.3010
10 3«io = 20 logio 20 = 1.3010
1Q2.3010 ^ 200 logio 200 = 2.3010.
It should be clear from this example that the decimal part of
the logarithm (called the mantissa) of a number greater than 1
depends only on the succession of figures composing the num-
ber and not on the position of the decimal point, while the in-
tegral part (called the characteristic) depends simply on the
position of the decimal point. Hence it is only necessary to
tabulate the mantissas, for the characteristics can be found by
inspection as the following considerations show.
Since
100 = 1, 10^ = 10, 102 = 100, 10^ = 1000, 10^ = 10,000, etc.
we have logio 1 = 0, log^o 10 = 1, log^o 100 = 2,
logio 1000 = 3, logio 10,000 = 4, etc.
V, § 42] LOGARITHMS 55
It follows that a number with one digit (9^= 0) at the left of the
decimal poiut has for its logarithm a number equal to + a
decimal ; a number with tv:o digits at the left of its decimal
point has for its logarithm a number equal to 1 + a decimal ; a
number with three digits at the left of the decimal point has
for its logarithm a number equal to 2 + a decimal, etc. We
conclude, therefore, that the characteristic of the common loga-
rithm of a number greater than 1 is one less than the number of
digits at the left of the decimal point.
Thus, logio 456.07 = 2.65903.
The case of a logarithm of a number less than 1 requires
special consideration. Taking the numerical example first con-
sidered above, if logio 2 = 0.30103, we have logio 0.2 = 0.30103-1.
Why? This is a negative number, as it should be (since the
logarithms of numbers less than 1 are all negative, if the
base is greater than 1). But, if we were to carry out this
subtraction and write logio 0-- = — 0.69897 (which would be
correct), it would change the mantissa, which is inconvenient.
Hence it is customary to write such a logarithm in the form
9.30103 - 10.
If there are n ciphers immediately following the decimal
point in a number less than 1, the characteristic is — n— 1.
For convenience, if n < 10, we icrite this as (9 — n) — 10. TJiis
characteristic is ivntten in two parts. The first part 9 — n is
icritten at the left of the mantissa and the — 10 at the right.
In the sequel, unless the contrary is specifically stated, we
shall assume that all logarithms are to the base 10. We may
accordingly omit writing the base in the symbol log when there
is no danger of confusion. Thus, the equation log 2 = 0.30103
means logio 2 = 0.30103.
To make practical use of logarithms in computation it is
necessary to have a conveniently arranged table from which
we can find (a) the logarithm of a given number and (b) the
number corresponding to a given logarithm. The general
56 PLANE TRIGONOMETRY [V, § 42
principles governing the use of tables will be explained by the
following examples [Tables, pp. 110, 111].
Example 1. Find log 42.7.
The characteristic is 1. In the column headed N (p. 110) we find 42
and if we follow this row across to the column headed 7, we read 6304,
which is the desired mantissa. Hence log 42.7 = 1.6304.
Example 2. Eind log 0.03273.
The characteristic is 8 — 10. The mantissa cannot be found in our
table, but we can obtain it by a process called interpolation. We shall
assume that to a small change in the number there corresponds a propor-
tional change in the mantissa. Schematically we have
Number Mantissa
^ r3270 -> 5145-
^13273 — > ? 14 = difference
3280 -> 5159
difference = 10
Our desired mantissa is 5145 + j3_ . 14 = 5149. Hence log 0.03273
= 8.5149 - 10.
Example 3. Find x when logic = 0.8485.
We cannot find this mantissa in our table, but we can find 8482 and
8488 which correspond to 7050 and 7060 respectively. Reversing the
process of example 2, we have schematically
Number
Mantissa
"7050 ^r-
84821 1
8485J
Difference =
10
? •) 9.9645 - 10
12.7795 - 10
Product = 601.9 ^ns. (<-) 2.7795
Example 2. Eind the value of 732.6 -f- 89.14.
Numbers Logarithms
732.6 (->) 2.8649
89.14 (^) 1.9501
Quotient = 8.219 Ans, (<-) 0.9148
Example 3. Eind the value of 89.14 -4- 732.6.
Numbers Logarithms
89.14 (->) 11.9501-10
732.6 (->) 2.8649
Quotient = 0.1217 ^ns. (<~) 9.0852 - 10
763.2 X 21.63
Example 4. Eind the value of
.i
Whenever an example involves several different operations on the
logarithms as in this case, it is desirable to make out a blank form. When
a blank form is used, all logarithms should be looked up first and entered
in their proper places. After this has been done, the necessary opera-
tions (addition, subtraction, etc.) are performed. Such a procedure
saves time and minimizes the chance of error.
EORM
Numbers Logarithms
763.3 (-^)
21.63 (-^) ( + )
product
986.7 (-» (-)
. . . . Ans. (<—)
58
PLANE TRIGONOMETRY
[V, §43
Form Filled In
Numbers
763.2 (->)
21.63 (->)
product
986.7 (->)
16.73 Ans. (<-)
Example 5. Find (1.357)^
Numbers
1.357
(-»
(1.357)5 = 4.602 Ans. (<-)
Example 6. Find the cube root of 30.11.
Numbers
30.11 (-^)
\/30.11 =3.111 Ans. (-e-)
Logarithms
2.8826
1.3351
4.2177
2.9942
1.2235
Logarithms
0.1326
0.6630
Logarithms
1.4787
0.4929
Example 7. Find the cube root of 0.08244.
Numbers Logarithms
0.08244 (-^) 28.9161 - 30
v/0.08244 = 0.4352 Ans. (^ 9.6387-10
EXERCISES
Compute the value of each of the following expressions using the table
on pp. 110, 111.
1.
34.96 X 4.65.
2.
518.7 X 9.02 X .0472.
3
0.5683
0.3216
4.
5.007 X 2.483
6.524 X 1.110
6.
(34.16 X .238)2.
6.
8,572 X 1.973 x (.8723)2.
7
'/ 648.8
"V (21.4)2
8.
J1379.
>'2791
9.
10.
4
'2. 8076 X 3.184 ^
(2.012)3
2941 X 17.32
2173 X 18.75*
11.
VO. 00732 ^
\/735
12. (20.027)i
13. 2100.
14- ^1502^ 100^.
15. ro n9.7.«?.^^i
16.
(0.02735) ^
V3275
(2.01)^
V, § 44] LOGARITHMS 59
M 1 '
44. Cologarithms. Since — and M are equivalent,
we may in a logarithmic computation, add the logarithm of
— instead of subtracting log N, The logarithm of — is
called the cologarithm of N, Therefore
colog N = log 1/^ = log 1 — log N = — log N,
since log 1 is zero.
We write cologarithms, like logarithms, with positive man-
tissas. Therefore the cologarithm is most easily found by sub-^
tracting the logarithm from zero, written in the form 10.0000
-^10.
Example. Find the colog 27.3.
10.0000 - 10
lo g 27. 3 rr 1.4362
colog 27. 3= 8.6638-10
The cologarithm can be written down immediately by subtracting the
last significant figure of the logarithm from 10 and each of the others
from 9. If the logarithm is positive the cologarithm is negative and
hence — 10 is affixed.
There is no gain in using cologarithms when we have a quotient of two
numbers. There is an advantage when either the numerator or denomi-
nator contains two or more factors, for we can save an operation of addi
tion or subtraction. Let us solve Ex. 4, § 43, using cologarithms.
1. Find the value of -
986.7
Numbers
Log
763.2
-^
2.8826
21.63
->
1.3351
986.7
->
(colog) 7.0058 -
-10
16.73
<-
1.2235
EXERCISES
Compute the value of each of the following expressions, using cologa-
rithms.
/ 2.80 X 37.6 /
>'4.96 X 23.3* ' V:
J ^/^.uv ^ t^.-v. « ^, 97.63x876.5
4.96 X 23.3 >2876 x 3.4 x 2.987
60 PLANE TRIGONOMETRY [V, §44
3 5 5 V3275
• 7x8x9x27.6' ' (2.01)*(1.76)io*
3^^ . ^ 1293 X 12 7 X 5
4.
^'''^' ' (l + ^V3)(760 + 8)
MISCELLANEOUS EXERCISES
1. What objections are there to the use of a negative number as the
base of a system of logarithms ?
2. Show that a^^Sa' = x.
3. Write each of the following expressions as a single term :
(a) log X + logy — log z. (6) 3 log x — 2 log 2/ + 3 log z.
(c) 3 log a — log (x + ?/) — I log (ex + c^) + log Vw + x.
4. Solve for x the following equations :
(a) 2 log2 X + log2 4 = 1. (c) 2 logio x — S logio 2 = 4.
(6) logs X - 3 logs 2 = 4. (d) 3 log2 x + 2 log2 3 = 1,
5. How many digits are there in 2^5 ? 31^^ ? 3^2 x 28 ?
6. Which is the greater, (|J)ioo or 100 ?
7. Find the value of each of the following expressions :
(a) log6 35. (6) logs 34. (c) logy 245. (d) logi3 26.
8. Prove that log^ a • log^ 6 = 1.
9. Prove that
loga ^ + ^ -^^ ~ ^ = 2 log, [X 4- Vi^"=l].
X - \/x2 - 1
10. The velocity v in feet per second of a body that has fallen s feet
is given by the formula v = V64.3 s.
What is the velocity acquired by the body if it falls 45 ft. 7 in. ?
11. Solve for x and ?/ the equations : 2^ = 16^^, x + 4 ?/ = 4.
CHAPTER VI
LOGARITHMIC COMPUTATION
45. Logarithmic Computation. In the last chapter a few
examples of the use of logarithms in computation were given
in connection with a four-place table. Such a table suffices
for data and results accurate to four significant figures. When
greater accuracy is desired we use a five-, six-, or seven-place
table.
No subject is better adapted to illustrate the use of logarith-
mic computation than the solution of triangles, which we shall
consider in some detail. Five-place tables and logarithmic
solutions ordinarily are used at the same time, since both tend
toward greater speed and accuracy.
46. Five-place Tables of Logarithms and Trigonometric
Functions. The use of a five-place table of logarithms differs
from that of a four-place table in the general use of so-called
" interpolation tables '' or " tables of proportional parts,'' to
facilitate interpolation. Since the use of such tables of pro-
portional parts is fully explained in every good set of tables,
it is unnecessary to give such an explanation here. It will be
assumed that the student has made himself familiar with their
use."^
In the logarithmic solution of a triangle we nearly always
need to find the logarithms of certain trigonometric functions.
For example, if the angles A and B and the side a are given,
we find the side b from the law of sines given in § 30,
, a sin 5
^ = — — T'
suiA
* For this chapter, such a five-place table should be purchased. See, for
example. The Macmillan Tables, which contain all the tables mentioned
here with an explanation of their use.
61
62 PLANE TRIGONOMETRY [VI, § 46
To use logarithms we should then have to find log a, log (sin B)
and log (sin A), With only a table of natural functions and a
table of logarithms at our disposal, we should have to find first
sin Ay and then log sin A. For example, ii A = 36° 20', we
would find sin 36° 20' = 0.59248, and from this would find log
sin 36° 20' = log 0.59248 = 9.77268 - 10. This double use of
tables has been made unnecessary by the direct tabulation of the
logarithms of the trigonometric functions in terms of the angles.
Such tables are called tables of logarithmic sines, logarithmic
cosines, etc. Their use is explained in any good set of tables.
The following exercises are for the purpose of familiarizing
the student with the use of such tables.
EXERCISES
1. Find the following logarithms : *
(a) log cos 27° 40'.5. (d) log ctn 86° 53'.6.
(h) log tan 85° 20'. 2. (e) log cos 87° 6'.2.
(c) logsin45°40'.7. (/) log cos 36° 53'. 3.
2. Find A^ when
(a) log sin A = 9.81632 - 10. (d) log sin A = 9.78332 - 10.
(6) log cos^ = 9.97970 - 10. (e) log ctni^ = 0.70352.
(c) log tan A = 0.45704. (/) log tan J ^ = 9.94365 - 10.
3. Find^,iftan^=^IM22L§M10.
87325
4. Given a triangle ABC, in which ZA = 32°, ZB = 27°, a = 5.2, find
6 by use of logarithms.
47. The Logarithmic Solution of Triangles. The effective
use of logarithms in numerical computation depends largely on
a proper arrangement of the work. In order to secure this,
the arrangement should be carefully planned beforehand by
constructing a blank form, which is afterwards filled in. More-
over, a practical computation is not complete until its accuracy
has been checked. The blank form should provide also for a
good check. Most computers find it advantageous to arrange
* Five-place logarithms are properly used when angles are measured to the
nearest tenth of a minute. For accuracy to the nearest second, six places
should be used.
VI, § 48] LOGARITHMIC COMPUTATION 63,
the work in two columns, the one at the left containing the
given numbers and the computed results, the one on the right
containing the logarithms of the numbers each in the same
horizontal line with its number. The work should be so
arranged that every number or logarithm that appears is
properly labeled ; for it often happens that the same number
or logarithm is used several times in the same computation and
it should be possible to locate it at a glance when it is wanted.
The solution of triangles may be conveniently classified
under four cases :
Case I. Given two angles and one side.
Case II. Given two sides and the angle opposite one of the
sides.
Case III. Given tivo sides and the included angle.
Case IV. Given the three sides.
In each case it is desirable (1) to draw a figure representing
the triangle to be solved with sufficient accuracy to serve as a
rough check on the results ; (2) to write out all the formulas
needed for the solution and the check ; (3) to prepare a blank
form for the logarithmic solution on the basis of these
formulas ; (4) to fill in the blank form and thus to complete
the solution.
We give a sample of a blank form under Case I ; the student
should prepare his own forms for the other cases.
48. Case I. Given Two Angles and One Side.
Example. Given : a = 430.17, ^ = 47° 13'.2, 5=52° 29'.5. (Fig. 37.)
To find: C, b, c.
Formulas : q
C=180°-(^ + i^),
6=—^ sin 5,
sin^
- - ^ sin C.
sin^
Check (§ 36) : £^ = t^nlJC-B)
^^ ^ c + 6 t.z,n\{C+B) ^ Fig. 37
64
PLANE TRIGONOMETRY
[VI, § 48
The following is a convenient blank form for the logarithmic solu-
tion. The sign ( + ) indicates that the numbers should be added ; the
sign (— ) indicates that the number should be subtracted from, the one
just above it.
A =
Ai- B =
C=. .
a = . .
sin A = sin
a/sin A
sin B = sin
6= . .
Numbers
179^ 60'.0
Logarithms
a/sin A
sin C = sin
c-\- b =
C- B= . ,
C+ B= . .
tan^(C— l?)i= tan
tan^(C+ 5)= tan
(-
■^) (+)
^)
-^) (+)
Check
-» (-)
(1)
(Logs (1) and (2)
►) should be equal
>■) ( — ) for check.)
(2)
FilUng in this blank form, we obtain the solution as follows.
Numbers Logarithms
A= 47°13'.2
B= 52°29\6
A-{- B= 99°42'.8
179°60'.0
C= 80° 17'. 2
a = 430.17
(-^)
2.63364
sinJl = sin 47° 13'. 2
(-»
(-) 9.86567-
10
a/sin A
2.76797
sinB = sin52°29'.6
(-»
( + ) 9.89943-
-10
b = 464.94 Ans.
C^)
2.66740
Check*
VI, § 49] LOGARITHMIC COMPUTATION 65 ,
a/sin A 2.76797
sin C = sin BOM 7 '.2 (->) (+) 9.99373 -10
c = 677.70 Ans. {<-) 2.76170
Check
c-b= 112.76 (->) 2.05215
c + 6 = 1042.64 (->) (-) 3.01813
9.03402-10]
C-B= 27M7'.6
C+ ^ = 132° 46'. 8
tan ^(C- B)= tan 13° 53'.8 (->) 9.39342 - 10
tan i ( C + ^) = tan 66° 23'. 4 (->) (-) 0.35942
9.03400-10.
EXERCISES
Solve and check the following triangles ABC :
1. a = 372.5, A = 25° 30', B = 47° 50'.
2. c =327.85, ^ = 110°52'.9, 5 = 40°31'.7. Ans. C = 28°35'.4,
a = 640.11, 6 = 445.20.
3. a = 53.276, 4 = 108° 50'.0, C = 57°13'.2.
4. 6=22.766, 5 = 141° 59'.1, C = 25° 12'.4.
5. 6 = 1000.0, J5 = 30°30'.5, C = 50°50'.8.
6. a = 257.7, ^ = 47° 25', 5 = 32° 26'.
49. Case II. Given Two Sides and an Angle Opposite
One of Them.
If A, a, b are given, B may be determined from the relation
(1) sm ^ =
a
If log sin ^ = 0, the triangle is a right triangle. Why ?
If log sin J5 > 0, the triangle is impossible. Why ?
If log sin ^ < 0, there are two possible values, Bi, B^ of B,
which are supplementary.
Hence there may be two solutions of the triangle. (See
Example.)
No confusion need arise from the various possibilities if the
corresponding figure is constructed and kept in mind.
It is desirable to go through the computation for log sin B
* A small discrepancy in the last figure need not cause concern. Why ?
F
66
PLANE TRIGONOMETRY
[VI, § 49
before making out the rest of the blank form, unless the data
obviously show what the conditions of the problem actually
are.
Example 1. Given : A = 46° 22^2, a = 1.4063, b = 2.1048. (Fig. 38.)
To find: B, C, c.
Formula: smB = ^^^.
Fig. 38
Numbers
6 = 2.1048 (-
sin ^ = sin 46^ 22'. 2 (-
bsinA
a = 1.4063 (-
sin B (-
Logarithms
0.32321
/) ( + ) 9.85962 - 10
0.18283
(-) 0.14808
-) 0.03475
Hence the triangle is impossible. Why ?
Example 2. Given : a = 73.221, b = 101.53, A = 40° 22'.3. (Fig. 39.)
To find: B, C, c.
Formula: sin^= ^^"^^ .
Logarithms
2.00660
*^) ( + ) 9.81140 - 10
Numbers
b = 101.53 (-
sin ^ = sin 40° 22'. 3 (-
6sinJL 11.81800-10
(T = 73.221 (->) (-) 1.86464
sin B 9.95336 - 10
The triangle is therefore possible and
has two solutions (as the figure shows) .
We then proceed with the solution as
follows :
We find one value Bi of B from
the value of log sin B. The other
value B2 of B is then given by B2 =
180° - J5i.
VI, § 49] LOGARITHMIC COMPUTATION 67
Other formulas :
C= 180^ -(.-l-f B).
a sin C
c =
sin A
Chbck: 'L^^'^IiiiC^^_.
c -\- b tan^(C+ B)
Numbers Logarithms
sin B 9.95336 - 10
Bi= 63°55'.2
179° 60\0
B2= 116° -i'.S
A-\- Bi = 104°17'.5
179° 60^0
Ci= 75° 42'. 5
a (~>) 1.86464
sin^ (-^) (-) 9.81140 -10
a/ sin A 2.05324
sin Ci = sin75" 42.5 (->) ( + ) 9.98634 - 10
Ci = 109.54 (<-) 2.03958
Ci-6= 8.01 (->) 0.90363
CiH- 6 = 211.07 (-^) (-) 2.32443
8.57920-10 1
Ci- Bi= 11° 47'. 3
Ci + jBi = 139° 37'.7
i
!
tanirCi - Bi)= tan5° 53'. 6 (->) 9.01377 - 10 [ ^^^^^*
tan ^( Ci + Bi) = tan 69° 48'. 8 (->) 0.43455 }
8.57922 - 10 J
One solution of the triangle gives, therefore. B = 63° 55'. 2, C = 75° 42'. 5,
c = 109.54.
To obtain the second solution, we begin with Bo = 116° 4'. 8. We find
C2 from C2 = 180° -(J. + ^2); i-e. C2 = 23° 32'. 9. The rest of the com-
putation is similar to that above and is left as an exercise.
EXERCISES
1. Show that, given A^ a, 6, if A is obtuse, or if A is acute and a > &,
there cannot be more than one solution.
Solve the following triangles and check the solutions :
2.0 = 32.479, 6 = 40.176, ^ = 37° 25M.
68
PLANE TRIGONOMETRY
tVI, § 49
3. 6 = 4168.2, c = 3179.8, B = 61°2VA.
4. a = 2.4621, 6 = 4.1347, 5 = 101° 37^3.
5. a = 421.6, c = 532.7, A = 49° 21^8.
6. a = 461.5, c = 121.2, C=22°31'.6.
7. Find the areas of the triangles in Exs. 2-5.
50. Case HI. Given Two Sides and the Included Angle.
Example. Given: a=214.17, 6=356.21,
B C = 62°21'.4. (Fig. 40.)
To find : A, B, c.
A/ \ Formulas :
Numbers
b-a = 142.04
6 -f a = 570.38
(6 - a)/(6 + a)
tan i(5 -i-A)= tan 58° 49'. 3
tani(5- J.)=tan22°22'.2
,'.A= 36°27M
B= 81°11'.5
a = 214.17
sinJ. = sin36°27M
a/sin A
sin C = sin62°21'.4
c = 319.32 Ans.
Check by finding log (6/sin B).
tan 1
(i?-^) = ^^tani(^ + ^);
6 + ci
B-{-A = 180° - C = 117° 38^6
a sin C _
sin^
Logarithms
(-»
2.15241
(-»
(-) 2.75616
9.39625 - 10
(^)
( + ) 0.21817
«~)
9.61442 - 10
J.ns.
^?is.
(->)
2.33076
(-»
(-) 9.77389-10
2.55687
(-»
( + ) 9.94736-10
(^)
2.50423
EXERCISES
Solve aud check each of the following triangles :
1. a = 74.801, 6 = 37.502, C = 63°35'.5.
2. a =423.84, 6 = 350.11, C = 43° 14'.7.
3. 6 = 275, c = 315, A = 30° 30/.
4. a =150.17, c = 251.09, jB = 40°40'.2.
5. a = 0.25089, 6 = 0.30007, C = 42° 30' 20^
6. Find the areas of the triangles in Exs. 1-5.
VI, § 51] LOGARITHIMIC COMPUTATION
69
51. Case IV. Given the Three
Sides.
Example. Given: a = 261.62,
b =: 322.42,
c = 291.48.
To find: A, B, C.
Formulas :
s= i(a+ 6 + 0-
-4
(s — g) (s — 6) (s — c)
tan ^ A :
tan J 5 :
s — a
Check : ^ + 5 + C = 180°
Numbers
a = 261.62
6 = 322.42
c ^ 291.48
2s = 875.52
s = 437.76
s - a = 176.14
s-b = 115.34
s - c = 146.28
r
tan ^ C = -
Logarithms
8 = 437.76 (Check). *(-
r2
2.24586
2.06198
( + ) 2.16518
6.47302
.^) (-) 2.64124
3.83178
r
s — a
tan J J. :
r
s-b
: tan25°4M
tan 35° 32'. 4
i<-)
«-)
r =
s — c =
tan i C = tan 29° 23 .4+ (<-)
A= 50° 8'.2 Ans.
B= 71° 4^8 ^ns.
C = 58° 46'.9 Ans.
(Check.)
1.91589
2.24586
9.67003-10
1.91589
2.06198
9.85391 - 10
1.91589
2.16518
9.75071-10
179° 59\9
*By adding s -
(§37)
-«, 5—6, 5 — C.
70 PLANE TRIGONOMETRY [VI, § 51
EXERCISES
Solve and check each of the following triangles :
1. a = 2.4169, b = 3.2417, c = 4.6293.
2. a = 21.687, b = 10.429, c = 14.221.
Z. a = 528.62, b = 499.82, c = 321.77.
4. a = 2179.1, 6 = 3467.0, = 5061.8.
5. a = 0.1214, 6 = 0.0961, c = 0.1573.
6. Eind the areas of the triangles in Exs. 1-5.
7. Find the areas of the inscribed circles of the triangles in Exs. 1-5.
OTHER LOGARITHMIC COMPUTATIONS
52. Interest and Annuities.
Simple Interest.
Let the principal be represented by F
the interest on $ 1 for one year by r
the number of years by n
the amount of P for n years by A^
Then the simple interest on P for a year is Pr
the amount of P for a year is P -\-Pr =P(l+r),
the simple interest on P for n years is Pur
the amount of P for n years is A^^ = P(l + nr).
Example. How long will it take $5 210, at 4% simple interest, to
amount to ^ 298.20 ?
An = P(l + nr) i.e. n = ^" ~ ^ .
Pr
Number Logarithm
An- P= 88.20 -^ 1.9455
Pr= 8.40 -> 0.9243
n = 10.5 <- 1.0212 10 yr. 6 mo. ^ns.
Compound Interest.
Let the original principal be P
and the rate of interest r
Then the amount A^ at the end of the first year is
A, = P-{-Pr=P(l + r),
VI, § 52] LOGARITHMIC COMPUTATION 71 ,
the amount A2 at the end of the second year is
A, = A,{1 + r) = P(l + r)^
the amount at the end of n years is
A^ = Pil + ry.
If the interest is compounded semiannually, ^„ — P[ 1 + -
if quarterly ^„ = Pf 1 + - ) , if g times a year A,^ = P( 1 -^-
\ V _ \ 9J
Since P in n years will amount to A,^, it is evident that P at
the present time may be considered as equivalent in value to
A due at the end of ii years. Hence P is called the present
worth of a given future sum A. Since
A„ = P(l + ry, P=A„il + r)-''.
Example. In how many years will one dollar double itself at 4 9^ in-
terest compounded annually ?
An = P(l + r)^ or log — " = nlog(l + r).
. ^^ logA-lQg^
log (1 + r)
Hence ^ ^log2 - logl ^ OgOlO ^ 1,,^^
log (1.04) 0.0170
17 yr. 9 mo. Ans.
AxxuiTiES. An annuity is a fixed sum of money payable
at equal intervals of time.
To find the present worth of an annuity of A dollars pay-
able annually for n years, beginning one year hence, the rate
of interest being r and the number of years n.
Since the present worth of the first payment is A(l + r)~-,
of the second ^(1 + r)~^, etc., the present worth of the whole
P=^[(l + r)-i+(l + r)-2+ ... +(l + r)-].
The quantity in the brackets is a G. P. whose ratio is (1 + r)~K
Summing, we have
l-(l+r)-i
(1 + ryj
72 PLANE TRIGONOMETRY [VI, § 52
If the annuity is perpetual, i.e. n is infinite, the formula for
present worth becomes P — —.
Example. What should be paid for an annuity of 1 100 payable an-
nually for 20 years, money being worth 4 % per annum ?
p=mi L__].
0.04 L (1.04)2oJ
By logarithms ( 1 .04) 20 = 2. 188.
Therefore P= — [l ^1 =2500 [ lil??1 =$1358, approximately.
0.04 L 2.188 J L2.I88J ^
53. Projectiles. Logarithms are used extensively in ballis-
tic computations. [Ballistics is the science of the motion of
a projectile.] The following is a very simple example of the
type of problem considered.
The time of flight of a projectile (in vacuum) is given by
the formula T=^^ ^ where X is the horizontal range
in feet, <^ is the angle of departure, and g is the acceleration
due to gravity in feet per second per second [g = 32.2]. If it
is known that the range is 3000 yd. and that the angle of de-
parture is 30° 20', find the time of flight.
T = 4
2 X tan )
9
Numbers Logarithms
2 X= 18000 -> 4.2553
tan 30° 20' -> 9.7673 - 10
4.0226
32.2 -> 1.5079
2)2.5147
18.09 <- 1.2574 r = 18.09 seconds. Ans.
EXERCISES
1. Find the amount of $ 500 in 10 years at 4 per cent compound inter-
est, compounded semiannually.
2. In how many years will a sum of money double itself at 5 per cent
interest compounded annually ? semiannually ?
VI, § 54] LOGARITHMIC COMPUTATION 73'
3. A therinoinotor bulb at a temperature of 20"^ C. is exposed to the air
for 15 seconds, in wliich time the temperature drops 4 degrees. If the
hiw of cooUng is giveu by the formuhi = ^oe~''S where 6 is the tinal tem-
perature, ^0 the initial temperature, e the natural base of logarithms, and,
t the time in seconds, find the value of b.
4. The stretch s of a brass wire when a weight m is hung at its free
end is given by the formula ^^^ j
where m is the weight applied in grams, g = 980, / is the length of the
wire in centimeters, r is the radius of the wire in centimeters, and A: is a
constant. If m = 844.9 grams, I = 200.9 centimeters, r = 0.30 centi-
meter when s = 0.056, find k.
5. The crushing weight P in pounds of a wrought-iron column is given
by the formula .73.-5
P = 299,600^^ — ,
where d is the diameter in inches and I is the length in feet. What weight
will crush a \NTOught-iron column 10 feet long and 2.7 inches in diameter?
6. The number n of vibrations per second made by a stretched string
is given by the relation -1 -^p-
2i\^'
where I is the length of the string in centimeters, 3/ is the weight in
grams that stretches the string, m the weight in grams of one centimeter
of the string, and g = 980. Find n when M = 5467.9 grams, i = 78.5
centimeters, m = 0.0065 gram.
7. The time t of oscillation of a pendulum of length I centimeters is
given by the formula — -—
>980
Find the time of oscillation of a pendulum 73.27 centimeters in length.
8. The weight w in grams of a cubic meter of aqueous vapor saturated
at 17^ C. is given by the formula
^f. ^ 1203 X 12.7 X 5
(l + iV3)(760x8)'
Compute IV.
54. The Logarithmic Scale. An arithmetic scale in which the
segments from the origin are proportional to the logarithms of 1, 2, 3, etc.,
is called a logarithmic scale. Such a scale is given in Fig. 42.
I I I 1 — I I I I I 1
1 f 3 4 5 6 7 8 9 10
Fig. 42
4
PLANE TRIGONOMETRY
[VI, §
55. The Slide Rule. The slide rule consists of a rule along the
center of which a slip of the same material slides in a groove. Along the
.1
2
1 1
1 '.T'l
5
6
7 8 9 1
1
!
^^
3
^
5
6 7 89
A ^v^
R r i ' ' '
■' 37r ^
s
R
2
3
^
5
e - e 9
-^
C ^T-r-
'■'Hi
n i' i •!-
lli|ln
1
1
2
3
4
5
6
(7
8 9
Fig. 43
upper edge of the groove are engraved two logarithmic scales, A and J5, ,
that are identical. Along the low^er edge are also two identical logarithmic
scales, G and D, in which the unit is twice that in scales A and B. Since
the segments represent the logarithms of the numbers found in the scale,
the operation of adding the segments is equivalent to multiplying the
r
1 2
3^
i I
4
1
5
6 7 8 9 1
! III!
2
1 I
A 1 ! 1 I M M ' 1 1 ' ' ■ ' ' ' i ' ''MM
^1 1 hj Ml 1 III I I lilllllii: ' . ^' I'lllilil
\ (
D ' —
i : ''lilli
\
^r
1
2
' Stt 4
5
6 7 8 9
I
c^-
! , , , 2
1 , , . , ?
/
V
1 1 ' 1
mU
T
'7
i \
^l|||||llllllllllllll|lilil!l' . • , . . r '--.i -r-!:Mi||!l|mi
Nil
1
1 1
|i
1
1
1
2
-co
1
T '
Fig. 44
corresponding numbers. Thus in Fig. 44 the point marked 1 on scale B
is set opposite the point marked 2.5 on scale A. The point marked 4 on
scale B will be opposite the point marked 10 on scale A, i.e. 2.6 x 4: = 10.
Similarly we read 2.5 x 3.2 = 8, 2.5 x 2.5 = 6.25. Other multiphcations
can be performed in an analogous manner.
Division can be performed by reversing the operation. Thus in Fig. 44
every number of scale B is the result of dividing the number above it by
2.5. Thus we read 7.2-4- 2.5 = 2.9 approximately.
Since scales C and D are twice as large as scales A and B, it follows
that the numbers in these scales are the square roots of the numbers
opposite to them in scales A and B. Conversely the numbers on scales
A and B are the squares of the numbers opposite them on scales C and
D. Moreover the scales C and D can be used for multiplying and divid-
ing, but the range of numbers is not so large. •
For a more complete discussion of the use of a sHde rule consult the
book of instructions published by any of the manufacturers of slide rules,
where also exercises will be found for practice.
CHAPTER VII
TRIGONOMETRIC RELATIONS
56. Radian Measure. In certain kinds of work it is more
convenient in measuring angles to use, instead of the degree,
a unit called the radian. A radian is defined as the angle at
the center of a circle whose subtended arc is equal in length
to the radius of the circle (Fig. 45). Therefore, if an angle
at the center of a circle of radius 7' units subtends an arc of
s units, the measure of in radians is
(1) 6 = ^.
Since the length of the whole circle is 2 7rr, it follows that
— = 2 TT radians = 360^
/•
or
(2) IT radians = 180°.
Therefore,
180° _ _
1 radian = = o<° 1/ 45" (approximately). p^^ ^-
TT
It is important to note that the radian ^ as delined is a con-
stant angle, i.e. it is the same for all circles, and can therefore
be used as a unit of measure.
From relation (2) it follows that to convert radians into
degrees it is only necessary to multiply the number of radians
by ISO/tt, while to convert degrees into radians we multiply
the number of degrees by 7r/180. Thus 45° is tt '4 radians ;
TT 2 radians is 90°.
* The symbol *" is ofteif used to denote radians. Thus 2'' stands for 2
radians, tt'' for tt radians, etc. When the angle is expressed in terms of tt (the
radian being the unit), it is customary to omit ^ Thus, when we refer to an
angle tt, we mean an angle of tt radians. AVhen the word radian is omitted,
it should be mentally supplied in order to avoid the error of supposing tt
means 180. Here, as in geometry, w = .*>. 14159. . . .
76 PLANE TRIGONOMETRY \yil, § 57
57. The Length of Arc of a Circle. Erom relation (1),
§ 56, it follows that
That is (Fig. 46), if a central angle is measured
in radians, and if its intercepted arc and the
radius of the circle are measured in terms of
the same unit, then
length of arc = radius X central angle in radians.
EXERCISES
1. Express the following angles in radians :
25°, 145°, 225°, 300°, 270°, 450°, 1150°.
2. Express in degrees the following angles :
TT TtT StT q 5 it
4' Q' Q' '4
3. A circle has a radius of 20 inches. How many radians are there in
an angle at the center subtended by an arc of 25 inches ? How many
degrees are there in this same angle ? Arts, j*" ; 71° 37' approx.
4. Find the radius of a circle in which an arc 12 inches long subtends
an angle of 35°.
5. The minute hand of a clock is 4 feet long. How far does its ex-
tremity move in 22 minutes ?
6. In how many hours is a point on the equator carried by the rotation
of the earth on its axis through a distance equal to the diameter of the earth?
7. A train is traveling at the rate of 10 miles per hour on a curve of
half a mile radius. Through what angle has it turned in one minute ?
8. A wheel 10 inches in diameter is belted to a wheel 3 inches in
diameter. If the first wheel rotates at the rate of 5 revolutions per
minute, at what rate is the second rotating ? How fast must the former
rotate in order to produce 6000 revolutions per minute in the latter ?
58. Angular Measurement in Artillery Service. The
divided circles by means of which the guns of the United States Field
Artillery are aimed are graduated neither in degrees nor in radians, but
in units called mils. The mil is defined as an angle subtended by an arc
of 6^/00 ^^ ^^^^ circumference, and is therefore equal to
2 7r 3.1416
6400 3200
= 0.00098175 =(0.001 - 0.00001825) radian.
VII, § 58] TRIGONOMETRIC RELATIONS
77
The mil is therefore approximately one thousandth of a radian.
(Hence its name.)*
Since (§57)
length of arc = radius x central angle in radians,
it follows that we have approximately
lenixth of arc :
radius
■ lOOO'
X central angle in mils ;
(angle
i.e. length of arc in yards = (radius in thousands of yards)
in mils). The error here is about 2 ^c.
Example 1. A battery occupies a front of 60 yd. If it is
at 5500 yd. rans^e, what an^jle does it subtend (Fisr. 47)? We
have, evidently, j^j^ ^j
anffle = — = 11 mils.
^ 5.5
Example 2. Indirect Fire, f A battery
posted with its right gun at G is to open fire on
a battery at a point T, distant 2000 yd. and in-
visible from G (Eig. 48) . The officer directing
the fire takes post at a point B from which both
the target T and a church spire P, distant
3000 yd. from G, are visible. B is 100 yd. at
the right of the Une G T and 120 yd. at the
right of the line GP and the officer finds by
measurement that the angle PBT contains
3145 mils. In order to train the gun on the
target the gunner must set off the angle PG T
on the sight of the piece and then move the gun
* To give an idea of the value in mils of certain angles the following has
been taken from the Drill Regulations for Field Artillery (1911), p. 164:
" Hold the hand vertically, palm outward, arm fully extended to the front.
Then the angle subtended by the
width of thumb is 40 mils
width of first finger at second joint is 40 mils
width of second finger at second joint is .... 40 mils
width of third finger at second joint is 35 mils
width of little finger at second joint is 30 mils
width of first, second, and third fingers at second joint is . 115 mils
These are average values."
t The limits of the text preclude giving more than a single illustration of
the problems arising in artillery practice. For other problems the student is
referred to the Drill Regulations for Field Artillery (1911), pp. 57, 61, 150-164 ;
and to Andrews, Fundamental of Military Service, pp. 153-159, from which
latter text the above example is taken.
78 PLANE TRIGONOMETRY [VII, § 58
until the spire P is visible through the sight. When this is effected, the
gun is aimed at T.
Let F and E be the feet of the perpendiculars from B to GT and GP
respectively, and let BT' and BP' be the parallels to GT and GP that
pass through B. Then, evidently, if the officer at B measures the angle
PB r, which would be used instead of angle PG T were the gun at B in-
stead of at G, and determines the angles TBT' = FTB and PBP' = EPB,
he can find the angle PG T from the relation
PGT = P'BT' = PBT- TBT' - PBPf.
Now tan FTB = ^,td.n EPB = ^ •
TF PE
Furthermore if FTB and EPB are small angles, i.e. if FB and EB are
small compared with G T and GP respectively, the radian measure of the
angle is approximately equal to the tangent of the angle. Why ? Hence
we have
FTB = t^n FTB =z^]
G T \
\ approximately.
EPB = tan EPB = ^^ \
GP]
Therefore TBT = FTB = J^ radians = 50 mils,
2000
PBP' = EPB = ^^ radians = 40 mils.
3000
Hence PGT = PBT - TBV - PBP'
- 3145 - 50 - 40
= 3055 mils,
which is the angle to be set off on the sight of the gun.
Hence from the situation indicated in Fig. 48 we have the following
rule :
(1) Measure in mils the angle PBT from the aiming point P to the
target T as seen at B.
(2) Measure or estimate the offsets FB and EB in yards, the range
GT and the distance GP of the aiming point P in thousands of yards.
(3) Compute in mils the offset angles by means of the relations
TBT = FTB,
PBP' = EPB,
TBT' = ^.
GT
PBP' = — .
GP
(4) Then the angle of deflection PGT is equal to the angle PBT
diminished by the sum of the offset angles.
VII, § 59] TRIGONOMETRIC RELATIONS 79
EXERCISES
1. A battery occupies a front of 80 yd. It is at 5000 yd. range.
What angle does it subtend ?
2. In Fig. 48 suppose PBT = 3000 mils, FB = 200 yd., GT = 3000 yd.,
EB = 150 yd., GP= 4000 yd. Find the number of mils in PGT.
3. A battery at a point G is ordered to take a masked position and be
ready to fire on an indicated hostile battery at a point T whose range is
known to be 2100 yd. The battery commander finds an observing station
5, 200 yd. at the right and on the prolongation of the battery front, and
175 yd. at the right of PG. An aiming point P, 5900 yd. in the rear, is
found, and PB T is found to be 2600 mils. Find PG T.
4. A battery at a point G is to fire on an invisible object at a point T
whose range is known to be 2000 yd. A battery commander finds an
observing station B, 100 yd. at the right of GT and 150 yd. at the right
of GP. The aiming point P is 1500 yd. in front and to the left of GT.
The angle TBP contains 1200 mils. Find PG T.
59. The Sine Function. Let us trace in a general way the
variation of the function sin ^ as ^ increases from 0° to 360°.
For this purpose it will be convenient to think of the distance
r as constant, from which it follows that
the locus of P is a circle. When 6 = 0°, the
point P lies on the o^-axis and hence the
ordinate is 0, i.e. sin 0° = 0/n =0. As ^
increases to 90°, the ordinate increases
until 90° is reached, when it becomes equal
to r. Therefore, sin 90° = r/r = 1. As ^ Pig. 49
increases from 90° to 180°, the ordinate de-
creases until 180° is reached, when it becomes 0. Therefore
sin 180° = 0/r = As ^ increases from 180° to 270°, the ordi-
nate of P continually decreases algebraically and reaches its
smallest algebraic value when 6 = 270°. In this position the
ordinate is — r and sin 270° = — r/r = — 1. When enters
the fourth quadrant, the ordinate of P increases (algebraically)
until the angle reaches 360°, when the ordinate becomes 0.
80
PLANE TRIGONOMETRY
[VII, § 59
Hence, sin 360° = 0. It then appears that :
as 6 increases from 0° to 90°, sin 6 increases from to 1 ;
as 6 increases from 90° to 180°, sin 6 decreases from 1 to ;
as 6 increases from 180° to 270°, sin 6 decreases from to — 1 ;
as 6 increases from 270° to 360°, sin 6 increases from — 1 to 0.
It is evident that the function sin 6 repeats its values in the
same order no matter how many times the point P moves
around the circle. We express this fact by saying that the
function sin 6 is periodic and has a period of 360°. In symbols
this is expressed by the equation
sin [0 + n . 360°] = sin 9,
where n is any positive or negative integer.
The variation of the function sin 6 is well shown by its
graph. To construct this graph proceed as follows : Take a
system of rectangular axes and construct a circle of unit radius
T
Fig. 50
with its center on the ir-axis (Fig. 50). Let angle XM^P = 6,
Then the values of sin 6 for certain values of are shown in
the unit circle as the ordinates of the end of the radius drawn
at an angle 0.
e
30^
45^^
60°
90°
sin^
3fiPi
M,P2
M^P,
M,P,
...
Now let the number of degrees in 6 be represented by dis-
tances measured along OX. At a distance that represents 30°
erect a perpendicular equal in length to sin 30° ; at a distance
VII, § 60] TRIGONOMETRIC RELATIONS
81
that represents 60° erect one equal in length to sin 60°, etc.
Through the points 0, Pi, jPo? •*• draw a smooth curve ; this
curve is the graph of the function sin 6,
If from any point P on this graph a perpendicular PQ is
drawn to the ;r-axis, then QP represents the sine of the angle
represented by the segment OQ.
Since the function is periodic, the complete graph extends
indefinitely in both directions from the origin (Fig. 51).
T
1
/'\
/\ /\
' \y
lbO\ /360^ 5iO^X
-1
y = sin X
Fig. 51
60. The Cosine Function. By arguments similar to those
used in the case of the sine function we may show that :
as 6 increases from 0° to 90°, the cos decreases from 1 to ;
as 6 increases from 90° to 180°, the cos decreases from to — 1 ;
as 9 increases from 180° to 270°, the cos increases from — 1 to ;
as increases from 270° to 360°, the cos increases from to 1.
The graph of the function is readily constructed by a method
Fig. 52
similar to that used in the case of the sine function. This is
illustrated in Fig. 52.
The complete graph of the cosine function, like that of the
sine function, will extend indefinitely from the origin in both
82
PLANE TRIGONOMETRY
[VII, § 60
directions (Fig. 53). Moreover cos^, like sin^, i'^ periodic and
has a period of 360°, i.e.
cos [9 + n-360°]= cos 9,
where n is any positive or negative integer.
7
1
^^ /^
A /^^
Vy °
\/ \'^
-1
y=t'Osa:
Fig. 53
61. The Tangent Function. In order to trace the varia-
tion of the tangent function, consider a circle of unit radius
with its center at the origin of a system of rectangular axes
(Fig. 54). Then construct the tangent to
this circle at the point M(l, 0) and let P
denote any point on this tangent line. If
angle MOP= 0, we have tan 6 = MP/OM
= MP /I = MP, i.e. the line MP represents
tan 6.
Now when 6 = 0°, MP is 0, i.e. tan 0° is 0.
As the angle increases, tan 6 increases. As
approaches 90° as a limit, 3IP becomes
infinite, i.e. tan 6 becomes larger than any number whatever.
At 90° the tangent is undefined. It is sometimes convenient
to express this fact by writing
tan 90° =00.
However we must remember that this is not a definition for
tan 90°, for oo is not a number. This is merely a short way of
saying that as approaches 90° tan becomes infinite and
that at 90° tan is undefined.
Thus far we have assumed 6 to be an acute angle approach-
ing 90° as a limit. Now let us start with as an obtuse angle
Fig. 54
VII, § on
TRIGONOMETRIC RI^.ATIONS
83
and let it decrease towards 90° as a limit. In Fig. ryB the line
MP' (which is here negative in direction) represents tan 6,
Arguing precisely as we did before, it is
seen that as the angle 6 aj)proaches 90°
as a limit, tan again increases in magni-
tude beyond all bounds, i,e. becomes inh-
nite, remaining, however, always negative.
We then have the following results.
(1) When 6 is acute and increases to-
wards 90° as a limit, tan always remains
positive but becomes infinite. At 90° tan is undefined.
(2) When 9 is obtuse and decreases towards 90° as a limit,
tan always remains negative but becomes infinite. At 90°
tan is undefined.
It is left as an exercise to finish tracing the variation of the
tangent function as varies from 90° to 360°. Note that
tan 270°, like tan 90°, is undefined. In fact tan n • 90° is unde-
fined, if n is any odd integer.
Fig.
Fig. 5G
To construct the graph of the function tan we proceed
along lines similar to those used in constructing the graph of
sin and cos 0. The following table together with Fig. 50
illustrates the method.
84
PLANE TRIGONOMETRY
[\1I, § 61
e
0°
30°
45°
60°
90°
120°
135°
150°
180°
210°
tan^
MPi
MP2
MP^
undefined
MP^
MP^
MP^
JfP7 =
MPi
It is important to notice that tan 6, like sin 6 and cos d^ is
periodic, but its period is 180°. That is
tan(e + n • 180°)= tan e,
where n is any positive or negative integer.
EXERCISES
1. What is meant by the period of a trigonometric function ?
2. What is the period of sin d ? cos 6 ? tan d ?
3. Is sin 6 defined for all angles ? cos d ?
4. Explain why tan 6 is undefined for certain angles. Kame four
angles for which it is undefined. Are there any others ?
5. Is sin (<9 + 360°) = sin 6 ?
6. Is sin (^+ 180°) = sin 6*?
7. Is tan (^ + 180°) = tan d ?
8. Is tan (0 + 360°) = tan^ ?
Draw the graphs of the following functions and explain how from the
graph you can tell the period of the function :
9. sin^. 11. tan^. 13. sec ^.
10. cos (9. 12. csc^. 14. ctn6>.
Verify the following statements :
15. sin90° + sin270° = 0. 18. cos 180° + sin 180° =- 1.
16. cos90° + sin0° = 0. 19. tan 360° + cos 360° = 1.
17. tanl80° + cosl80°=- 1. 20. cos 90° + tan 180°- sin 270° = !.'
21. Draw the graphs of the functions sin 6, cos 6, tan 6, making use of
a table of natural functions. See p. 112.
22. Draw the curves y = 2smd ; y = 2cose ; y = 2 tan d.
23. Draw the curve y = sin 6 + cos 6.
24. From the graphs determine values of 6 for which sin 6 = ^ ; sin ^
= 1 ; tan ^ = 1 ; cos ^ = J ; cos ^ = 1.
VII, § 63] TRIGONOMETRIC RELATIONS
85
62. The Trigonometric Functions of — 9. Draw the angles
6 and — 6, where OP is the terminal line of 6 and OP is the
terminal line of — 6. Figure 57 shows an angle 6 in each of
Fig 57
the four quadrants. We shall choose OP = OP and (.r, y) as
the coordinates of P and (x\ y') as the coordinates of P', In
all four figures
x' = x, 2/' = - y, r' = r.
Hence
, ^/' -. — V.
sin (-6')^
: — sin ^,
cos(-6>)
— = - = cos 0^
v' r
tan (-6*)--^
■ = — tan 0,
Also,
csc(— ^)=— csc(9 ; sec(— ^)= sec^ ; ctn (— ^)= — ctn^.
The above results can be stated as follows : The functions of
— 6 equal numerically the like named functions of 0. The
algebraic sign, however, will be opposite except for the cosine
and secant.
Example. sin-10^=— sinlO'', cos— 10^ = cos10'', tan— 10^= -tan 10°.
63. The Trigonometric Functions of 180° + 0. Similarly,
the following relations hold :
sin (180° + (9) = - sin 6, esc (180° + ^) = - esc (9,
cos (180° + (9) = - cos e, sec (180° -{-0)=- sec (9,
tan (180° + (9) = tan (9, ctn (180° -h 0) = ctn 0.
The proof is left as an exercise.
86 PLANE TRIGONOMETRY [VII, § 64
64. Summary. An inspection of the results of §§ 27-28,
62-63 shows :
1. Each function of — or 180"^ ± 6 is equal in absolute value
(but not always in sign) to the same function of 0.
2. Each function of 90° — is equal in magnitude and in sign
to the corresponding co function of 6.
These principles enable us to find the value of any function
of any angle in terms of a function of a positive acute angle
(not greater than 45° if desired) as the following examples
show.
Example 1. Beduce cos 200° to a function of an angle less than 45°.
Since 200° is in the third quadrant, cos 200° is negative. Hence
cos 200° = - cos 20°. Why ?
Example 2. Reduce tan 260° to a function of an angle less than 45°.
Since 260° is in the third quadrant, tan 260° is positive. Hence
tan 260° = tan 80° = ctn 10° (§ 27).
Example 3. Reduce sin (— 210°) to a function of a positive angle
less than 45°.
From § 62 we know sin — 210° = — sin 210°.
Considering the positive angle 210°, we have
sin - 210° = - sin 210° = - [ - sin 30°] = sin 30°.
EXERCISES
Reduce to a function of an angle not greater than 45° :
1. sin 163°. 5. esc 901°.
2. cos(-110°). 6. ctn(~1215°).
Ans, -sin 20°. 7. tan 840°.
3. sec (-265°). 8. sin 510°.
4. tan 428°.
Find without the use of tables the values of the following functions :
9. cos 570°. 11. tan 390°. 13. cos 150°.
10. sin 330°. 12. sin 420°. 14. tan 300°.
Reduce the following to functions of positive acute angles :
15. sin 250°. 18. sec (-245°).
Ans. — sin 70° or — cos 20°. 19. csc(— 321°).
16. cos 158°. 20. sin 269°.
17. tan (-389°).
VII, § 64] TRIGONOMETRIC RELATIONS 87
Prove the following relations from a figure :
(«) sin (90" + ^)=cos^.
(c)
sin (180° + ^) = -sin6>.
cos (90'^ + e) = - sin d.
cos (180° +6) = — cos^'.
tan (90^ + 0) = - ctn d.
tan (180° + 0)= tan (9.
csc(90° + 6>)=sec^.
CSC(180° + ^):=- csc^.
sec (90^ + d) = - CSC e.
sec (180° + 6) = -sec 6.
ctn (90^ -{-$) = — tan d.
ctn (180° + 0)=z ctn^.
(b) sin (180'='- 6/)=sin^.
(d)
sin (270° -(9) = — cos (9.
cos (180^-^) = -cos (9.
cos (270° — $) = - sin 6.
tan (180° - 6') = -tan6>.
tan (270° — 6)= ctn 0.
CSC (180^-^)= csc^.
CSC (270°-^) = -sec (9.
sec (180^- ^) = - sec^.
sec (270°— 0) = -csc0.
Ctn (180^-^) = - ctn^.
ctn (270° -6)= tan 0.
(e) sin (270°
+ e):
= —
cos^.
cos (270°
+ 6):
= sin 6.
tan (270°
+ e):
= —
ctn^.
CSC (270°
+ e):
= -
sec^.
sec (270°
+ e):
= CSC 6.
ctn (270° + ^) = — tan^.
CHAPTER YIII
TRIGONOMETRIC RELATIONS (Continued)
65. Trigonometric Equations. An identity, as we have
seen (§ 26), is an equality between two expressions which is
satisfied for all values of the variables for which both expres-
sions are defined. If the equality is not satisfied for all
values of the variables for which each side is defined, it is
called a conditional equality, or simply an equation. Thus
1 — cos ^ = is true only ii = n - 360°, where n is an integer.
To solve a trigonometric equation, i.e. to find the values of
for which the equality is true, we usually proceed as follows.
1. Express all the trigonometric functions involved in terms
of one trigonometric function of the sa^ne angle.
2. Find the value (or values) of this function by ordinary
algebraic methods.
3. Find the angles between 0° and 360° which correspond to
the values found. These angles are called particular solutions.
4. Give the general solution by adding n • 360°, where n is
any integer, to the particular solutions.
Example 1. Find 6 when sin 6 = I.
The particular solutions are 30° and 150*^. The general solutions are
30° + n . 360°, 150° + n - 360°.
Example 2. Solve the equation tan ^ sin ^ — sin ^ = 0.
Factoring the expression, we have sin ^(tan ^ — 1) = 0. Hence we
have sin ^ = 0, or tan ^—1 = 0. Why ?
The particular solutions are therefore 0°, 180°, 45°, 225°. The general
solutions are n • 360°, 180° -f n • 360^ 45° + ^ • 360°, 225° + n • 360°.
88
1.
2
2.
2 ^
3.
2
4.
2
5.
tan^ =—1.
6.
ctn<9 = 1.
16.
2 sin ^ = tan 0,
VIII, § 66] TRIGONOMETRIC RELATIONS 89
EXERCISES
Give the particular and tlie general solutions of the following
equations :
V3 . 7. sec ^ = 2.
8. tan ^ = 0.
9. sec2(? = 2.
10. sin2 6 = 1.
11. cos^=— J.
12. csc2 d = f .
13. 4 sin ^ — 3 CSC ^ = 0.
14. 2sin^cos2^ = sin^.
15. cos $ -f sec ^ = f .
Ans. Particular solutions : 0", 180°, 60°, 300°.
17. 3 sin ^ + 2 cos ^ = 2. 18. 2 cos2 ^ — 1 = 1 _ sin2 6.
66. Inverse Trigonometric Functions. The equation
X = sin y (1)
may be read :
y is an angle whose sine is equal to x,
a statement which is usually written in the contracted form
y = arc sin x* (2)
For example, x = sin 30° means that x = ^, wliile y = arc sin ^
means that y = 30°, 150°, or in general (n being an integer),
30° + 71 ' 360° ; 150° + n • 360°.
Since the sine is never greater than 1 and never less than
— 1, it follows that — 1 ^ x ^ 1. It is evident that there is
an unlimited number of values oi y = arc sin x for a given value
of X in this interval.
We shall now define the principal value Arc sin a; f of arc sin x,
distinguished from arc sin x by the use of the capital A, to be
* Sometimes written y = sin -i x. Here — 1 is not an algebraic exponent,
but merely a part of a functional symbol. When we wish to raise sin x to
the power — 1, we write (sin x)-^.
t Sometimes written Sin-i x, distinguished from sin-i x by the use of the
capital S.
90
PLANE TRIGONOMETRY
[VIII, § 66
the numerically smallest angle whose sine is equal to x. This func-
tion like arc sin a? is defined only for those values of x for
which
The difference between arc sin a; and Arc sin a? is well illus-
trated by means of their graph. It is
evident that the graph oi y = arc sin x,
i.e, X = sin y is simply the sine curve
with the role of the x and y axes inter-
changed. (See Fig. 58.) Then for every
admissible value of x, there is an un-
limited number of values of y ; namely,
the ordinates of all the points Pi, Po, •••, in
which a line at a distance x and parallel
to the ?/-axis intersects the curve. The
single-valued function Arc sin x is repre-
sented by the part of the graph between
IT and N.
Similarly arc cos x, defined as " an angle whose cosine is x/^
has an unlimited number of values for
every admissible value ofa;(— l^x
y
K
-1
y
^
Tx'
M
(
IT
2
y^ arc sin x
y=
=j.>
c sin X
Fig. 58
Y
^TT
)
STT
i
iV
(:
TT
2
■v.
\
M
-1
IT
1 X
y= arc cos x
y=Arc cos X
Fig. 59
symbols arc ctnoj; arc seca^; arc esc a;.
The principal values of all the inverse trigonometric functions
are given in the following table.
VIII, § 66] TRIGONOMETRIC RELATIONS
91
y =
Arc sin x
Arc cosx
Arc tan x
Range of x
-l^x^ 1
-l^x^l
all real values
Range of y
-!Lto^
2 2
to TT
to —
2 2
X positive
X negative
1st Quad.
4th Quad.
1st Quad.
2d Quad.
1st Quad.
4th Quad.
Arc ctnx
Arc sec x
Arc CSC X
Range of x
all values
x^lorx^— 1
x^l orx^"— 1
Range of y
to TT
to TT
to -
2 2
X positive
X negative
1st Quad.
2d Quad.
1st Quad.
2d Quad.
1st Quad.
4th Quad.
In so far as is possible we select the principal value of each
inverse function, and its range, so that the function is single-
valued, continuous, and takes on all possible values. This ob-
viously cannot be done for the Arc sec x and for Arc esc y.
(/) Arc cos -^.
EXERCISES
1. Explain the difference between arc sin x and Arc sin x.
2. Find the values of the follow^ing expressions :
(a) Arc sin J. (d) Arc tan — 1.
(b) arc sin J. . . V3
^ ^ ^ (e) arc cos -^.
(c) arc tan 1. 2
3. What is meant by the angle tt ? 7r/4 ?
4. Through how many radians does the minute hand of a watch turn
in 30 minutes ? in one hour ? in one and one half hours ?
6. For what values of x are the following functions defined :
(a) arc sin x ? (c) arc tan x ? (e) arc sec x ?
(b) arc cos x ? (d) arc ctn x ? (/) arc esc x ?
6. What is the range of values of the functions :
(a) Arc sin x ? (c) Arc tan x ? (e) Arc sec x.
(h) Arc cos X ? (.
Through A draw a line q^ parallel to q and with the same
direction. [It is evident that we may assume without loss of
generality that q is horizontal and is directed to the right.]
Let A^B^ be the projection of AB on q and let BB^ meet qi
in ^1. Then by the definition of the cosine we have
AB
-—^ = cos (qip) — cos (pQ'i) = cos (gp) = cos {pq)
AB
* (P^) represents an angle through which p may be rotated in order to
make its direction coincide with the direction of q ; similarly for {qp).
94 PLANE TRIGONOMETRY [VIII, § 67
in magnitude and sign. Hence
ABi = AB • cos (pg) = AB ■ cos (qp).
But AB, = A'B' = proj^ AB.
Therefore proj^ AB = AB • cos (pp) = AB • cos (gjp).
Case 2. Suppose AB is negative.
If AB is negative, BA is positive and We have from Case 1,
B'A' = BA • cos (pq)= BA • cos (qp).
Changing the signs of both members of this equation, we have
A^B' = AB • cos (pg)= AB • cos (qp).
The special cases 1, 2, 3, are obtained from formula (1)
by placing (qj:)) or (pq) equal to 0°, 180°, 90° respectively.
Theorem. If A, B, C are any three points in a plane, a.nd I
is any directed line in the p)lane, the algebraic sum of the projec-
tions of the segments AB and BC on I is equal to the projection
of the segment AC on I.
As a point traces out the path from A to JB, and then from
B to C (Eig. 62), the projection of the point traces out the
segments from ^' to -B' and then from B^
to O. The net result of this motion is a
motion from A^ to O which represents
the projection of AC, i.e.
AB^ + B'C = A'C\
EXERCISES
1. What is the projection of a Hue segment upon a hne Z, if the hne
segment is perpendicular to the hne I ?
2. Find iproj^. AB and projy J.^^ in each of the following cases, if a
denotes the angle from the x-axis to AB.
(a) AB = 5, a = 60°. (c) AB = 6, a = 90°.
(b) AB = 10, a = 300°. (d) AB = 20, a = 210°.
* Projx ^B and projy AB mean the projections of AB on the a:-axis and
the 2/-axis, respectively.
VIII, § 68] TRIGONOMETRIC RELATIONS
95
3. Prove by means of projection that in a triangle ABC
a = b cos C -\- c cos B. .
4. If projj AB = 3 and proj^ AB =—4, find the length of AB.
5. A steamer is going northeast 20 miles per hour. How fast is it
going north ? going east ?
6. A 20 lb. block is sliding down a 15° incline. Find what force
acting directly up the plane will just hold the block, allowing one half a
pound for friction.
7. Prove that if the sides of a polygon are projected in order upon any
given line, the sum of these projections is zero.
r>
P.
•^
N^
/
■^"^
p
xF
~
y
X'
X
r
X
68. The Addition Formulas. We may now derive formulas
for sin (a + jS), cos (a + /3), and tan (a + /S) in terms of func-
tions of a and /3. To this end
let F (x, y) be any point on the
terminal side of the angle a (the
initial side being along the posi-
tive end of the a^-axis and the
vertex being at the origin). The
angle a -{- (3 is then obtained by
rotating OP through an angle
)8. If P'{x', y') is the new posi- Fig. 68
tion P after this rotation and
OP = OP' = r, we have sin (« + m = ^, cos (a + i^) = - , by
r r
definition. Our first problem is, therefore, to find x^ and y' in
terms of x, y, and /3.
In the figure OJWP is the new position of the triangle OMP
after rotating it about through the angle p. Now,
x^ = proj^ OP' = proj, OJf ' + proj^ M'P
= a;cos^ + 2/cos/'^ + |^
= x cos /3 — y sin ^.
96 PLANE TRIGONOMETRY [VIII, § 68
Similarly,
y' = proj, OP' = proj, OM' + proj, M'P'
(it ^
\2 )
= X sin P + y cos fi<
Hence, • / , m v' ^ • o . V ^
' sm (a + ^) = -^ = - sm ^ 4- ^ cos B
TV r
or (1) sin (a + P) = sin a cos p + cos a sin p.
Also
cos (a + p) =~=z- cos /? — ^ sin /J.
r r r
or (2) cos (a H- p) = cos a cos p — sin a sin p.
Further we have
tan (a + 8)= ^^^ (^ + P) = sin a cos ^ + cos « sin ^8 ,
cos (a + y8) cos a cos ji — sin a sin ji
Dividing numerator and denominator by cos a cos )8, we have
(3) tan(a+B)= tana + tanp
^ ^ V -r p; i_tanatanp
Furthermore, by replacing yS by — ^ in (1), (2), and (3), and
recalling that
sin (— 13) =— sin jS, cos (— /3) = cos JS, tan (— y8) = — tan ^,
we obtain
(4) sin (a — P) = sin a cos p — cos a sin p,
(5) cos (a — P) = cos a cos p + sin a sin p,
(6) tan (a - p) = tana- tan p
^ ^ ^ *^^ 1 + tan a tan p
EXERCISES
Expand the following :
1. sin (45° -\-a)= 3. cos (60° + «) = 5. sin (30° - 45°) =
2. tan (30°-^)= 4. tan (45° + 60°) = 6. cos (180° - 45°) =
7. What do the following formulas become if a = /3 ?
sin (a + p)= sin a cos /3 + cos a sin /3o . fa A- 3^— ^^^ ^ + ^^^ i^ .
sin (06 — j8) = sin a cos |8 — cos a sin /3. 1 — tan a tan /3
cos(a + /3)= coscccos j8 — sin a sin/?. , . ^x_ tanoc — tanj8 ^
cos (a — j3) = cos a cos /3 + sin a sin /3. 1 + tan a tan ^
VIII, § 68] TRIGONOMETRIC RELATIONS 97
8. Complete the following formulas :
sin 2 a cos a -f cos 2 a sin a = tan 2 a + tanoc _
9.
sin 3 a cos a — cos 3 a sin a = 1 — tan 2 a tan a
Prove sin 75° = V|^ ^ ^^^ ^^o ^ V3- 1 ^ ^^^ 750 ^ V3 + 1
: sm a.
2\/2 2V2 V3-1
10. Given tan a = J, sin ^3 = j\, and a and j3 both positive acute angles,
find the value of tan (a + ^) ; sin (a — /3) ; cos (a + /3) ; tan (a — /3).
11. Prove that
(a) cos (60° + a) + sin (30° + a) = cos a.
(6) sin (60° + I?)- sin (60° -6) = sin 6>.
(c) cos (30° + )- cos (30° - ^) = - sin 6.
(d) cos (45° + d)+ cos (45° - 1?) = \/2 • cos ^.
(e) sin^a+|Wsin^a-|^:
(/) cos [« + -)+ cos (a--\ = \^S' cos a.
(a) tan(45° + 0= ^ +tan^ ^ ,^. tan (45° - 6>)= ^ " ^^^^ .'
^^ ^ ^ l-tan6> ^ ^ ^ ^ l+tani?
12. By using the functions of 60° and 30° find the value of sin 90° ;
cos 90°.
13. Find in radical form the value of sin 15° ; cos 15° ; tan 15° ;
sin 105° ; cos 105° ; tan 105°.
14. If tan a = f , sin /3 = y\, and a is in the third quadrant while /3 is
in the second, find sin (a ± ^); cos (« ± ^) ; tan (a ± /3).
Prove the following identities :
- - sin (a + /3) _ tan a + tan ^ ^ ^^ sin 2 a , cos 2 a _ gjv, s /v
sin(a — /3) tana — tan j3 * sec a esc a
^^ tancc-tan(ce-/3) ^ ^^^ ^ 19. (^) sin (i80° - $) = sin 0.
1 4- tan a tan (a-^) (5) cos (180° -$) = - cos d.
18. tan(^±45°) + ctn(6>T45°)=0. (c) tan (180° - ^) = - tan (9.
20. cos (a + /3) cos (a — /3) = cos2 a — sin2 j3.
21. sin (a -\- /3) sin (a — j3) = sin2 a - sin2 ^.
22. ctn(a + ^) = "^^^^^^^-^. 23. ctn (« - « = ^^^^.^^^^^±1 .
ctn a + ctn /8 ctn j8 — ctn a
24. Prove Arc tan ^ + Arc tan i = 7r/4.
[Hint : Let Arc tan ^ = x and Arc tan ^ = y. Then we wish to prove
X + 1/ = 7r/4, which is true since tan (x + y)= l.~\
25. Prove Arc sin a + Arc cos a=:-ifO
cos 2 d, tan 2 ^.
Prove the following identities ;
7. sin2a=^i^^^. 9. sec2« = - "^'^'^
1 + tan2 a csc2 a — 2
o o 1 — tan2 a 4
7738
7443
7520
7597
7672
7745
7451
7528
7604
7679
7752
7459
7536
7612
7686
7760
74()6
7543
7619
7694
7767
7474
7551
7()27
7701
7774
1 2 2
12 2
1 1 2
112
112
3 4 5
3. 4 5
3 4 5
3 4 4
3 4 4
5 6 7
5 6 7
6 6 7
5 6 7
5 6 7
60
7782
7789
7796
7803
7810
7818
7825
7832
7839
7846
1 1 2
3 4 4
5 6 6
61
62
63
64
65
67
68
69
7853
7924
7993
8062
8129
8195
8261
8325
8388
7860
7931
8000
8069
8136
8202
8267
8331
8395
7868
7938
8007
8075
8142
8209
8274
8338
8401
7875
7M5
8014
8082
8149
8215
8280
8344
8407
7882
7952
8021
8089
8156
8222
8287
8351
8414
7889
7959
8028
8096
8162
8228
8293
8357
8420
7896
1966
8035
8102
8169
8235
8299
8363
8426
7903 7910! 7917
7973 7980,7987
8041 8048| 8055
8109 8116' 8122
8176, 8182 8189
8241 8248 8254
8306* 8312 8319
8370; 8376 8382
8432 8439 8445
112
112
112
112
1 1 2
112
112
1 1 2
1 1 2
3 3 4
3 3 4
3 3 4
3 3 4
3 3 4
3 3 4
3 3 4
3 3 4
3 3 4
5 6 6
5 5 6
5 5 6
5 5 6
5 5 6
5 5 6
5 5 6
4 5 6
4 5 6
70
8451
^57 1 8463' 8470|
8476
8482
8488
849418500 8506
1 1 2
3 3 4
4 5 6
71
72
73
74
75
76
77
78 >
79'
8513
8573
8633
8692
8751
8808
8865
8921
8976
8519
8579
8639
8698
8756
8814
8871
8927
8982
8525
8585
8645
8704
8762
8820
8876
8932
8987
8531
8591
8651
8710
8768
8825
8882
8938
8993
8537
8597
8657
8716
8774
8831
8887
8943
8998
8543
8603
8663
8722
8779
8837
8893
8949
9004
8549
8609
8669
8727
8785
8842
8899
8954
9009
8555' 8561 8567
8615' 8621 8627
8675, 8681 8686
8733 8739 8745
8791 8797,8802
8848 8854, 8859
8904 8910' 8915
89(30 8965 8971
9015 9020 9025
112
1 1 2
112
112
112
112
1 1 2
1 1 2
112
3 3 4
3 3 4
2 3 4
2 3 4
2 3 3
2 3 3
2 3 3
2 3 3
2 3 3
4 5 6
4 5 6
4 5 5
4 5 5
4 5 5
4 4 5
4 4 5
4 4 5
4 4 5
80
V)031
9036
9042! 9047
9053
9058
9063
9069 9074 9079
112
2 3 3
4 4 5
81
82
83
84
85
86
87
88
89
908,5
9138
9191
19243
19294
9345
9395
9445
9494
9090
9143
9196
9248
9299
9350
9400
9450
9499
909(3
9149
9201
9253
9304
9355
9405
9455
9504
9101
9154
9206
9258
9309
9360
^10
9460
9509
9106
9159
9212
9263
9315
9365
9415
9465
9513
9112
9165
9217
9269
9320
9370
9420
9469
9518
9117
9170
9222
9274
9325
9375
9425
9474
9523
9122
9175
9227
9279
9330
9380
9430
9479
9528
9128
9180
9232
9284
9335
9385
9435
9484
9533
9133
9186
9238
9289
9340
9390
9440
9489
9538
112
112
112
112
112
1 1 2
112
Oil
1 1
2 3 3
2 3 3
2 3 3
2 3 3
2 3 3
2 3 3
2 3 3
2 2 3
2 2 3
4 4 5
4 4 5
4 4 5
4 4 5
4 4 5
4 4 5
4 4 5
3 4 4
3 4 4
90
9542
9547
9552
9557
9562
9566
9571
9576
9581
9586
Oil
2 2 3
3 4 4
91
92
93
94
95
96
97
98
99
9590
9638
9685
9731
i9777
9823
9868
9912
9956
9595
9f)43
9689
9736
9782
9827
9872
9917
9961
9600
9647
9694
9741
9786
9832
9877
9921
9965
9605
9652
9699
9745
9791
9836
9881
9926
19969
9609
9657
9703
9750
9795
9841
9886
9930
9974
9614
9661
9708
9754
9800
9845
9890
9934
9978
9619
9666
9713
9759
9805
9850
9894
9939
9983
9624
9671
9717
9763
9809
9854
9899
9943
9^)87
9628
9675
9722
9768
9814
9859
9903
9948
9991
9633
9680
9727
9773
9818
9863
9908
9952
9996
Oil
1 1
1 1
1 1
1 1
1 1
Oil
1 1
1 1
2 2 3
2 2 3
2 2 3
2 2 3
2 2 3
2 2 3
2 2 3
2 2 3
2 2 3
3 4 4
3 4 4
3 4 4
3 4 4
3 4 4
3 4 4
3 4 4
3 3 4
3 3 4
N '
1
2
3
4
5
6
7
8
9
12 3
4 5 6
7 8 9
jng the proportional part corresponding to the fourth figure to the tabular number
corresponding to the ^st three figures. There may he an error of 1 in the last place.
112
Four Place Trigonometric Functions
[Characteristics of Logarithms omitted —
determine by the usual rule from the value]
Radians
Deg-rees
Sine
Tangent
Cotangent
Cosine
XV.AJ^X^Vx^ o
-M^ JZiXjfJJmXU-MiiiJ
Value
Logio
Value Logio
Value
Logio
Value
Log-io
.0000
.0029
0°00'
10
.0000
.0029
0000
1.0000
.0000
90° 00'
50
1.5708
1.5679
.4637
.0029 .4637
343.77
.5363
LOOOO
'.0000
.0058
20
.0058
.7648
.0058 .7648
171.89
.2352
1.0000
.0000
40
1.5650
.0087
30
.0087
.9408
.0087 .9409
114.59
.0591
i.ooa)
.0000
30
1.5621
.0116
40
.0116
.0658
.0116 .0658
85.940
.9342
.9999
.0000
20
1.5592
.0145
50
.0145
.1627
.0145 .1627
68.750
.8373
.9999
.0000
10
1.5563
.0175
1^00'
.0175
.2419
.0175 .2419
57.290
.7581
.9998
.9999
89° 00'
1.5533
.0204
10
.0204
.3088
.0204 .3089
49.104
.6911
.9998
.9999
50
1.5504
.0233
20
.0233
.3668
.0233 .3669
42.964
.6331
.9997
.9999
40
1.5475
.0262
30
.0262
.4179
.0262 .4181
38.188
.5819
.9997
.9999
30
1.5446
.0291
40
.0291
.4637
.0291 .4638
34.368
.5362
.9996
.9998
20
1.5417
.0320
50
.0320
.5050
.0320 .5053
31.242
.4947
.9995
.9998
10
1.5388
.0349
2^00'
.0349
.5428
.0349 .5431
28.636
.4569
.9994
.9997
88° 00
1.5359
.0378
10
.0378
.5776
.0378 .5779
26.432
.4221
.9993
.9997
50
1.5330
.0407
20
.0407
.6097
.0407 .6101
24.542
.3899
.9992
.9996
40
1.5301
.0436
30
.0436
.6397
.0437 .6401
22.904
.3599
.99^)0
.9996
30
1.5272
.0465
40
.0465
.6677
.0466 .6682
21.470
.3338
.9989
.9995
20
1.5243
.0495
50
.0494
.6940
.0495 .6945
20.206
.3055
.9988
.9995
10
1.5213
.0524
3^00'
.0523
.7188
.0524 .7194
19.081
.2806
.9986
.9994
87° 00'
1.5184
.0553
10
.0552
.7423
.0553 .7429
18.075
.2571
.9985
.9993
50
1.5155
.0582
20
.0581
.7645
.0582 .7652
17.169
.2348
.9983
.9993
40
1.5126
.0611
30
.0610
.7857
.0612 .7865
16.350
.2135
.9981
.9992
30
1.5097
.0640
40
.0640
.8059
.0641 .8067
15.605
.1933
.9980
.9991
20
1.5068
.0669
50
.0669
.8251
.0670 .8261
14.924
.1739
.9978
.9990
10
1.5039
.0698
4° 00'
.0698
.843()
.0699 .8446
14.301
.1554
.9976
.9989
86° 00
1.5010
.0727
10
.0727
.8613
.0729. .8624
13.727
.1376
.9974
.9989
50
1.4981
.0756
20
.0756
.8783
.0758 .8795
13.197
.1205
.9971
.9988
40
1.4952
.0785
30
.0785
.8946
.0787 .8%0
12.706
.1040
.9969
.9987
30
1.4923
.0814
40
.0814
.9104
.0816 .9118
12.251
.0882
.9967
.9986
20
1.4893
.0844
50
.0843
.9256
.0846 .9272
11.826
.0728
.9964
.9985
10
1.4864
.0873
5^00'
.0872
.9403
.0875 .9420
11.430
.0580
.9962
.9983
85° 00'
1.4835
.0902
10
.0901
.9545
.0904 .9563
11.059
.0437
.9959
.9982
50
1.4806
.0931
20
.0929
.9682
.0934 .9701
10.712
.0299
.9957
.9981
40
1.4777
.0960
30
.0958
.9816
.0963 .9836
10.385
.0164
.9954
.9980
30
1.4748
.0989
40
.0987
.9945
.0992 .9966
10.078
.0034
.9951
.9979
20
1.4719
.1018
50
.1016
.0070
.1022 .0093
9.7882
.9907
.9948
.9977
10
1.4690
.1047
6° 00'
.1045
.0192
.1051 .0216
9.5144
.9784
.9945
.9976
84° 00'
1.4661
.1076
10
.1074
.0311
.1080 .0336
9.2553
.9664
.9942
.9975
50
1.4632
.1105
20
.1103
.0426
.1110 .0453
9.0098
.9547
.9939
.9973
40
1.4603
.1134
30
.1132
.0539
.1139 .0567
8.7769
.9433
.9936
.9972
30
1.4573
.1164
40
.1161
.0648
.1169 .0678
8.5555
.9322
.9932
.9971
20
1.4544
.1193
50
.1190
.0755
.1198 .0786
8.3450
.9214
.9929
.9969
10
1.4515
.1222
7° 00'
.1219
.0859
.1228 .0891
8.1443
.9109
.9925
.9968
83° 00'
1.4486
.1251
10
.1248
.0961
.1257 .0995
7.9530
.9005
.9922
.9966
50
1.4457
.1280
20
.1276
.1060
.1287 .109(5
7.7704
.8904
.9918
.9964
40
1.4428
.1309
30
.1305
.1157
.1317 .1194
7.5958
.8806
.9914
.9963
30
1.4399
.1338
40
.1334
.1252
.1346 .1291
7.4287
.8709
.9911
.9961
20
1.4370
.1367
50
.1363
.1345
.1376 .1385
7.2687
.8615
.9907
.9959
10
1.4341
.1396
8° 00'
.1392
.1436
.1405 .1478
7.1154
.8522
.9903
.9958
82° 00'
1.4312
.1425
10
.1421
.1525
.1435 .1569
6.9682
.8431
.9899
.9f)56
50
1.4283
.1454
20
.1449
.1612
.1465 .1658
6.8269
.8342
.9894
.9954
40
1.4254
.1484
30
.1478
.1697
.1495 .1745
6.6912
.8255
.9890
.9952
30
1.4224
.1513
40
.1507
.1781
.1524 .1831
6.5606
.8169
.9886
.9950
20
1.4195
.1542
50
.1536
.1863
.1554 .1915
6.4348
.8085
.9881
.9948
10
1.4166
.1571
9^00'
.1564
.1943
.1584 .1997
6.3138
.8003
.9877
.9946
81° 00'
1.4137
Value
Lo?io
Value Loff^o
Value
Logio
Value
Logio
Degrees
Radians
1
Cosine
Cotangent
Tangent
Sine
Four Place Trigonometric Functions 113
[Cbaractoristics of Loirarithras omitted — determine by the usual rule from the value]
Radians
Degrees
Si.
SE
Tangent
COTAN
GENT
Cosine
Value
Logio
Value
Logio
Value
1-ogio
Value Logio
.1571
9^00
.1564
.1943
.15S4
.1997
6.3138
.8003
.9877 .9946
81^00'
1.4137
.KMX)
10
.1593
.2022
.1614
.2078
6.1970
.7922
.9872 .9944
50
1.4108
.1(529
20
.1622
.2100
.1(>44
.2158
6.0844
.7842
.9868 .9942
40
1.4079
.IimS
30
.1650
.217()
.1673
.223()
5.9758
.77(>4
.9863 .9940
30
1.4050
.U>87
40
.1(>79
.2251
.1703
.2313
5.8708
.7687
.9858 .9938
20
1.4021
.1716
50
.1708
.2324
.1733
.2389
5.7694
.7611
.9853 .9936
10
1.3992
.1745
10^00
.1736
.2397
.1763
.2463
5.6713
.7537
.9848 .9934
80° 00'
1.3963
.1774
10
.1765
.2468
.1793
.2536
5.5764
.7464
.9^43 .9931
50
1.3934
.1804
20
.171U
.25:38
.1823
.2609
5.4845
.7391
.9838 .9929
40
1.3904
.1833
30
.1822
.2606
.1853
.2680
5.3955
.7320
.9833 .9927
30
1.3875
.18!)2
40
.1851
.2674
.1883
.2750
5.3093
.7250
.9827 .9924
20
1.3846
.1891
50
.1880
.2740
.1914
.2819
5.2257
.7181
.9822 .9922
10
1.3817
.1920
11^00
.1908
.2806
.1944
.2887
5.1446
.7113
.9816 .9919
79° 00'
1.3788
.15U9
10
.1937
.2870
.1974
.2953
5.0658
.7047
.9811 .9917
50
1.3759
.1978
20
.1965
.2934
.2004
.3020
4.9894
.6980
.9805 .9914
40
1.3730
.2007
30
.1994
.2<)97
.2035
.3085
4.9152
.6915
.9799 .9912
30
1.3701
.2036
40
.2022
.3058
.2065
.3149 4.8430
.6851
.9793 .9909
20
1.3672
.2065
50
.2051
.3119
.2095
.3212 j 4.7729
.6788
.9787 .9907
10
1.3643
.2094
12^00
.2079
.3179
.2126
.3275 4.7046
.6725
.9781 .9904
78^00'
1.3614
.2123
10
.2108
.32:38
.2156
.3336 4.6382
.6664
.9775 .9901
50
1.3584
.2153
20
.21:36
.3296
.2186
.3397
4.5736
.6603
.9769 .9899
40
1.3555
.2182
30
.21(>4
.3353
.2217
.3458
4.5107
.6542
.9763 .9896
30
1.3526
.2211
40
.2193
.3410
.2247
.3517
4.4494
.6483
.9757 .9893
20
1.3497
.2240
50
.2221
.3466
.2278
.3576
4.3897
.6424
.9750 .9890
10
1.3468
.2269
13^00
.2250
.3521
.2309
.3634
4.3315
.6366
.9744 .9887
77° 00'
1.3439
.2298
10
.2278
.3575
.2339
.3691
4.2747
.6309
.9737 .9884
50
1.3410
.2327
20
.2306
.3629
.2370
.3748
4.2193
.6252
.9730 =9881
40
1.3381
!235(j
30
.2334
.3682
.2401
.3804
4.1653
.6196
.9724 .9878
30
1.3352
.2385
40
.2363
.3734
.2432
.3859 i 4.1126
.6141
.9717 .9875
20
1.3323
.2414
50
.2391
.3786
.2462
.3914
4.0611
.6086
.9710 .9872
10
1.3294
.2443
14^00'
.2419
.3837
.2493
.3968
4.0108
.6032
.9703 .9869
76° 00'
1.3265
.2473
10
.2447
.3887
.2524
.4021
3.9(317
.5979
.9696 .9866
50
1.3235
.2502
20
.2476
.3937
.2555
.4074
3.9136
.5926 1 .9689 .9863
40
1.3206
.2531
30
.2504
.3986
.2586
.4127
3.8667
.5873 1 .9681 .9859
30
1.3177
.25<'30
40
.2.532
.4035 .2617
.4178
3.8208
.5822 .9674 .9856
20
1.3148
.2589
50
.2560
.4083
.2(>48
.4230
3.7760
.5770 .9667 .9853
10
1.3119
.2618
15^00
.2588
.4130
.2679
.4281
3.7321
.5719 .9659 .9849
75° 00'
1.3090
.2647
10
.2616
.4177
.2711
.4331
3.6891
.5669 .9652 .9846
50
1.3061
.2676
20
.2644
.4223
.2742
.4381
3.6470
.5619 .9644 .9843
40
1.3032
.2705
30
.2672
.4269
.2773
.4430
3.6059
.5570 .9636 .9839
30
1.3003
.2734
40
.2100
.4314
.2805
.4479
3.5656
.5521
.9628 .9836
20
1.2974
.2763
50
.2728
.4359
.2836
.4527
3.5261
.5473
.9621 .9832
10
1.2945
.2793
16^00
.2756
.4403
.2867
.4575
3.4874
.5425
.9613 .9828
74° 00'
1.2915
.2822
10
.2784
.4447
.2899
.4622
3.4495
.5378
.9605 .9825
50
1.2886
.2851
20
.2812
.4491
.2931
.46()9
3.4124
.5331 .9596 .9821
40
1.2857
.28.80
30
.2840
.4533
.2962
.4716
3.3759
.5284
.9588 .9817
30
1.2828
.2^)r)9
40
.28(38
.4576
.2994
.4762
3.3402
.5238
.9580 .9814
20
1.2799
.29:38
50
.2896
.4618
.3026
.4808
3.3052
.5192
.9572 .9810
10
1.2770
.2967
17^00'
.2924
.4659
.3057
.4853
3.2709
.5147
.9563 .9806
73° 00'
1.2741
.29r>6
10
.2952
.4700
.3089
.4898 i 3.2371
.5102 i .9555 .9802
50
1.2712
.3025
20
.2979
.4741
..3121
.4943 3.2041
.5057 1 .9546 .9798
40
1.2683
.3054
30
.3007
.4781
.3153
.4987
3.1716
.,5013
.9537 .9794
30
1.2654
.3083
40
..3o:r>
.4821
.3ia5
..5031
's.w.n
.4969
.9528 .9790
20
1.2625
.3113
5i)
.30()2
.4861
.;3217
.5075
3.10^
.4925
.9520 .978*3
10
1.2595
.3142
18^00'
.3090
.4900
.3249
.5118
3.0777
.4882
.9511 .9782
72° 00'
1.2566
Value
Lo^io
Value
Loerio
Value
Loi?io
Value LojTio
Degrees
Radians
Cosine
Cotangent
Tangent
Sine
114 Four Place Trigonometric Functions
[Characteristics of Logarithms omitted — determine by the usual rule from the value]
Radtans
Deq-eees
Sine
Tangent
Cotangent | Cosine
A^VJi.XJ±t*.X^ fj
j_^ Jl/VTXWJH XjO
7alue
Logio
Value
Logio
Value
Logio
Value
Logio
.3142
18° 00'
.3090
.4900
.3249
.5118
3.0777
.4882
.9511
.9782
72° 00'
1.2566
.3171
10
.3118
.4939
.3281
.5161
3.0475
.4839
.9502
.9778
50
1.2537
.3200
20
.3145
.4977
.3314
.5203
3.0178
.4797
.9492
.9774
40
1.2508
.3229
30
.3173
.5015
.3346
.5245
2.9887
.4755
.9483
.9770
30
1.2479
.3258
40
.3201
.5052
.3378
.5287
2.9600
.4713
.9474
.9765
20
1.2450
.3287
50
.3228
.5090
.3411
.5329
2.9319
.4671
.9465
.9761
10
1.2421
.3316
19^00'
.3256
.5126
.3443
.5370
2.9042
.4630
.9455
.9757
71° 00'
1.2392
,3345
10
.3283
.5163
.3476
.5411
2.8770
.4589
.9446
.9752
60
1.2363
.3374
20
.3311
.5199
.3508
.5451
2.8502
.4549
.9436
.9748
40
1.2334
.3403
30
.3338
.5235
.3541
.5491
2.8239
.4509
.9426
.9743
30
1.2305
.3432
40
.3365
.5270
.3574
.5531
2.7980
.4469
.9417
.9739
20
1.2275
.3462
50
.3393
.5306
.3607
.5571
2.7725
.4429
.9407
.9734
10
1.2246
.3491
20° 00'
.3420
.5341
.3640
.5611
2.7475
.4389
.9397
.9730
70° 00'
1.2217
.3520
10
.3448
.5375
.3673
.5650
2.7228
.4350
.9387
.9725
50
1.2188
.3549
20
.3475
.5409
.3706
.5689
2.6985
.4311
.9377
.9721
40
1.2159
.3578
30
.3502
.5443
.3739
.5727
2.6746
.4273
.9367
.9716
30
1.2130
.3607
40
.3529
.5477
.3772
.5766
2.6511
.4234
.9356
.9711
20
1.2101
.3636
50
.3557
.5510
.3805
.5804
2.6279
.4196
.9346
.9706
10
1.2072
.3665
21° 00'
.3584
.5543
.3839
.5842
2.6051
.4158
.9336
,9702
69° 00'
1.2043
.3694
10
.3611
.5576
.3872
.5879
2.5826
.4121
.9325
.9697
50
1.2014
.3723
20
.3638
.5609
.3906
.5917
2.5605
.4083
.9315
.9692
40
1.1985
.3752
30
.3665
.5641
.3939
.5954
2.5386
.4046
.9304
.9687
30
1.1956
.3782
40
.3692
.5673
.3973
.5991
2.5172
.4009
.9293
.9682
20
1.1926
.3811
50
.3719
.5704
.4006
.6028
2.4960
.3972
.9283
.9677
10
1.1897
.3840
22° 00'
.3746
.5736
.4040
.6064
2.4751
.3936
.9272
.9672
68° 00'
1.1868
.3869
10
.3773
.5767
.4074
.6100
2.4545
.3900
.9261
.9667
50
1.1839
.3898
20
.3800
.5798
.4108
.6136
2.4342
.3864
.9250
.9661
40
1.1810
.3927
30
.3827
.5828
.4142
.6172
2.4142
.3828
.9239
.9656
30
1.1781
.3956
40
.3854
.5859
.4176
.6208
2.3945
.3792
.9228
.9651
20
1.1752
.3985
50
.3881
.5889
.4210
.6243
2.3750
.3757
.9216
.9646
10
1.1723
.4014
23° 00'
.3907
.5919
.4245
.6279
2.3559
.3721
.9205
.9640
67° 00'
1.1694
.4043
10
.3934
.5948
.4279
.6314
2.3369
.3686
.9194
.9635
50
1.1665
.4072
20
.3961
.5978
.4314
.6348
2,3183
.3652
.9182
.9629
40
1.1636
.4102
30
.3987
.6007
.4348
.6383
2.2998
.3617
.9171
.9624
30
1.1606
.4131
40
.4014
.6036
.4383
.6417
2.2817
.3583
.9159
.9618
20
1.1577
.4160
50
.4041
.6065
.4417
.6452
2.2637
.3548
.9147
.9613
10
1.1548
.4189
24° 00'
.4067
.6093
.4452
.6486
2.2460
.3514
.9135
.9607
66° 00'
1.1519
.4218
10
.4094
.6121
.4487
.6520
2.2286
.3480
.9124
.9602
50
1.1490
.4247
20
.4120
.6149
.4522
.6553
2.2113
.3447
.9112
.9596
40
1.1461
.4276
30
.4147
.6177
.4557
.6587
2.1943
.3413
.9100
.9590
30
1.1432
.4305
40
.4173
.6205
.4592
.6620
2.1775
.3380
.9088
.9584
20
1.1403
.4334
50
.4200
.6232
.4628
.6654
2.1609
.3346
.9075
.9579
10
1.1374
.4363
25° 00'
.4226
.6259
.4663
.6687
2.1445
.3313
.9063
.9573
65° 00'
1.1345
.4392
10
.4253
.6286
.4699
.6720
2.1283
.3280
.9051
.9567
50
1.1316
.4422
20
.4279
.6313
.4734
.6752
2.1123
.3248
.9038
.9561
40
1.1286
.4451
30
.4305
.6340
.4770
.6785
2.0965
.3215
.9026
.9555
30
1.1257
.4480
40
.4331
.6366
.4806
.6817
2.0809
.3183
.9013
.9549
20
1.1228
.4509
50
.4358
.6392
.4841
.6850
2.0655
.3150
.9001
.9543
10
1.1199
.4538
26° 00'
.4384
.6418
.4877
.6882
2.0503
.3118
.8988
.9537
64° 00'
1.1170
.4567
10
.4410
.6444
.4913
.6914
2.0353
.3086
.8975
.9530
50
1.1141
.4596
20
.4436
.6470
.4950
.6946
2.0204
.3054
.8962
.9524
40
1.1112
.4625
30
.4462
.6495
.4986
.6977
2.0057
.3023
.8949
.9518
30
1.1083
.4654
40
.4488
.6521
.5022
.7009
1.9912
.2991
.8936
.9512
20
1.1054
.4683
50
.4514
.6546
.5059
.7040
1.9768
.2960
.8923
.9505
10
1.1025
.4712
27° 00'
.4540
.6570
.5095
.7072
1.9626
.2928
.8910
.9499
63° 00'
1.0996
Value
Logio
Value
Logio
Value
Logio
Value
Logio
Degrees
Radians
Cosine
Cotangent
Tangent
Sine |
Four Place Trigonometric Functions
115
[Characteristics of Logarithms omitted — determine by the usual rule from the value]
Padiavs
DFaRFKS
Sine
Tange>-t 1 Cotangent | Cosine
i^i:.(jrax.li>9
Value
Logio
Value
Logio Value Logir. \'alue Logio
.4712
27° 00
.4540
.6570
.5095
.7072 1.9626 .2928
.8910 .9499
63° 00'
1.0996
.4741
10
.4566
.6595
.5i:)2
.7103 1.94S6 .2897
.8897 .9492
50
1.0966
.4771
20
.4592
.6620
.5169
.7134
1.9347 .2866
.8884 .9486
40
1.0937
.4800
30
.4617
.6644
.5206
.7165
1.9210 .2835
.8870 .9479
30
1.0908
.4829
40
.4643
.66i\S
.5243
.7196
1.9074 .2804
.8857 .947:^
20
1.0879
.4858
50
.4669
.6692
.5280
.7226
1.8940 .2774
.8843 .9466
10
1.0850
.4887
28^00'
.4695
.6716
.5317
.7257
1.8807 .2743
.8829 .9459
62° 00
1.0821
.4016
10
.4720
.6740
.5354
.7287
1.8676 .2713
.8816 .94.53
50
1.0792
.4945
20
.4746
.6763
.5392
.7317 \ 1.8546 .2683
.8802 .9446
40
1.0703
.4974
30
.4772
.6787
.5430
.7348 1.8418 .2652
.8788 .94:39
30
1.0734
.5003
40
.4797
.6810
.5467
.7378
1.8291 .2622
.8774 .94-32
20
1.0705
.5032
50
.4823
.6833
.5505
.7408
1.8165 .2592
.8760 .9425
10
1.0676
.5061
29° 00'
.4848
.6856
.5543
.7438
1.8040 .2562
.8746 .9418
61° 00'
1.0647
.5091
10
.4874
.6878
.5581
.7467 1.7917 .2533 ! .8752 .9411
50
1.0617
.5120
20
.4899
.6901
.5619
.7497 1.7796 .2503 ' .8718 .9404
40
1.0.588
.5149
30
.4924
.6923
.5658
.7526
1.7675 .2474 .8704 .9397
30
1.0559
.5178
40
.4950
.6946
.5696
.7556
1.75.56 .2444 .8(389 .9.390
20
1.05.30
.5207
50
.4975
.6968
.5735
.7585
1.7437 .2415 .8675 .9383
10
1.0501
.5236
30° 00'
.5000
mm
.5774
.7614
1.7321 .2386 .8660 .9375
60° 00'
1.0472
.5265
10
.5025
.7012
.5812
.7644
1.7205 .2356 .8646 .9368
50
1.0443
.5294
20
.5050
.7033
.5851
.7673
1.7090 .2327 ■ .8631 .9361
40
1.0414
.5323
30
.5075
.7055
.5890
.7701
1.6977 .2299 : .8616 .9353
30
1.0385
.5352
40
.5100
.7076
.5930
.7730 1.6864 .2270 ' .8601 .9346
20
1.0356
.5381
50
.5125
.7097
.5969
.7759
1.6753 .2241 .8587 .93-38
10
1.0327
.5411
31°00'
.5150
.7118
.6009
.7788
1.6643 .2212 .8572 .9331
59° 00'
1.0297
.5440
10
.5175
.7139
.6048
.7816
1.6534 .2184 .8557 .9323
50
1.0268
.5469
20
.5200
.7160
.6088
.7845 1.6426 .2155 , .8542 .9315
40
1.02:39
.5498
30
.5225
.7181
.6128
.7873 i 1.6319 .2127 : .8526 .9.308
30
1.0210
.5527
40
.5250
.7201
.6168
.7902
1.6212 .2098 ' .8511 .9300
20
1.0181
.5556
50
.5275
.7222
.6208
.7930
1.6107 .2070 .8496 .9292
10
1.0152
.5585
32° 00'
.5299
.7242
.6249
.7958
1.6003 .2042 .8480 .9284
58° 00'
1.0123
.5614
10
.5324
.7262
.6289
.7986
1.5900 .2014 \ .8465 .9276
50
1.0094
.5643
20
.5:348
.7282
.6330
.8014
1.5798 .1986 i .8450 .9268
40
1.0065
.5672
30
.5373
.7302
.6371
.8042
1.5697 .1958 .84-34 .9260
30
1.003()
.5701
40
.5398
.7322
.6412
.8070
1.5597 .1930 .8418 .9252
20
1.0007
.5730
50
.5422
.7342
.6453
.8097
1.5497 .1903 1.8403 .9244
10
.9977
.5760
33° 00'
.5446
.7361
.6494
.8125
1.5-399 .1875 .8387 .92-36
57°00'
.9948
.5789
10
.5471
.7380
.6536
.8153
1.5:301 .1847 .8-371 .9228
50
.9919
.5818
20
.5495
.7400
.6577
.8180
1.5204 .1820 .8:355 .9219
40
.9890
.5847
30
.5519
.7419
.6619
.8208
1.5108 .1792 .83:39 .9211
30
.9861
.587()
40
.5544
.7438 1 .6661
.8235
1.5013 .1765 .8-323 .9203
20
.98-32
.5905
50
.5568
.7457
.6703
.8263
1.4919 .1737 .8307 .9194
10
.9803
.5934
34° 00'
.5592
.7476
.6745
.8290
1.4826 .1710 .8290 .9186
56° 00'
.9774
.5963
10
.5616
.7494
.6787
.8317
1.4733 .1683 | .8274 .9177
50
.9745
.5992
20
.5640
.7513
.6830
.8344
1.4641 .1656! .8258' .9169
40
.9716
.6021
30
.5604
.7531
.6873
.8371 ! 1.4550 .1629 i .8241 .9160
30
.9687
.6050
40
.5688
.7550
.6916
.8398 1.4460 .1602 .8225 .9151
20
.9()57
.6080
50
.5712
.7568
.6959
.8425 1.4370 .1575 j .8208 .9142
10
.9628
.6109
35° 00'
.5736
.7586
.7002
.8452 1.4281 .1548 ' .8192 .9134
55° 00'
.9599
.6138
10
.5760
.7604
.7046
.8479 1.4193 .1521 .8175 .9125
50
.9570
.6167
20
.5783
.7622
.7089
.85(J6 1 1.4106 .1494 .8158 .9116
40
.9541
.6196
30
.5807
.7640
.7133
.8533
1.4019 .1467 .8141 .9107
30
.9512
.6225
40
.5831
.7657
.7177
.8.559
1.3934 .1441
.8124 .9098
20
.9483
.6254
50
.5854
.7675
.7221
.8586
1.3^8 .1414
.8107 .9089
10
.9454
.6283
36° 00'
.5878
.7692
.7265
.8613 ' 1.3764 .1387 ' .8090 .9080
54° 00'
.9425
Value
Logio
Value
LoETio' Value Logjo! Value Logio
Degbees
Radians
COR'INE
Cotangent i Tangent ( Sine
116 Four Place Trigonometric Functions
[Characteristics of Logarithms omitted — determine by the usual rule from the value]
"Radians
DEG-RKEft
Sine
Tangent
Cotangent
Cosine
■LWXVA'X.clb.X^ O
JU' .Cl VT X« JU •>» E7
7alue Logic
Value Logic
Value Logic
Value Logic
.6283
36^^00'
.5878 .7682
.7265 .8613
1.3764 .1387
.8090 .9080
64° 00'
.9425
.6312
10
.5901 .7710
.7310 .8639
1.3680 .13(31
.8073 .9070
50
.9396
.6341
20
.5925 .7727
.7355 .8666
1.3597 .1334
.8056 .9061
40
.9367
.6370
30
.5948 .7744
.7400 .8692
1.3514 .1308
.8039 .9052
30
.9338
.6400
40
.5972 .7761
.7445 .8718
1.3432 .1282
.8021 .9042
20
.9308
.6429
50
.5995 .7778
.7490 .8745
1.3351 .1255
.8004 .9033
10
.9279
.6458
37° 00'
.6018 .7795
.7536 .8771
1.3270 .1229
.7986 .9023
63° 00'
.9250
.6487
10
.6041 .7811
.7581 .8797
1.3190 .1203
.7969 .9014
50
.9221
.6516
20
.6065 .7828
.7627 .8824
1.3111 .1176
.7951 .9004
40
.9192
.6545
30
.6088 .7844
.7673 .8850
1.3032 .1150
.7934 .8995
30
.9163
.6574
40
.6111 .7861
.7720 .8876
1.2954 .1124
.7916 .8985
20
.9134
.6603
50
.6134 .7877
.7766 .8902
1.2876 .1098
.7898 .8975
10
.9105
.6632
38° 00'
.6157 .7893
.7813 .8928
1.2799 .1072
.7880 .8965
52° 00'
.9076
.6661
10
.6180 .7910
.7860 .8954
1.2723 .1046
.7862 .8955
50
.9047
.6690
20
.6202 .7926
.7907 .8980
1.2647 .1020
.7844 .8945
40
.9018
.6720
30
.6225 .7941
.7954 .9006
1.2572 .0994
.7826 .8935
30
.8988
.6749
40
.6248 .7957
.8002 .V)032
1.2497 .0968
.7808 .8925
20
.8959
.6778
50
.6271 .7973
.8050 .9058
1.2423 .0942
.7790 .8915
10
.8930
.6807
39° 00'
.6293 .7989
.8098 .9084
1.2349 .0916
.7771 .8905
51°00'
.8901
.6836
10
.6316 .8004
.8146 .9110
1.2276 .0890
.7753 .8895
50
.8872
.6865
20
.6338 .8020
.8195 .9135
1.2203 .0865
.7735 .8884
40
.8843
.6894
30
.6361 .8035
.8243 .9161
1.2131 .0839
.7716 .8874
30
.8814
.6923
40
.6383 .8050
.8292 .9187
1.2059 .0813
.7698 .8864
20
.8785
.6952
50
.6406 .8066
.8342 .9212
1.1988 .0788
.7679 .8853
10
.8756
.6981
40° 00'
.6428 .8081
.8391 .9238
1.1918 .0762
.7660 .8843
50° 00'
.8727
.7010
10
.6450 .8096
.8441 .9264
1.1847 .0736
.7642 .8832
50
.8698
.7039
20
.6472 .8111
.8491 .9289
1.1778 .0711
.7623 .8821
40
.8668
.7069
30
.6494 .8125
.8541 .9315
1.1708 .0685
.7604 .8810
30
.8639
.7098
40
.6517 .8140
.8591 .9341
1.1640 .0659
.7585 .8800
20
.8610
.7127
50
.6539 .8155
.8642 .9366
1.1571 .0634
.7566 .8789
10
.8581
.7156
41° 00'
.6561 .8169
.8693 .9392
1.1504 .0(^8
.7547 .8778
49° 00'
.8552
.7185
10
.6583 .8184
.8744 .9417
1.1436 .0583
.7528 .8767
50
.8523
.7214
20
.6604 .8198
.8796 .9443
1.1369 .0557
.7509 .8756
40
.8494
.7243
30
.6626 .8213
.8847 .9468
1.1303 .0532
.7490 .8745
30
.8465
.7272
40
.6648 .8227
.8899 .9494
1.1237 .0506
.7470 .8733
20
.8436
.7301
50
.6670 .8241
.8952 .9519
1.1171 .0481
.7451 .8722
10
.8407
.7330
42° 00
.6691 .8255
.9004 .9544
1.1106 .0456
.7431 .8711
48° 00'
.8378
.7359
10
.6713 .8269
.9057 .9570
1.1041 .0430
.7412 .8699
50
.8348
.7389
20
.6734 .8283
.9110 .9595
1.0977 .0405
.7392 .8688
40
.8319
.7418
30
.6756 .8297
.9163 .9621
1.0913 .0379
.7373 .8676
30
.8290
.7447
40
.6777 .8311
.9217 .9646
1.0850 .0354
.7353 .8665
20
.8261
.7476
50
.6799 .8324
.9271 .9671
1.0786 .0329
.7333 .8653
10
.8232
.7505
43° 00'
.6820 .8338
.9325 .9697
1.0724 .0303
.7314 .8641
47° 00'
.8203
.7534
10
.6841 .8351
.9380 .9722
1.0661 .0278
.7294 .8629
50
.8174
.7563
20
.6862 .8365
.9435 .9747
1.0599 .0253
.7274 .8618
40
.8145
.7592
30
.6884 .8378
.9490 .9772
1.0538 .0228
.7254 .8606
30
.8116
.7621
40
.6905 .8391
.9545 .9798
1.0477 .0202
.7234 .8594
20
.8087
.7650
50
.6926 .8405
.9601 .9823
1.0416 .0177
.7214 .8582
10
.8058
.7679
44° 00'
.6947 .8418
.9657 .9848
1.0355 .0152
.7193 .8569
46° 00'
.8029
.7709
10
.6967 .8431
.9713 .9874
1.0295 .0126
.7173 .8557
50
.7999
.7738
20
.6988 .8444
.9770 .9899
1.0235 .0101
.7153 .8545
40
.7970
.7767
30
.7009 .8457
.9827 .9924
1.0176 .0076
.7133 .8532
30
.7941
.7796
40
.7030 .8469
.9884 .9949
1.0117 .0051
.7112 .8520
20
.7912
.7825
50
.7050 .8482
.9942 .9975
1.0058 .0025
.7092 .8507
10
.7883
.7854
45° 00'
.7071 .8495
1.0000 .0000
1.0000 .0000
.7071 .8495
45° 00'
.7854
Value Logio
Value Logio
Value Logio
Value Logio
Degrees
Jadians
Cosine
Cotangent
Tangent
Sine
Values aud Logtirithius of Haversines
117
[Characteristics ^
:>{ Logarithms omitted -
— determine by rule from the value]
0'
10' 1
20'
3C
'
40'
oC
)'
Value
Logio
\alue
I^ogio
Value
Log,o
Value
Logio
Value
Log,o
Value
Logjo
.0000
.0000 4.3254
.0000 4.9275
.0000 t
).2796
.0000 5.5295
.0001 5.7233 1
1
.0001 5.8817
.0001 6.0156
.0001 6.1315
.0002
.2338
.0002
.3254
.0003
.4081
2
.0003
.4837
.0004
.5532
.0004
.6176
.0005
.6775
.0005
.7336
.0006
.7862
3
.0007
.8358
.0008
.8828
.0008
.9273
.0009
.9697
.0010
.0101
.0011
.0487
4
.0012
.0856
.0013
.1211
.0014
.1551
.0015
.1879
.0017
.2195
.0018
.2499
5
.0019
.2793
.0020
.3078
.0022
.3354
.0023
.3621
.0024
.3880
.0026
.4132
6
.0027
.4376
.0029
.4614
.0031
.4845
.0032
.5071
.0034
.5290
.0036
.5504
7
.0037
.5713
.0039
.5918
.0041
.6117
.0043
.6312
.0045
.6503
.0047
.6689
S
.0049
.6872
.0051
.7051
.0053
.7226
.0055
.7397
.0057
.7566
.0059
.7731
9
.0062
.7893
.0064
.8052
.0066
.8208
.0069
.8361
.0071
.8512
.0073
.8660
10
.0076
.8806
.0079
.8949
.0081
.9090
.0084
.9229
.0086
.9365
.0089
.9499
11
.0092
.9631
.0095
.9762
.0097
.9^90
.0100
.0016
.0103
.0141
.0106
.0264
12
.0109
.0385
.0112
.0504
.0115
.0622
.0119
.073b
.0122
.0853
.0125
.0966
13
.0128
.1077
.0131
.1187
.0135
.1296
.0138
.1404
.0142
.1510
.0145
.1614
U
.0149
.1718
.0152
.1820
.0156
.1921
.0159
.2021
.0163
.2120
.0167
.2218
15
.0170
.2314
.0174
.2409
.0178
.2504
.0182
.2597
.0186
.2689
.0190
.2781
16
.0194
.2871
.0198
.2961
.0202
.3049
.0206
.3137
.0210
.3223
.0214
.3309
17
.0218
.3394
.0223
.3478
.0227
.3561
.0231
.3644
.0236
.3726
.0240
.3806
IS
.0245
.3887
.0249
.3966
.0254
.4045
.0258
.4123
.0263
.4200
.0268
.4276
19
.0272
.4352
.0277
.4427
.0282
.4502
.0287
.4576
.0292
.4649
.0297
.4721
20
.0302
.4793
.0307
.4865
.0312
.4936
.0317
.5006
.0322
.5075
.0327
.5144
21
.0332
.5213
.0337
.5281
.0343
.5348
.0348
.5415
.0353
.5481
.0359
.5547
22
.0364
.5612
.0370
.5677
.0375
.5741
.0381
.5805
.0386
.5868
.0392
.5931
23
.0397
.5993
.0403
.6055
.0409
.6116
.0415
.6177
.0421
.6238
.0426
.6298
24
.0432
.6357
.0438
.6417
.0444
.6476
.0450
.6534
.0456
.6592
.0462
.6650
25
.0468
.6707
.0475
.6764
.0481
.6820
.0487
.6876
.0493
.6932
.0500
.6987
26
.0506
.7042
.0512
.7096
.0519
.7151
.0525
.7204
.0532
.7258
.0538
.7311
27
.0545
.7364
.0552
.7416
.0558
.7468
.0565
.7520
.0572
.7572
.0578
.7623
28
.0585
.7673
.0592
.7724
.0599
.7774
.0606
.7824
.0613
.7874
.0620
.7923
29
.0627
.7972
.0634
.8020
.0641
.8069
.0648
.8117
.0655
.8165
.0663
.8213
30
.0670
.8260
.0677
.8307
.0684
.8354
.0692
.8400
.0699
.8446
.0707
.8492
31
.0714
.8538
.0722
.8583
.0729
.8629
.0737
.8673
.0744
.8718
.0752
.8763
32
.0760
.8807
.0767
.8851
.0775
.8894
.0783
.8938
.0791
.8981
.0799
.9024
33
.0807
.9067
.0815
.9109
.0823
.9152
.0831
.9194
.0839
.9236
.0847
.9277
34
.0855
.9319
.0863
.9360
.0871
.9401
.0879
.9442
.0888
.9482
.0896
.9523
35
.0904
.9563
.0913
.9603
.0921
.9643
.0929
.9682
.0938
.9722
.0946
.9761
36
.0955
.9800
.0963
.9838
.0972
.9877
.0981
.9915
.0989
.9954
.0998
.9992
37
.1007
.0030
.1016
.0067
.1024
.0105
.1033
.0142
.1042
.0179
.1051
.0216
38
.1060
.0253
.1069
.0289
.1078
.0326
.1087
.0362
.1096
.0398
.1105
.0434
39
.1114
.0470
.1123
.0505
.1133
.0541
.1142
.0576
.1151
.0611
.1160
.0646
40
.1170
.0681
.1179
.0716
.1189
.0750
.1198
.0784
.1207
.0817
.1217
.0853
41
.1226
.08b7
.1236
.0920
.1246
.0954
.1255
.0987
.1265
.1021
.1275
.1054
42
.1284
.1087
.1294
.1119
.1304
.1152
.1314
.1185
.1323
.1217
.1333
.1249
43
.1343
.1282
.1353
.1314
.1363
.1345
.1373
.1377
.1383
.1409
.1393
.1440
44
.1403
.1472
.1413
.1503
.1424
.1534
.1434
.1565
.1444
.1596
.1454
.1626
45
.1464
.1657
.1475
.1687
.1485
.1718
.1495
.1748
.1506
.1778
.1516
.1808
46
.1527
.1838
.1538
.1867
.1548
.1897
.1558
.1926
.1569
.1956
.1579
.1985
47
.1590
.2014
.1600
.2043
.1611
.2072
.1622
.2101
.1633
.2129
.1644
.2158
48
.1654
.2186
.1665
.2215
.1676
.2243
.1687
.2271
.1698
.2299
.1709
.2327
49
.1720
.2355^ 1731
.2382
.1742
.2410
.1753
.2437
.1764
.2465
.1775
.2492
50
.1786
.2519
.1797
.2546
.1808
.2573
.1820
.2600
.1831
.2627
.1842
.2653
51
.1853
.2680
.1S65
.2706
.1876
.2732
.1887
.2759
.1899
.2785
.1910
.2811
52
.1922
.2837
.1933
.2863
.1945
.2888
.1956
.2914
.1968
.2940
.1979
.2965
53
.1991
.2991
.2003
.3016
.2014
.3041
.2026
.3066
.2038
.3091
.2049
.3116
54
.2061
.3141
.2073
.3166
.2085
.3190
.2096
.3215
.2108
.3239
.2120
.3264
55
.2132
.3288
' .2144
.3312
.2156
.3336
.2168
.3361
.2180
.3384
.2192
.3408
56
.2204
.3432
.2216
.3456
.2228
.3480
.2240
.3503
.2252
.3527
.2265
.3550
57
.2277
.3573
.2289
.3596
.2301
.3620
.2314
.3643
.2326
.3666
.2338
.3689
58
.2350
.3711
.2363
.3734
.2375
.3757
.2388
.3779
.2400
.3802
.2412
.3824
59
.2425
.3847
.2437
.3869
.2450
.3891
.2462
.3913
.2475
.3935
.2487
.3957
118 Values and Logarithms of Haversines
[Characteristics of Logarithms omitted — determine by rule from the value]
o
'
10'
20'
30'
40'
50'
Value
Logjo
Value
Logio
Value
Logio
Value
Logio
Value
Logio
Value
I^ogio
60
.2500
.3979
.2513
.4001
.2525
.4023
.2538
.4045
.2551
.4066
.2563
.4088
61
.2576
.4109
.2589
.4131
.2601
.4152
.2614
.4173
.2627
.4195
.2640
.4216
62
.2653
.4237
.2665
.4258
.2678
.4279
.2691
.4300
.2704
.4320
.2717
.4341
63
.2730
.4362
.2743
.4382
.2756
.4403
.2769
.4423
.2782
.4444
.2795
.4464
64
.2808
.4484
.2821
.4504
.2834
.4524
.2847
.4545
.2861
.4565
.2874
.4584
65
.2887
.4604
,2900
.4624
.2913
.4644
.2927
.4664
.2940
.4683
.2953
.4703
66
.2966
.4722
.2980
.4742
.2993
.4761
.3006
.4780
.3020
.4799
.3033
.4819
67
.3046
.4838
.3060
.4857
.3073
.4876
.3087
.4895
.3100
.4914
.3113
.4932
68
.3127
.4951
.3140
.4970
.3154
.4989
.3167
.5007
.3181
.5026
.3195
.5044
69
.3208
.5063
.3222
.5081
.3235
.5099
.3249
.5117
.3263
.5136
.3276
.5154
70
.3290
.5172
.3304
.5190
.3317
.5208
.3331
.5226
.3345
.5244
.3358
.5261
71
.3372
.5279
.3386
.5297
.3400
.5314
.3413
.5332
.3427
.5349
.3441
.5367
72
.3455
.5384
.3469
.5402
.3483
.5419
.3496
.5436
.3510
.5454
.3524
.5471
73
.3538
.5488
.3552
.5505
.3566
.5522
.3580
.5539
.3594
.5556
.3608
.5572
74
.3622
.5589
.3636
.5606
.3650
.5623
.3664
.5639
.3678
.5656
.3692
.5672
75
.3706
.5689
.3720
.5705
.3734
.5722
.3748
.5738
.3762
.5754
.3776
.5771
76
.3790
.5787
.3805
.5803
.3819
.5819
.3833
.5835
.3847
.5851
.3861
.5867
77
.3875
.5883
.3889
.5899
.3904
.5915
.3918
.5930
.3932
.5946
.3946
.5962
78
.3960
.5977
.3975
.5993
.3989
.6009
.4003
.6024
.4017
.6039
.4032
.6055
79
.4046
.6070
.4060
.6085
.4075
.6101
.4089
.6116
.4103
.6131
.4117
.6146
80
.4132
.6161
.4146
.6176
.4160
.6191
.4175
.6206
.4189
.6221
.4203
.6236
81
.4218
.6251
.4232
.6266
.4247
.6280
.4261
.6295
.4275
.6310
.4290
.6324
82
.4304
.6339
.4319
.6353
.4333
.6368
.4347
.6382
.4362
.6397
.4376
.6411
83
.4391
.6425
.4405
.6440
.4420
.6454
.4434
.6468
.4448
.6482
.4463
.6496
84
.4477
.6510
.4492
.6524
.4506
.6538
.4521
.6552
.4535
.6566
.4550
.6580
85
.4564
.6594
.4579
.6607
.4593
.6621
.4608
.6635
.4622
.6649
.4637
.6662
86
.4651
.6676
.4666
.6689
.4680
.6703
.4695
.6716
.4709
.6730
.4724
.6743
87
.4738
.6756
.4753
.6770
.4767
.6783
.4782
.6796
.4796
.6809
.4811
.6822
88
.4826
.6835
.4840
.6848
.4855
.6862
.4869
.6875
.4884
.6887
.4898
.6900
89
.4913
.6913
.4937
.6926
.4942
.6939
.4956
.6952
.4971
.6964
.4985
.6977
90
.5000
.6990
.5015
.7002
.5029
.7015
.5044
.7027
.5058
.7040
.5073
.7052
91
.5087
.7065
.5102
.7077
.5116
.7090
.5131
.7102
.5145
.7114
.5160
.7126
92
.5174
.7139
.5189
.7151
.5204
.7163
.5218
.7175
.5233
.7187
.5247
.7199
93
.5262
.7211
.5276
.7223
.5291
.7235
.5305
.7247
.5320
.7259
.5334
.7271
94
.5349
.7283
.5363
.7294
.5378
.7306
.5392
.7318
.5407
.7329
.5421
.7341
95
.5436
.7353
.5450
.7364
.5465
.7376
.5479
.7387
.5494
.7399
.5508
.7410
96
.5523
.7421
.5537
.7433
.5552
.7444
.5566
.7455
.5580
.7467
.5595
.7478
97
.5609
.7489-
.5624
.7500
.5638
.7511
.5653
.7523
.5667
.7534
.5682
.7545
98
.5696
.7556
.5710
.7567
.5725
.7577
.5739
.7588
.5753
.7599
.5768
.7610
99
.5782
.7621
.5797
.7632
.5811
.7642
.5825
.7653
.5840
.7664
.5854
.7674
100
.5868
.7685
.5883
.7696
.5897
.7706
.5911
.7717
.5925
.7727
.5940
.7738
101
.5954
.7748
.5968
.7759
.5983
.7769
.5997
.7779
.6011
.7790
.6025
.7800
102
.6040
.7810
.6054
.7820
.6068
.7830
.6082
.7841
.6096
.7851
.6111
.7861
103
.6125
.7871
.6139
.7881
.6153
.7891
.6167
.7901
.6181
.7911
.6195
.7921
104
.6210
.7931
.6224
.7940
.6238
.7950
.6252
.7960
.6266
.7970
.6280
.7980
105
.6294
.7989
.6308
.7999
.6322
.8009
.6336
.8018
.6350
.8028
.6364
.8037
106
.6378
.8047
.6392
.8056
.6406
.8066
.6420
.8075
.6434
.8085
.6448
.8094
107
.6462
.8104
.6476
.8113
.6490
.8122
.6504
.8131
.6517
.8141
.6531
.8150
108
.6545
.8159
.6559
.8168
.6573
.8177
.6587
.8187
.6600
.8196
.6614
.8205
109
.6628
.8214
.6642
.8223
.6655
.8232
.6669
.8241
.6683
.8250
.6696
.8258
110
.6710
.8267
.6724
.8276
.6737
.8285
.6751
.8294
.6765
.8302
.6778
.8311
111
.6792
.8320
.6805
.8329
.6819
.8337
.6833
.8346
.6846
.8354
.6860
.8363
112
.6873
.8371
.6887
.8380
.6900
.8388
.6913
.8397
.6927
.8405
.6940
.8414
113
.6954
.8422
.6967
.8430
.6980
.8439
.6994
.8447
.7007
.8455
.7020
.8464
114
.7034
.8472
.7047
.8480
.7060
.8488
.7073
.8496
.7087
.8504
.7100
.8513
115
.7113
.8521
.7126
.8529
.7139
.8537
.7153
.8545
.7166
.8553
.7179
.8561
116
.7192
.8568
.7205
.8576
.7218
.8584
.7231
.8592
.7244
.8600
.7257
.8608
117
.7270
.8615
.7283
.8623
.7296
.8631
.7309
.8638
.7322
.8646
.7335
.8654
178
.7347
.8661
.7360
.8669
.7373
.8676
.7386
.8684
.7399
.8691
.7411
.8699
119
.7424
.8706
.7437
.8714
.7449
.8721
.7462
.8729
.7475
.8736
.7487
.8743
Values jiud Logarithms of Haversines
[Characteristics of Logarithms omitted — determine by rule from the value]
119
^
C
10'
20'
30'
40'
50' 1
Value
I-ogio
Value
I>og,o
Value
Logio
Value
Logio
Value
T^ogio
Value
Login
120
.7500
.8751
.7513
.8758
.7525
.8765
.7538
.8772
.7550
.8780 .7563
.8787
121
.7575
.8794^
.7588
.8801
.7600
.8808
.7612
.8815
.7625
.8822
> .7637
.8829
122
.7650
.8836
.7662
.8843
.7674
.8850
.7686
.8857
.7699
.886^
.7711
.8871
123
.7723
.8878
.7735
.8885
.7748
.8892
.7760
.8898
.7772
.8905
.7784
.8912
124
.7796
.8919
.7808
.8925
.7820
.8932
.7832
.8939
.7844
.8945
.7856
.8952
125
.7868
.8959
.7880
.8965
.7892
.8972
.7904
.8978
.7915
.8985
.7927
.8991
126
.7939
.8998
.7951
.9004
.7962
.9010
.7974
.9017
.7986
.9023
.7997
.9030
127
.8009
.9036
.8021
.9042
.8032
.9048
.8044
.9055
.8055
.9061
.8067
.9067
128
.8078
.9073
.8090
.9079
.8101
.9085
.8113
.9092
.8124
.9098
.8135
.9104
129
.8147
.9110
.8158
.9116
.8169
.9122
.8180
.9128
.8192
.9134
.8203
.9140
130
.8214
.9146
.8225
.9151
.8236
.9157
.8247
.9163
.8258
.9169
.8269
.9175
131
.8280
.9180
.8291
.9186
.8302
.9192
.8313
.9198
.8324
.9203
.8335
.9209
132
.8346
.9215
.8356
.9220
.8367
.9226
.8378
.9231
.8389
.9237
.8399
.9242
133
.8410
.9248
.8421
.9253
.8431
.9259
.8442
.9264
.8452
.9270
.8463
.9275
134
.8473
.9281
.8484
.9286
.8494
.9291
.8501
.9297
.8515
.9302
.8525
.9307
135
.8536
.9312
.8546
.9318
.8556
.9323
.8566
.9328
.8576
.9333
.8587
.9338
136
.8597
.9343
.8607
.9348
.8617
.9353
.8627
.9359
.8637
.9364
.8647
.9369
137
.8657
.9374
.8667
.9379
.8677
.9383
.8686
.9388
.8696
.9393
~ .8706
.9398
138
.8716
.9403
.8725
.9408
.8735
.9413
.8745
.9417
.8754
.9422
.8764
.9427
139
.8774
.9432
.8783
.9436
.8793
.9441
.8802
.9446
.8811
.9450
.8821
.9455
140
.8830
.9460
.8840
.9464
.8849
.9469
.8858
.9473
.8867
.9478
.8877
.9482
141
.8886
.9487
.8895
.9491
.8904
.9496
.8913
.9500
.8922
.9505
.8931
.9509
142
.8940
.9513
.8949
.9518
.8958
.9522
.8967
.9526
.8976
.9531
.8984
.9535
143
.8993
.9539
.9002
.9543
.9011
.9548
.9019
.9552
.9028
.9556
.9037
.9560
144
.9045
.9564
.9054
.9568
.9062
.9572
.9071
.9576
.9079
.9580
.9087
.9584
145
.9096
.9588
.9104
.9592
.9112
.9596
.9121
.9600
.9129
.9604
.9137
.9608
146
.9145
.9612
.9153
.9616
.9161
.9620
.9169
.9623
.9177
.9627
.9185
.9631
147
.9193
.9635
.9201
.9638
.9209
.9642
.9217
.9646
.9225
.9650
.9233
.9653
148
.9240
.9657
.9248
.9660
.9256
.9664
.9263
.9668
.9271
.9671
.9278
.9675
149
.9286
.9678
.9293
.9682
.9301
.9685
.9308
.9689
.9316
.9692
.9323
.9695
150
.9330
.9699
.9337
.9702
.9345
.9706
.9352
.9709
.9359
.9712
.9366
.9716
151
.9373
.9719
.9380
.9722
.9387
.9725
.9394
.9729
.9401
.9732
.9408
.9735
152
.9415
.9738
.9422
.9741
.9428
.9744
.9435
.9747
.9442
.9751
.9448
.9754
153
.9455
.9757
.9462
.9760
.9468
.9763
.9475
.9766
.9481
.9769
.9488
.9772
154
.9494
.9774
.9500
.9777
.9507
.9780
.9513
.9783
.9519
.9786
.9525
.9789
155
.9532
.9792
.9538
.9794
.9544
.9797
.9550
.9800
.9556
.9803
.9562
.9805
156
.9568
.9808
.9574
.9811
.9579
.9813
.9585
.9816
.9591
.9819
.9597
.9821
157
.9603
.9824
.9608
.9826
.9614
.9829
.9619
.9831
.9625
.9834
.9630
.9836
158
.9636
.9839
.9641
.9841
.9647
.9844
.9652
.9846
.9657
.9849
.9663
9851
159
.9668
.9853
.9673
.9856
.9378
.9858
.9683
.9860
.9688
.9863
.9693
.9865
160
.9698
.9867
.9703
.9869
.9708
.9871
.9713
.9874
.9718
.9876
.9723
9878
161
.9728
.9880
.9732
.9882
.9737
.9884
.9742
.9886
.9746
.9888
.9751
9890
162
.9755
.9892
.9760
.9894
.9764
.9896
.9769
.9898
.9773
.9900
.9777
9902
163
.9782
.9904
.9786
.9906
.9790
.9908
.9794
.9910
.9798
.9911
.9802
9913
164
.9806
.9915
.9810
.9917
.9814
.9919
.9818
.9920
.9822
.9922
.9826
9923
165
.9830
.9925
.9833
.9927
.9837
.9929
.9841
.9930
.9844
.9932
.9848
9933
166
.9851
.9935
.9855
.9937
.9858
.9938
.9862
.9940
.9865
.9941
.9869
9943
167
.9872
.9944
.9875
.9945
.9878
.9947
.9881
.9948
.9885
.9950
.9888
9951
168
.9891
.9952
.9894
.9954
.9897
.9955
.9900
.9956
.9903
.9957
.9905
9959
169
.9908
.9960
.9911
.9961
.9914
.9962
.9916
.9963
.9919
.9965
.9921
9966
170
.9924
.9967
.9927
.9968
.9929
.9969
.9931
.9970
.9934
.9971
.9936
9972
171
.9938
.9973
.9941
.9974
.9943
.9975
.9945
.9976
.9947
.9977
.9949
9978
172
.9951
.9979
.9953
.9980
.9955
.9981
.9957
.9981
.9959
.9982
.9961
9983
173
.9963
.9984
.9964
.9984
.9966
.9985
.9968
.9986
.9969
.9987
.9971
9987
174
.9973
.9988
.9974
.9988
.9976
.9989
.9977
.9990
.9978
.9991
.9980
9991
175
.9981
.9992
.9982
.9992
.9983
.9993
.9985
.9993
.9986
.9994
.9987
9994
176
.9988
.9995
.9989
.9995
.9990
.9996
.9991
.9996
.9992
.9996
.9992
9997
177
.9993
.9997
.9994
.9997
.9995
.9998
.9995
.9998
.9996
.9998
.9996
9998
178
.9997
.9999
.9997
.9999
.9998
.9999
.9998
.9999
.9999
.9999
.9999
9999
179
.9999
.9999
.9999
.9999
.9999
.9999
.9999
.9999
.9999 0.0000
1.0000
0000
INDEX
Abscissa, 6.
Absolute value, of a directed quan-
tity, 7.
Addition, of angles, 9 ; formulas in
trigonometo', 95.
Angle, definition of, 7 ; directed, 7 ;
measurement of, 8 ; addition and
subtraction of, 9 ; functions of, 2 ;
of elevation and depression, 16 ;
of triangle, 48 ; in artillerj' sen-ice,
76.
Annuities, 70.
Arc of a circle, 76.
Artillery service, use of angles in, 76.
Axes, of coordinates, 5.
Briggian logarithms, 54.
Characteristic of a logarithm, 54.
Cologarithms, 59.
Common logarithms, 54.
Compass, Mariner's, 29.
Computation, numerical, 18, 24 ;
logarithmic, 61 ff.
Coordinates in a plane, 5.
Cosecant, 32.
Cosine, definition of, 12 ; variation
of, 81 ; graph of, 82 ; law of — s,
40.
Cotangent, definition of, 32.
Course, 29.
Coversed sine, 32.
Dead reckoning, 30.
Departure, 29.
Difference in latitude, 29 ; in longi-
tude, 30.
Directed, angles, 7 ; quantities, 6 ;
segments, 7.
Distance, 29.
Elements of a triangle, 1.
Function, definition of, 3 ; representa-
tion of, 32 ; trigonometric, 12 ff.,
58.
Graph of trigonometric functions,
80, 82, 83.
Haversine, definition of, 32 ; solu-
tion of triangles by, 48 ; tables of,
117-9.
Identities, trigonometric, 35.
Initial position, 7.
Interest, 70.
Interpolation, 22.
Knot, 29.
Latitude, difference in, 29 ; middle,
30.
Law, of sines, 40 ; cosines, 40 ; of
tangents, 47.
Logarithm, definition of, 52 ; inven-
tion of, 50 ; laws of, 53 ; systems
of, 54 ; characteristic and man-
tissa of, 54 ; use of tables of, 56 ;
tables of, 110-16.
Logarithmic scale, 73.
Magnitude, 6.
Mantissa. 54.
Mariner's compass, 29.
Middle latitude, 30.
Mil, 76.
Napier, J., 50.
Nautical mile, 29.
Navigation, 28 fF.
Negative angle, definition of, 7 ;
functions of, 85.
Ordinate, 6.
121
122
INDEX
Parts of a triangle, 1.
Period of trigonometric functions,
80, 82, 84.
Plane sailing, 28.
Plane trigonometry, 1.
Product formulas, 101.
Projectile, 72.
Projection, 92.
Quadrant, 6.
Radian, 75.
Radius of inscribed circle.
Rotation, angles of, 8.
Rounded numbers, 25.
46.
Scale, logarithmic, 73.
Secant, definition of, 32.
Significant figures, 25.
Sine, definition of, 12 ; variation of,
79 ; graph of, 80 ; law of s, 40.
Slide rule, 74.
Solution of triangles, 1, 16 ff., 41 ff.,
48, 62 ff .
Spherical trigonometry, 1.
Tables, of squares, 27, 106-7; of
haversines, 117-9; of logarithms,
110-11 ; of trigonometric func-
tions, 112-19.
Tangent, definition of, 3, 12 ; variation
of, 82 ; graph of, 83 ; line repre-
sentation of, 83 ; law of s, 47.
Triangle, area of, 45 ; angles of, 48 ;
solution of, 1, 16 ff., 41 ff., 48, 62.
Trigonometric equations, 88.
Trigonometric functions, definitions
of, 3, 12, 15, 32 ; graphs of, 80, 82,
83 ; computation of, 18 ff. ; periods
of, 80, 82, 84; inverse, 87; formulas,
15, 32, 34, 96 ff. ; logarithms of,
61; tables of, 21, 112-19.
Versed sine, defined, 32.
Printed in the United States of America.
THE following pages contain advertisements of a
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ELEMENTARY MATHEMATICAL
ANALYSIS
BY
JOHN WESLEY YOUNG
Professor of Mathematics in Dartmouth College
And frank MILLET MORGAN
Assistant Professor of Mathematics in Dartmouth College
Edited by Earle Raymond Hedrick, Professor of Mathematics
in the University of Missouri
///., Cloth, i2mo, $2.60
A textbook for the freshman year in colleges, universities, and
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theme of functionality so that each subject, without losing its
fundamental character, is shown clearly in its relationship to the
others, and to mathematics as a whole.
More emphasis is placed on insight and understanding of
fundamental conceptions and modes of thought ; less emphasis
on algebraic technique and facility of manipulation. Due recog-
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The text presupposes only the usual entrance requirements in
elementary algebra and plane geometry.
THE MACMILLAN COMPANY
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Trigonometry
By ALFRED MONROE KENYON
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and ^
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Edited by Earle Raymond Hedrick
With Brief Tables, 8vo, $1.20
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The book contains a minimum of purely theoretical matter. Its entire organization is
intended to give a clear view of the meaning and the immediate usefulness of Trigonometry.
The proofs, however, are in a form that will not require essential revision in the courses that
follow. ...
The number of exercises is very large, and the traditional monotony is broken by illus-
trations from a variety of topics. Here, as well as in the text, the attempt is often made to
lead the student to think for himself by giving suggestions rather than completed solutions
or demonstrations.
The text proper is short; what is there gained in space is used to make the tables very
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Law become practicable for actual computation. The use of the slide rule and of four-place
tables is encouraged for problems that do not demand extreme accuracy.
Analytic Geometry and Principles of Algebra
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Cloth, i2mo, $1.75
This work combines with analytic geometry a number of topics traditionally treated in
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The treatment of solid analytic geometry follows the more usual lines. But, in view of the
application to mechanics, the idea of the vector is given some prominence; and the represen-
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plained and illustrated by practical examples.
The exercises have been selected with great care in order not only to furnish sufficient
material for practice in algebraic work but also to stimulate independent thinking and to
point out the applications of the theory to concrete problems. The number of exercises is
sufl&cient to allow the instructor to make a choice.
THE MACMILLAN COMPANY
Publishers 64-66 Fifth Avenue New Tork
A Short Course in Mathematics
By R. E. MORITZ
Professor of Mathematics, University of Washington
Cloth J 1 2 mo
A text containing the material essential for a short course in Freshman Mathematics which
is complete in itself, and which contains no more material than the average Freshman can
assimilate. The book will constitute an adequate preparation, for further study, and will
enable the student to take up the usual course in analytical geometry without any handicap.
Among the subjects treated are : Factoring, Radicals, Fractional and Negative Exponents,
Imaginary Quantities, Linear and Quadratic Equations ; Coordinates, Simple and Straight
Line Graphs, Curve Plotting, Maxima and Minima, Areas; The General Angle and Its
Measures, The Trigonometric or Circular Functions, Functions of an Acute Angle; Solution
of Right and Oblique Triangles; Exponents and Logarithms; Application of Logarithms to
Numerical Exercises, to Mensuration of Plane Figures, and to Mensuration of Solids; The
Four Cases of Oblique Triangles, Miscellaneous Problems Involving Triangles.
Plane and Spherical Trigonometry
By LEONARD M. PASSANO
Associate Professor of Mathematics in the Massachusetts Institute of
Technology
Cloth, 8vo, $1.2 j
The chief aims of this text are brevity, clarity, and simplicity. The author presents the
whole field of Trigonometry in such a way as to make it interesting to students approaching
some maturity, and so as to connect the subject with the mathematics the student has pre-
viously studied and with that which may follow.
CONTENTS
CHAPTER
PL.\NE TRIGONOMETRY chapter
6. The Solution of General Triangles
. . 7. The Solution of Trigonometric Equa-
The Trigonometric Functions of Any tions
Angle and Identical Relations among
Them
2. Identical Relations Among the Func- SPHERICAL TRIGONOMETRY
tions of Related Angles. The Values
of the Functions of Certain Angles 8. Fundamental Relations
3. The Solution of Right Triangles. g. The Solution of Right Spherical Tri
Logarithms and Computation by angles
Means of Logarithms lo. The Solution of Oblique Spherical
4. Fundamental Identities Triangles
5. The Circular or Radian Measure of an n. The Earth as a Sphere ...
Angle. Inverse Trigonometric Func- Answers
tions
THE MACMILLAN COMPANY
Publishers 64-66 Fifth Avenue Now York
Differential and Integral Calculus
By CLYDE E. LOVE, Ph.D.
Assistant Professor of Mathematics in the University of Michigan
Crown 8vo,$2.io
Presents a first course in the calculus — substantially as the author has
taught it at the University of Michigan for a number of years. The follow-
ing points may be mentioned as more or less prominent features of the book :
In the treatment of each topic the author has presented his material in
such a way that he focuses the student's attention upon the fundamental
principle involved, insuring his clear understanding of that, and preventing
him from being confused by the discussion of a multitude of details. His
constant aim has been to prevent the work from degenerating into mere
mechanical routine; thus, w^herever possible, except in the purely formal
parts of the course, he has avoided the summarizing of the theory into
rules or formulae which can be applied blindly.
The Calculus
By ELLERY WILLIAMS DAVIS
Professor of Mathematics, the University of Nebraska
Assisted by William Charles Brenke, Associate Professor of Mathe-
matics, the University of Nebraska
Edited by Earle Raymond Hedrick
Cloth, semi-flexible, with Tables, i2mo, $2.10
Edition De Luxe, flexible leather binding, $2.50
This book presents as many and as varied applications of the Calculus
as it is possible to do without venturing into technical fields whose subject
matter is itself unknown and incomprehensible to the student, and without
abandoning an orderly presentation of fundamental principles.
The same general tendency has led to the treatment of topics with a view
toward bringing out their essential usefulness. Rigorous forms of demon-
stration are not insisted upon, especially where the precisely rigorous proofs
would be beyond the present grasp of the student. Rather the stress is laid
upon the student's certain comprehension of that which is done, and his con-
viction that the results obtained are both reasonable and useful. At the
same time, an effort has been made to avoid those grosser errors and actual
misstatements of fact which have often offended the teacher in texts other-
wise attractive and teachable.
THE MACMILLAN COMPANY
Publishers 64-66 Fifth Avenue New Tork
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